Home | Contact Us | FAQ | Search & Site Map | Link to Us
Sign In | Join | Other 45 Sites in Network
Home
Discussion Groups
Biology
BiologyBotanyMicrobiologyEntomologyEvolutionPaleontology
Chemistry
General ChemistryAnalytical ChemistryElectrochemistryOrganic Synthesis
Earth Science
GeologyMineralogyOceanographyMeteorologyEarthquakes
Physics
General PhysicsResearchRelativityParticle PhysicsElectromagnetismFusionOpticsAcousticsNew Theories

Natural Science Forum / Physics / Acoustics / February 2004



Tip: Looking for answers? Try searching our database.

Acoustic transverse Doppler shift?

Thread view: 
Enable EMail Alerts  Start New Thread
Thread rating: 
Eric Baird - 13 Feb 2004 02:15 GMT
Hello!
  I've been looking in modern physics textbooks for a reference to
the acoustic transverse Doppler effect.

In other words, the Doppler shift that you'd expect to hear if the
source was stationary wrt the air, and you were moving past at v m/s,
and pointed your rifle mic out at 90 degrees to your direction of
motion ... when you hear a quick burst of signal entering your
directional mic, what sort of frequency shift should it have?

Anyone know of a good reference source that gives the "official"
equation for this shift?


PS: I know what =I= think it ought to be, but I can't find the damned
thing in print.  
PPS: If modern physics people don't know about the effect, can I lay a
claim to it? <grin>

=Erk= (Eric Baird)
EjP - 13 Feb 2004 04:14 GMT
> Hello!
>    I've been looking in modern physics textbooks for a reference to
[quoted text clipped - 9 lines]
> equation for this shift?
>  

Acoustic Doppler shifts depend only on the compenent of motion
toward or away from the listener, so there is no transverse
Doppler shift.

> PS: I know what =I= think it ought to be, but I can't find the damned
> thing in print.  
> PPS: If modern physics people don't know about the effect, can I lay a
> claim to it? <grin>

Since it doesn't exist, you are welcome to it.

-E

> =Erk= (Eric Baird)
EjP - 13 Feb 2004 04:19 GMT
>> Hello!
>>    I've been looking in modern physics textbooks for a reference to
[quoted text clipped - 11 lines]
> toward or away from the listener, so there is no transverse
> Doppler shift.

...unless of course the source were moving fast enough to
consider relativistic effects of course, in which case
it would be exactly the same as the EM transverse Doppler
shift.

>> PS: I know what =I= think it ought to be, but I can't find the damned
>> thing in print.   PPS: If modern physics people don't know about the
[quoted text clipped - 6 lines]
>
>> =Erk= (Eric Baird)
Angelo Campanella - 13 Feb 2004 08:40 GMT
> In other words, the Doppler shift that you'd expect to hear if the
> source was stationary wrt the air, and you were moving past at v m/s,
> and pointed your rifle mic out at 90 degrees to your direction of
> motion ... when you hear a quick burst of signal entering your
> directional mic, what sort of frequency shift should it have?

The rifle mic character implies a very directional microphone, so that
hypothetically, source sound is only received when adjacent to the sound
source. FYI, the beamwidth of such mics is not so narrow.

The sound entering the microphone when adjacent to the source will be
the same frequency as emitted since at that position, for an instant,
the distance to the source is not changing.

However the rate of change of frequency with time will be a maximum, as
it is swinging from a higher frequency as you were approaching, to a
lower frequency as you soon will be moving further away.

> Anyone know of a good reference source that gives the "official"
> equation for this shift?

See the FAQ file in my web page. This gives accurate values when you are
approaching, and when you are receding from, a sound source. For the
braodside pass by, the frequency swings from a high frequency to a low
frequency. The frequency behavior with time can be calculated according
to plane geometry (a simple calculation when your path is a straight
line). The velocity used in every case is the rate of change of distance
to the source.

             ---------   www.CampanellaAcoustics.com  ---------

"I have simply studied carefully whatever I've undertaken, and tried to
hold a reserve that would carry me through." - Charles A. Lindbergh.

"As for background noise level; 35 dBA is a good classroom; 45 dBA is a
sound masking system!" - Anthony K. Hoover
Don Pearce - 13 Feb 2004 09:21 GMT
>Hello!
>   I've been looking in modern physics textbooks for a reference to
[quoted text clipped - 15 lines]
>
>=Erk= (Eric Baird)

Assume a set of axes, the vertical of which is represented by the
direction from the source to the microphone and draw on them a vector
representing the speed and direction of travel of the source. The
length of the Y (cosine) portion of this vector represents the net
speed of the source towards (or away from) the microphone at that
instant. Add (or subtract when moving away) this to the speed of sound
to get the ratio of perceived to actual frequency.

Once you have this clear in your head, just derive the actual equation
relating angle, velocity and frequency.

d

_____________________________

http://www.pearce.uk.com
Eric Baird - 13 Feb 2004 20:21 GMT
>Once you have this clear in your head, just derive the actual equation
>relating angle, velocity and frequency.

As I said I've already derived it ... I'd just like to be able to find
an example of the effect in print in a modern reference book.
Uncle Al - 13 Feb 2004 17:41 GMT
> Hello!
>    I've been looking in modern physics textbooks for a reference to
[quoted text clipped - 8 lines]
> Anyone know of a good reference source that gives the "official"
> equation for this shift?

You want to be *very* careful about whether this is a relativistic
example (light) or a Galilean one (sound).  It makes a difference.

For velocities at an arbitrary angle theta with ful reativisitic
correciton, Jackson gives

u_parallel = (u'_parallel + v)/(1+(v dot u')/c^2)
u_perp = u'_perp/(gamma_v(1+(v dot u')/c^2))

<http://www.physics.umanitoba.ca/~souther/waves02/feb0402/sld011.htm>

Google
"transverse doppler effect"  423 hits
"transverse doppler shift"  212 hits

Signature

Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
"Quis custodiet ipsos custodes?"  The Net!

The Alaskan - 13 Feb 2004 18:37 GMT
A reference to Jackson brings back memories (painful ones) of graduate
E&M. Thank for the memory (i think)...RonMan

> You want to be *very* careful about whether this is a relativistic
> example (light) or a Galilean one (sound).  It makes a difference.
[quoted text clipped - 10 lines]
> "transverse doppler effect"  423 hits
> "transverse doppler shift"  212 hits
Eric Baird - 13 Feb 2004 20:22 GMT
>> Hello!
>>    I've been looking in modern physics textbooks for a reference to
[quoted text clipped - 11 lines]
>You want to be *very* careful about whether this is a relativistic
>example (light) or a Galilean one (sound).  It makes a difference.

Indeed.
This is for an acoustic calculation, for sound in air, when the
transmission medium is stationary wrt the source, but when the
detector is moving relative to source and medium at v m/s.

As I stated above.

>For velocities at an arbitrary angle theta with ful reativisitic
>correciton, Jackson gives

<SNIP!!!>

That's an answer to a different question.
I was asking about a simple acoustic effect, sound in air, no use of
special relativity involved.

>Google
>"transverse doppler effect"  423 hits
>"transverse doppler shift"  212 hits

Yes, but do any of those hits give the ACOUSTIC transverse Doppler
prediction?

Please read more carefully.

=Erk= (Eric Baird)
Uncle Al - 13 Feb 2004 23:40 GMT
> >> Hello!
> >>    I've been looking in modern physics textbooks for a reference to
[quoted text clipped - 34 lines]
> Yes, but do any of those hits give the ACOUSTIC transverse Doppler
> prediction?

Ditto.  There is no acoustic transverse Doppler effect with Galilean
transforms.

Signature

Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
"Quis custodiet ipsos custodes?"  The Net!

Eric Baird - 16 Feb 2004 00:13 GMT
<snip>

>> Yes, but do any of those hits give the ACOUSTIC transverse Doppler
>> prediction?
>
>Ditto.  There is no acoustic transverse Doppler effect with Galilean
>transforms.

If it makes things any clearer, I've posted an attempt at a trig
derivation of the effect in this thread, in a reply to Franz:

http://groups.google.com/groups?selm=goks20l20tc7egaiekrf0q7ges8qep4720%404ax.com

If we were talking at cross-purposes, that should hopefully clear
things up.

I /think/ I managed to do it without any dumb mistakes ... but if you
do manage to find an accidental sign inversion or something in there,
there must be a second mistake further down that cancels it out,
because it's the right answer!  ;)

=Erk= (Eric Baird)
Angelo Campanella - 16 Feb 2004 07:04 GMT
> If it makes things any clearer, I've posted an attempt at a trig
> derivation of the effect in this thread, in a reply to Franz:
[quoted text clipped - 3 lines]
> If we were talking at cross-purposes, that should hopefully clear
> things up.

That's a nice derivation of the collimated detector where rays coming
from a certain direction will pass down the collimating tube unimpeded
(particle physics).

However, if instead a use a line of microphones (to produce the
"directional microphone" receiver), along a line parallel to the
direction of motion, so that the sound-wave-front is incident on the
line of microphones, I think that the only place where such an
all-in-phase situation exists is when the array and sound source are
both on the line perpendiular to the velocity, V.

Angelo Campanella
Eric Baird - 25 Feb 2004 00:01 GMT
>> If it makes things any clearer, I've posted an attempt at a trig
>> derivation of the effect in this thread, in a reply to Franz:
[quoted text clipped - 14 lines]
>all-in-phase situation exists is when the array and sound source are
>both on the line perpendiular to the velocity, V.

Hmm. Nice one! Clever! :)

But even if you have all these detectors that are /calculated/ to be
in phase, you still have to find some way to get all that
spatially-distributed information to a particular point, and if we
aren't allowed to use electrical wiring (because then we would have an
experiment that depends on a hybrid of EM and acoustic signals), we'd
need some way to acoustically collect all that information at a single
position so that we could verify the phase relationship.
That's more difficult.

We could try replacing the line with a section of curved reflector
that focuses the wavefront on a single microphone (eg one of those
parabolic microphones that used to be marketed as kids' toys) ... but
again, the focus that we obtain when the reflector and mic are
stationary will be messed up when they  are moving transversely
(presumably, unless you tilt the detector apparatus).

====

I know that some people might argue that the correct way to measure a
"transverse" shift is to angle the detector differently depending on
speed, but that's not how they actually measure the optical
"transverse Doppler effect" in constant-velocity tests. They either
aim the detector at 90 degrees in the lab frame and see what the
detector reports, or they measure the forward and rearward shifts and
derive a sort of "transverse" effect from those two measurements.

What they basically do is to say that, if we take the recession shift
reported by the experiment and divide out the ratio
:   f'/f = c/(c+v)
, then what remains is interpretable as being a residual "transverse"
Doppler shift component. Most direct constant-velocity verifications
of the optical transverse effect seem to be done this way.

If we apply this same technique to acoustics (and use "s" for the
speed of sound in place of "c" for the speed of light), then if the
air is stationary wrt the observer, the standard predicted Doppler
shift will be:
:   f'/f = s/(s+v)
, and after division, we are left indeed left with a "null" derived
transverse effect.

But if we carry out the "acoustic" version of the experiment and have
the air instead being stationary in the /source/ frame, the standard
predicted Doppler shift will instead be:  
:   f'/f = (s-v)/s

, and if we divide out the earlier relationship, we are left with a
residual frequency-shift effect of:
:   f'/f = 1 - v^2/s^2
, which is the same "transverse" prediction that we got before for the
moving transverse-aimed rifle mic, when the air was stationary wrt the
source. So the "acoustic" result does seem to be consistent, using
either method.

So ... if we follow the constant-velocity methodology used by the
"optical" folks to prove an "optical" transverse redshift in light,
there's an analogous effect in acoustics, as long as the air is moving
wholly or partially with the sound source.

The acoustic version of the effect might not be considered to be
/theoretically/ interesting, but it does seem to be real.

=Erk= (Eric Baird)

Franz Heymann - 13 Feb 2004 21:02 GMT
> Hello!
>    I've been looking in modern physics textbooks for a reference to
> the acoustic transverse Doppler effect.

What acoustic transverse effect?
The frequency shift depende only on the component of relative velocity along
a line between the detector and the source.

Franz
Eric Baird - 14 Feb 2004 21:31 GMT
>> Hello!
>>    I've been looking in modern physics textbooks for a reference to
>> the acoustic transverse Doppler effect.
>
>What acoustic transverse effect?

It's an aberration effect.

If a stationary sound source is immersed in still air, and a detector
is swept through the region, and the detector is aimed at exactly 90
degrees to its direction of motion, then the portion of the signal
that is picked up by that transverse-aimed detector will not be the
same portion of signal that was originally projected at 90 degrees to
the detector's path by the sound source.

So although we can draw a straight line that represents the detector's
path, and can argue that the part of the wavefront that hits that path
at 90 degrees should be unshifted, the aberration effect means that
the /moving/ transverse-aimed detector is actually receiving signals
that (according to our stationary reference system) would be
intersecting that path at a different angle.

>The frequency shift depende only on the component of relative velocity along
>a line between the detector and the source.

Yep, nicely put.

So what we need to do is (a) calculate the aberration angle, (b)
calculate the longitudinal component for the angled ray that actually
registers on the moving transverse-aimed detector, and then (c) apply
the appropriate longitudinal Doppler law to that longitudinal
component to get the final freqency shift reported by the equipment.

So, in the diagram below, we have a stationary sound source "X" in
still air, and a detector "Y" moving from right to left at the bottom
of the diagram.  
The column of "H"'s is a transverse-aimed tube placed over the
detector to make sure that sound can only reach it in a particular
direction.

          X
         /
  H   /  <-
  H  /
  H /
  H/
  Y      <-
 
  <----v----

If the signal from X enters the tip of the tube, then by the time it
reaches the detector at the far end, the tube will have moved further
to the left, so the signal that successfully passes through the tube
to the detector without touching the tube sides is actually moving
along the line marked out by the diagonal "/"  marks.

So, if we say that the speed of sound is "s" m/s, and that the sound
happens to take one second to reach the detector then we have a
right-angled triangle with baseline v metres and hypoteneuse c metres,
and the ray that will be intercepted and detected will be one that is
offset from 90 degrees by an aberration angle "A", where
:  SIN(A) = v/s  

Now, when we stand at X and look along this diagonal line towards the
microphone at Y, the mic is partly moving across our field of view and
partly receding, and the velocity's recession component "w" would then
seem to be :
:  w = v SIN(A) ,

      \    
w /      \
  <----v----|A

, and since we've just said that SIN(A) = v/s, our recession velocity
component is:
:  w = v * v/s
:  w = v^2/s

Finally, since the Doppler formula for a "stationary" source and a
"moving" observer receding at v  is :
:  freq'/freq = 1 -  v/s
, we can say that our recession component w should be responsible for
a shift showing up on our transverse-aimed moving microphone of
:  freq'/freq = 1 - w/s
:  freq'/freq = 1 - v^2/s^2

:==SUMMARY==
So ... if the above calculations aren't screwed up, they seem to say
that if we fix together an array of four microphones each pointing
outwards at 90 degrees to its neighbours and forming the shape of a
cross, and move that mic assembly through the air along a
straight-line path aligned with two of those mics, and our sound
sources are stationary wrt the air, the "forward" and "rearward" mics
should show shifts of
:  freq'/freq = 1 +/-  v/s
, and the two side mics should show a frequency reduction of  
:  freq'/freq = 1 - v^2/s^2

, and that's your acoustic transverse Doppler effect.

=Erk= (Eric Baird)
Franz Heymann - 14 Feb 2004 21:55 GMT
> >> Hello!
> >>    I've been looking in modern physics textbooks for a reference to
[quoted text clipped - 10 lines]
> same portion of signal that was originally projected at 90 degrees to
> the detector's path by the sound source.

That is not a transverse Doppler shift.
The TDS is a purely relativistic effect which occurs with light propagation
only.
Aberration and Doppler shifts are entirely separate phenomena

> So although we can draw a straight line that represents the detector's
> path, and can argue that the part of the wavefront that hits that path
[quoted text clipped - 7 lines]
>
> Yep, nicely put.

In other words, you agree that there is no transverse Doppler effect in the
case of sound.
In the case of light, there actually *is* a Doppler shift which occurs when
the source is moving *at right angles* to the line of sight.  It is a purely
relativistic effect.

[snip]

The stuff I snipped has nothing to do with the transverse Doppler shift.

Franz
Eric Baird - 15 Feb 2004 22:50 GMT
>> >> Hello!
>> >>    I've been looking in modern physics textbooks for a reference to
[quoted text clipped - 12 lines]
>
>That is not a transverse Doppler shift.

It is a Doppler shift that is present in a signal from a detector that
is aimed at 90 degrees to the direction of motion wrt a source.
It may not be the /same/ transverse Doppler shift that you are
familiar with from textbooks, but that's not the same as saying that
the effect does not exist.

>The TDS is a purely relativistic effect which occurs with light propagation
>only.

Those supplied calculations say otherwise.

>Aberration and Doppler shifts are entirely separate phenomena

They are quite intimately related, actually

>> So although we can draw a straight line that represents the detector's
>> path, and can argue that the part of the wavefront that hits that path
[quoted text clipped - 11 lines]
>In other words, you agree that there is no transverse Doppler effect in the
>case of sound.

No.

I would agree that the simple calculation for Doppler effects on a
detector moving past a source (with the detector pointing at 90
degrees to the direction of motion), should give us a "no shift"
prediction when the sound-carrying medium has no motion wrt our
detector (the "moving source" or "stationary detector" case).

But if the sound-carrying medium is instead stationary wrt the sound
/source/, (i.e. the "moving detector", or  "stationary source" case),
then I calculate that the same detector should pick up a signal whose
frequency is reduced by the factor

:  freq'/freq = 1 - vv/ss

So, in the case of sound, in some situations there is no predicted
Doppler effect on the transverse-aimed detector, and in other cases
there is a predicted frequency-reduction, depending on how the air is
moving wrt the source and detector.

If the air moving in the direction of the detector path, but at an
intermediate velocity, then we should get an similarly-intermediate
frequency drop in the audio signal received.

>In the case of light, there actually *is* a Doppler shift which occurs when
>the source is moving *at right angles* to the line of sight.  It is a purely
>relativistic effect.

and yet ... if you actually do the audio calculations for a
"stationary" source and a "moving" sensor, you will find an analogous
effect for audio, when the sensor is set up to point at right angles
to its direction of motion.

That's the calculation that I provided you with. If you choose not to
look at it, that is entirely up to you.

>[snip]
>
>The stuff I snipped has nothing to do with the transverse Doppler shift.

Ah. the words "_THE_ transverse Doppler shift" (emphasis added),
rather presuppose that there can only be /one/ transverse Doppler
effect, don't they?

But how do you know there /is/ only one, until you've done the
calculation?

I would suggest that if you are at all interested in the subject of
Doppler effects, you may like to forget official "syllabus physics"
for a few minutes, and try the actual math.
You may find it a liberating experience.

Physics is not like "bible studies", the reference works are
occasionally allowed to be misleading (or even wrong sometimes).
Hopefully it doesn't happen very often, but it does happen.

=Erk= (Eric Baird)
Franz Heymann - 16 Feb 2004 11:24 GMT
> >> >> Hello!
> >> >>    I've been looking in modern physics textbooks for a reference to
[quoted text clipped - 27 lines]
>
> They are quite intimately related, actually

Aberration is an effective shift in source direction
Doppler effect is a change in frequency of a moving source.
They are related only insofar as both are phenomena associated with moving
sources.
There is no transverse Doppler shift.  The frequency shift is a function
purely of the source frequency measured in coordinates moving with the
source, and the line-of-sight componenet of the relative velocity between
the source and the observer.

> >> So although we can draw a straight line that represents the detector's
> >> path, and can argue that the part of the wavefront that hits that path
[quoted text clipped - 13 lines]
>
> No.

Sorry, but then you are out on a limb, and I cannot help you any more.

Goodbye

[snip]

Franz
 
Sign In
Join
My Latest Posts
My Monitored Threads
My Blog
My Photo Gallery
My Profile
My Homepage

Start New Thread
Enable EMail Alerts
Rate this Thread



©2009 Advenet LLC   Privacy Policy - Terms of Use
This website includes both content owned or controlled by Advenet as well as content owned or controlled by third parties.