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Natural Science Forum / Physics / Optics / December 2004



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Light, Heat, Vacuum

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Tom Hubin - 23 Dec 2004 17:08 GMT
Hello,

While a light bulb filament is powered, the glass bulb is very hot. I
would expect very little heat transfer from the filament to the glass
through the small amount of gas within the bulb. Is the glass heating
due to absorption of infrared?

I am wondering about the energy loss of a light bulb filament after the
power is removed.

Visible and IR light are emitted so that is some of the loss. Heat
transfer from filament to glass bulb should be small due to vacuum. Heat
transfer from filament ends to external electrical contacts will occur.
Eventually the filament reaches ambient temperature and equilibrium.

If the unpowered hot filament were surrounded by a perfect vacuum it
would continue to emit light for a while. As energy is lost, the
filament would cool and emit less light. At what point does this process
stop?

Tom Hubin
thubin@earthlink.net
Fleetie - 23 Dec 2004 17:52 GMT
> Hello,
>
[quoted text clipped - 8 lines]
> Visible and IR light are emitted so that is some of the loss. Heat
> transfer from filament to glass bulb should be small due to vacuum.

Yeah and heat transfer from the Sun to the Earth should be small "due
to vacuum". Oh, and light transfer too.

THINK, MAN.

"Conduction, convection and radiation"

> transfer from filament ends to external electrical contacts will occur.
> Eventually the filament reaches ambient temperature and equilibrium.
[quoted text clipped - 3 lines]
> filament would cool and emit less light. At what point does this process
> stop?

Just as hell freezes over.
Repeating Rifle - 23 Dec 2004 20:52 GMT
> While a light bulb filament is powered, the glass bulb is very hot. I
> would expect very little heat transfer from the filament to the glass
> through the small amount of gas within the bulb. Is the glass heating
> due to absorption of infrared?

Most modern incandescant lamps have an inert gas such as nitrogen filling
the envelope. It is not a vacuum as used by early carbon filament lamps.

Bill
redbelly98@yahoo.com - 23 Dec 2004 23:40 GMT
> As energy is lost, the filament would cool and emit less light.
> At what point does this process stop?

The process would stop at a temperature of absolute zero, but
that is never reached.

Before it reaches absolute zero, it will reach an equilibrium
temperature determined by it's surroundings.  At that point, it
both radiates energy, and absorbs energy that is being radiated by
it's surroundings; the two processes balance each other --> no
further temperature change happens.
dbohara@mindspring.com - 25 Dec 2004 07:08 GMT
> > As energy is lost, the filament would cool and emit less light.
> > At what point does this process stop?
[quoted text clipped - 7 lines]
> it's surroundings; the two processes balance each other --> no
> further temperature change happens.

The rate at which the filament emits is given by P/A = sigma*T^4
where:  sigma is a constant and T is the absoluite temp and P/A is the
power density.  This is Stefans Law.  This shows that it emits
considerably more for even a small increase in temp. Most of this is in
the IR spectrum.  The frosted bulb serves to scatter the visible
portion of the light and substantial amounts of light (IR and visible)
are absorbed by the bulb thus heating it.  Very little of the bulb
heating is done by conduction through the glass, most of it is by
radiation.
redbelly98@yahoo.com - 27 Dec 2004 23:04 GMT
dboh...@mindspring.com wrote:

> The rate at which the filament emits is given by P/A = sigma*T^4

Don't forget the emissivity factor on the right hand side.  Which, if
memory serves, is around 0.3 for tungsten at 3000 K (a typical bulb
filament temperature).
(Your conclusions are still right on the money.)

-- Mark
Ian Stirling - 28 Dec 2004 12:46 GMT
> dboh...@mindspring.com wrote:
>
[quoted text clipped - 4 lines]
> filament temperature).
> (Your conclusions are still right on the money.)

Is a tungsten filliment at 3000K still the same colour as it is at 300K?
(obviously usually swamped by self-generated light)
redbelly98@yahoo.com - 28 Dec 2004 15:13 GMT
Nope, they're different.  3000 K is yellow or yellow-orange, while 300
K would be a deep red color (assuming you have a visible sensor with
enough sensitivity to "see" its radiation)

See Fig. 2 at
http://www.ledproductstore.com/colorimetry.htm

If you're unfamilar with this diagram, it's the CIE Chromaticity
Diagram and shows all colors that can be perceived by the human eye.
Colors associated with single-wavelengths appear around the outer edge
of the diagram, and colors associated with blackbodies of varying
temperatures lie along the curve that is shown in the figure (red for
cooler temperatures, blue-white for the hottest temperatures).

While it's not clear from the figure just where the color converges to
at low temperatures, the color is noticeably changing even at 1000 K.
The figure shows 2850 K to be in the yellow-orange portion of the
diagram (and 3000 K would of course be close to this).

It may be that for cooler temperatures the blackbody curve approaches
the "pure red" point on the diagram, but if somebody else could confirm
or refute that I'd be interested.

Regards,

Mark
Ian Stirling - 28 Dec 2004 16:58 GMT
> Nope, they're different.  3000 K is yellow or yellow-orange, while 300
> K would be a deep red color (assuming you have a visible sensor with
> enough sensitivity to "see" its radiation)

Sorry, unclear.
I was meaning the colour as viewed by reflected light, not emitted.
redbelly98@yahoo.com - 28 Dec 2004 19:05 GMT
> I was meaning the colour as viewed by reflected light, not emitted.

Sorry.

It seems that there is a difference in color, but perhaps a very small
one.  My CRC Handbook of Chemistry and Physics (76th ed.) lists
emissivity of tungsten at various temperatures for two wavelengths, 467
nm and 650 nm.

At 300 K, the emissivity is 7% higher at 467 than 650 (.505 vs. .472)
At 3000 K, it's 9% higher at 467 (.455 vs. .418)

This suggests a shift toward the blue at higher temperatures, but you'd
probably need to look at emissivity in the entire visible spectrum to
make definitive statements like that.  Suffice it to say that there is
a difference.

-- Mark

p.s. Of course, viewing reflected light from a 3000 K source would be a
real problem.
John Savard - 25 Dec 2004 20:30 GMT
>At what point does this process
>stop?

Well, when the filament cools to 3.6 degrees Kelvin, it's still emitting
microwaves similar to the cosmic microwave background... so I think
you're in for a long wait.

John Savard
http://home.ecn.ab.ca/~jsavard/index.html
 
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