The natural frequency of a cylindrical organ pipe is elementary, dear Dr
Watson: open 2 ends: L = lambda/2, closed 1 end: L = lambda/4. BUT, what is
the change of diameter like in a trumpet do? And how about change of
direction, the simplest that looong Swiss mountain horn which makes a 90 deg
turn close to the exit?
What are the answers, or, if that is too longwinded, where can I read up on
this?
Looking forward to hearing from you!
Klaus Weber
bert stoltenborg - 27 Nov 2005 14:37 GMT
> The natural frequency of a cylindrical organ pipe is elementary, dear Dr
> Watson: open 2 ends: L = lambda/2, closed 1 end: L = lambda/4. BUT, what is
[quoted text clipped - 8 lines]
>
> Klaus Weber
To begin with: to get the naturel freq of a pipe you have to apply an
endcorrection :-)
salmonegg@sbcglobal.net - 28 Nov 2005 01:40 GMT
On 11/27/05 1:19 AM, in article -LednXZsI-zL5xTenZ2dnUVZ_v-dnZ2d@is.co.za,
> The natural frequency of a cylindrical organ pipe is elementary, dear Dr
> Watson: open 2 ends: L = lambda/2, closed 1 end: L = lambda/4. BUT, what is
[quoted text clipped - 8 lines]
>
> Klaus Weber
Without an extensive knowledge of mathematical physics and partial
differential equations in particular, it is very difficult to understand the
fine points of any answers you get to your questions. Some good
approximations can be obtained. Good computer simulations may help with fine
points such as end effects, and varying size of the bore.
What I did find out is that conical bore instruments, such as an oboe, will
provide fundamentals for L = lambda/2 instead of L = lambda/4. Then there
are the subtler effects on top of that.
Bill
-- Ferme le Bush