Cosmic microwave background photons redshift on their way to Earth.
Their energy gets put into massless antimatter particles (the missing
antimatter of the universe has been split into tiny pieces and their
rest mass has been transferred to matter.The pieces do not annihilate
with matter because the probability of all the pieces of one
antiparticle coming back together at one point in space is small).The
antimatter particles are dark energy and move at the speed of
light.When the cmbr had a thousand times more energy, in the early
universe,then the antimatter had a thousand times less energy.
In the antimatter a negative charge orbits a positive charge and the
same for a photon.Energy is transferred from the orbiting charge in
the photon to the orbiting charge in the antimatter.When the
antimatter has absorbed all the energy it can, the energy will be
transferred back to the photons and the universe begins to
contract.Because photons had more energy in the past
when there was less dark energy, gravity must have been stronger too,
so that the rate at which stars burned fuel was unaffected.In
George Luis le Sage's theory of pushing gravity, there would have been
a higher concentration of gravitational force carriers in the early
universe
(same number in a smaller volume)and these would have produced the
stronger gravitational force.This stronger gravitational force may be
able to explain
why galaxies formed quicker than expected.
alistair - 04 Nov 2004 18:50 GMT
In the following I assume that a photon is made of a spherical
positive charge and a spherical negative charge (each 10^-19 C) and
that a much smaller negative charge travels over the surface of the
spherical positive charge.As it does so the negative charge, in
combination with the forward motion of the photon as a whole,traces
out a spiral wave pattern with peaks and troughs.The wavelength of the
average cmbr photon is 10^- 4 metres.So a negative charge travelling
at around the speed of light in a circle would take 10^-4/c = 10^-12
seconds per revolution (corresponding to a peak to peak distance).
The force acting on the negative charge is given by:
mv^2/r = k q1 q2/r^2
(I am assuming that the distance between the positive and negative
charge
is so small that, for some reason,the coulomb law becomes valid
again).
m is the rest mass equivalent of the cmbr photon energy (10^-36 kg in
this case) - inertia is assumed to exist as the circling charge
interacts at right angles to the general direction of travel of the
photon, with a medium of particles in which the photon is bathed.Using
q1 = 10^-19 C and q2 = 10^-61 C (I'll explain why later)
10^-36 r^2 / rt^2 = 10^9 x 10^-19 x 10^-61 / r^2
using t = 10^-12 seconds per revolution:
r = 10^-20 metres.
So in a typical cmbr photon of wavelength 10^-36 metres, the negative
and positive charges are 10^-20 metres apart.
Why did I use q2 = 10^-61 C
Because the longest time a cmbr photon can take to lose energy is the
age of the universe- 10^18 seconds.Using E x t = hbar,the minimum mass
is 10^-69 kg, and assuming that this mass derives from split protons
(dark energy has a density of about 10^-26 kg/m^3 - close to the mass
of one proton per cubic metre) with a charge to mass ratio of 10^8,
and that the q/m ratio stays constant, then q2 must be 10^-61.
This value of q2 gives the smallest value that r can have.We can thus
say that,
if the coulomb law is valid at around 10^-20 metres, then the minimum
distance between the positive and negative charges in a cmbr photon of
wavelength 10^-36 metres is 10^-20 metres.
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alistair - 04 Nov 2004 22:03 GMT
The charge sphere of radius 10^-20 metres, in the cmbr photon,could
accommodate 10^42 smaller spheres with a radius of 10^-34 metres (the
string minimum).
10^42 is the factor which splits the proton into masses of
10^-69 kg (10^-27/10^42). An interesting coincidence!
Evidence in support of string theory perhaps?