Home | Contact Us | FAQ | Search & Site Map | Link to Us
Sign In | Join | Other 45 Sites in Network
Home
Discussion Groups
Biology
BiologyBotanyMicrobiologyEntomologyEvolutionPaleontology
Chemistry
General ChemistryAnalytical ChemistryElectrochemistryOrganic Synthesis
Earth Science
GeologyMineralogyOceanographyMeteorologyEarthquakes
Physics
General PhysicsResearchRelativityParticle PhysicsElectromagnetismFusionOpticsAcousticsNew Theories

Natural Science Forum / Physics / Particle Physics / December 2004



Tip: Looking for answers? Try searching our database.

Feynman diagrams - a new interpretation

Thread view: 
Enable EMail Alerts  Start New Thread
Thread rating: 
alistair@goforit64.fsnet.co.uk - 10 Dec 2004 20:07 GMT
A virtual electron-positron pair is created in the vacuum
and then annihilates.In this loop the energy of one of the virtual
particles does not have to follow E^2 = p^2c^2 + m^2c^4 because the
other particle can compensate for its failure to do so.This leads to
infinity in the path integral for all possible
energy combinations for the virtual particles.But here is an
interpretation of Feynman diagrams that does not lead to
infinities:
(1) all particles are real (even the so-called virtual particles)

(2) particles can reach a speed far greater than the speed
of light, but a speed which is,nevertheless,finite.

(3)the speed of any particle is given by the ratio
of an electric field vector associated with that particle divided by a
magnetic field vector associated with that particle.
(E/B)

(4) When a particle and antiparticle annihilate then
E1 + E2 = E3
B1 + B2 = B3
where E3/B3 is the speed of a photon (E1/B1 and E2/B2 would
be speed of particle and antiparticle).

(5) E^2 = p^2c^2 + m^2c^4  = p'^2v^2 + m'^2 v^4
where v = the limiting speed for all particles
(3 x 10^22 m/s - in my opinion!).

David Bohm's version of quantum mechanics then makes sense:
"virtual" particles - which could constitute the guiding wave - would
move real particles, and one real particle would change the velocity of
another real particle, but only after a small time delay.
FrediFizzx - 10 Dec 2004 22:03 GMT
| A virtual electron-positron pair is created in the vacuum
| and then annihilates.In this loop the energy of one of the virtual
[quoted text clipped - 28 lines]
| move real particles, and one real particle would change the velocity of
| another real particle, but only after a small time delay.

If you allow virtual particles, then you also have to allow for "less than
virtual" particles.  These are the particles in a modified Dirac sea.

FrediFizzx

http://www.vacuum-physics.com/QVC/quantum_vacuum_charge.pdf
or postscript
http://www.vacuum-physics.com/QVC/quantum_vacuum_charge.ps
alistair@goforit64.fsnet.co.uk - 10 Dec 2004 22:16 GMT
The magnetic and electric field of the particle and antiparticle will
each be associated with certain total energy.The magnetic field
of each particle could be given by integer multiples of a minimum Bo
e.g
1 x Bo, 2 x Bo, 3 x Bo
since a particle or antiparticle must have a maximum magnetic field
because there is a finite amount of energy in the universe,
this would mean a finite number of energy distributions between
particle and antiparticle and so no infinities in the path
integral.
alistair@goforit64.fsnet.co.uk - 11 Dec 2004 11:58 GMT
David Bohm's version of quantum mechanics can be
summed up as follows:
dQ/dt = f(x,t)
velocity of a particle depends instantaneously on the position of
another particle at a certain time

This is at odds with notions of causality.
However if we write:
dQ/dt = f( x, t - a small increment in t ) and assume a signal passes
from one particle to another, causality is restored to the universe.
alistair@goforit64.fsnet.co.uk - 11 Dec 2004 21:23 GMT
The ratio of E/B for a particle, moving relative to another particle
with its own value of E/B, determines the relative speed of that
particle in the universe.As a quark or lepton moves faster through a
medium of magnetic particles, these magnetic particles accumulate in
the quark or lepton, and cancel out the magnetic charge at the centre
of the quark or lepton (the magnetic charge is inside a sphere of
electric charges).B decreases and the quark or lepton expands.The mass
of the quark or lepton has increased.Relativity theory says that
a particle with a certain rest mass must have a
fixed mass  at a fixed speed.But this is not
the case if B is artificially changed by
outside intervention e.g we could feed magnetic charge to the particle
in a laboratory.
And virtual particle pairs can have lots of combinations of E/B each
with a probability amplitude.We know that E/B can never be greater than
the speed of light for photons, so we know
also that virtual positron-electron pairs (which can yield photons)
can't both have E/B greater than the speed of light.In other words the
probability amplitude for this happening is zero.
Why don't virtual positrons and electrons naturally have a non-zero
probability to travel faster than light
if the limiting value of E/B can be far greater?
There must be a force which limits how much
B ,and therefore energy, can be removed from an
electron ( some B must be tightly bound to electric charge or colour
charge).Virtual particles that transfer  energy from one real particle
to another faster than the speed of light (e.g in my interpretation of
David Bohm's version of quantum mechanics) must have a weaker force
binding
B to electricity or the colour force,and so a high probability of
getting a low B and a high E/B.
alistair@goforit64.fsnet.co.uk - 12 Dec 2004 19:07 GMT
According to Planck's theory:
Energy per unit volume per unit frequency is given by:

Sv = 8pih/c^3 x f ^ 3 / [e ^ (hf/kT) - 1]

Since the energy of a photon is all kinetic, and kinetic energy is
proportional to temperature, and temperature
is proportional to pressure (for an ideal gas),
then the force exerted on a real particle, with rest mass, by
an electromagnetic photon, is proportional to Sv.
Holding frequency,f, constant, and invoking a photon that moves faster
than the speed of light ( a posulated gravitational force carrier-in
reality there will be 2 bound photons to give spin 2 for this
carrier)with speed v, we can write:

force of gravity/force of electricity =
{10^-38 = 8pih/v^3 x f ^ 3 / [e ^ (hf/kT) - 1]}divided by

{ 8pih/c^3 x f ^ 3 / [e ^ (hf/kT) - 1]}
v = 10^21 m/s

The gravitational force carrier moves fast!
alistair@goforit64.fsnet.co.uk - 13 Dec 2004 10:05 GMT
David Bohm's version of quantum mechanics can be
summed up as follows:
dQ/dt = f(x,t)
velocity of a particle depends instantaneously on the position of
another particle at a certain time

This is at odds with notions of causality.
However if we write:
dQ/dt = f( x, t - a small increment in t ) and assume a signal passes
from one particle to another, causality is restored to the universe.

When a real particle changes its position, it stops blocking
gravitatonal force carriers along the line that joined it to a second
real particle, and that second real particle reacts to the
increase in flux.This is the origin of correlated photon
polarizations.Also,because the speed of gravity is 10^21 m/s,
and it takes an atom about 10^-8 seconds to absorb a photon,
we can say that correlated polarizations would no longer exist
at a photon separation of 10^13 metres or greater (it would take the
gravitational force carrier 10^-8 seconds to travel this distance to
cause correlations).10^13 metres is about 100 times the distance of the
Earth to the Sun.So to measure
the breakdown in photon polarization correlation we need to
look for photons from pions that have split into correlated photon
pairs in space,photonswhich have been redirected to Earth by strong
gravitational fields - and photons that have
had their polarization changed by passage through a gas,dust etc.
alistair@goforit64.fsnet.co.uk - 13 Dec 2004 21:12 GMT
The idea that the EM force carrier and the gravitational force carrier
can be considered to be a gas of radiation following a Planck blackbody
spectrum would also suggest that the
EM force of attraction between two opposite charges is caused by a
pushing force.The EM force of repulsion would have to be due to the
effect charges have on the structure of space itself (which would
reduce the transfer of energy from force carriers to one side of a
spherical charge).This probably amounts to saying that
charges affect some surrounding medium of particles which scatter force
carrying particles.
alistair@goforit64.fsnet.co.uk - 14 Dec 2004 13:33 GMT
Particles with rest mass moving faster than light could
only exist in space-time if they somehow obeyed the usual laws of
gravity.
A particle moving in a circular orbit can be described by

v^2 / r  = g

For a bigger value of v at the same radius a bigger value of
g and hence a bigger force are required.The particle speed
is given by E/B.To make the particle orbit faster we
take away some B and some rest mass with it.The particle travels faster
with a smaller rest mass but the same total mass because
a faster moving particle with a smaller rest mass
interacts with more mass-causing particles
(in the medium it is moving through) per unit time.
But because there is less B the mass-causing particles
are not bound tightly and the volume
of the orbiting particle increases , allowing it to trap
more gravitational force carriers from space and to
experience an increased force which keeps it in orbit.
alistair@goforit64.fsnet.co.uk - 14 Dec 2004 23:29 GMT
force of gravity/force of electricity =

{10^-38 = 8pih/v^3 x f ^ 3 / [e ^ (hf/kT) - 1]}divided by

{ 8pih/c^3 x f ^ 3 / [e ^ (hf/kT) - 1]}
v = 10^21 m/s

Using a more accurate value of Fg/Fe ( 7 x 10^-39)
we get v = 5.7 x 10^21 m/s.

This speed makes sense for the following reason:

The gravitational force carrier has the same energy as the electric
carrier but if it has a speed 7 x 10^21/ 3 x 10^8
times faster than light then for the same number
of wavelengths it must have (3 x 10^8/ 7 x 10^21) times the
amplitude, for its electric and magnetic field vectors to have the same
total energy as the electric force carrier ( it is less energetic per
unit length).Squaring the amplitude gives the intensity.
So the gravitional force carrier has an intensity (3 x 10^8/ 7 x
10^21)^2 times less than the electric force carrier.
With a wavelength 7 x 10^21/ 3 x 10^8 times greater it is
1/  (7 x 10^21/ 3 x 10^8)  times less likely to be absorbed
by a spherical charge { probability proportional to
tan^-1[(L1 - 2L2)/ d ] ( L1/L2 cos theta )
where L2 is radius of sphere and L1 is wavelength of force carrier -
deduced using idea that electrically neutral bosons are made from one
positive and one negative charge which oscillate and have to pass
through a spherical "slit"}.

Combining the amplitude squared and the wavelength factor gives a
reduction in intensity for gravity of 7 x 10^ - 39.
alistair@goforit64.fsnet.co.uk - 15 Dec 2004 11:18 GMT
force of gravity/force of electricity =

{10^-38 = 8pih/v^3 x f ^ 3 / [e ^ (hf/kT) - 1]}divided by

{ 8pih/c^3 x f ^ 3 / [e ^ (hf/kT) - 1]}
v = 10^21 m/s

Using a more accurate value of Fg/Fe ( 7 x 10^-39)
we get v = 5.7 x 10^21 m/s.

This speed makes sense for the following reason:

The gravitational force carrier has the same energy as the electric
carrier but if it has a speed 7 x 10^21/ 3 x 10^8
times faster than light then for the same number
of wavelengths it must have (3 x 10^8/ 7 x 10^21) times the
amplitude, for its electric and magnetic field vectors to have the same
total energy as the electric force carrier ( it is less energetic per
unit length).Squaring the amplitude gives the intensity.
So the gravitional force carrier has an intensity (3 x 10^8/ 7 x
10^21)^2 times less than the electric force carrier.
With an amplitude averaging 7 x 10^21/ 3 x 10^8 times smaller it must
be 1/  (7 x 10^21/ 3 x 10^8)  times less likely to be absorbed by a
spherical charge (the amplitude will be a measure of how positive and
negative charges are seperated within the electrically neutral bosons,
and hence of how
unscreened a charge is and how able it is to interact with the
charges of a larger spherical charge such as a proton).
Combining the amplitude squared and the amplitude gives a reduction in
intensity for gravity of 7 x 10^ - 39.
alistair@goforit64.fsnet.co.uk - 14 Dec 2004 22:32 GMT
force of gravity/force of electricity =

{10^-38 = 8pih/v^3 x f ^ 3 / [e ^ (hf/kT) - 1]}divided by

{ 8pih/c^3 x f ^ 3 / [e ^ (hf/kT) - 1]}
v = 10^21 m/s

Using a more accurate value of Fg/Fe ( 7 x 10^-39)
we get v = 5.7 x 10^21 m/s.

This speed makes sense for the following reason:

The gravitational force carrier has the same energy as the electric
carrier but if it has a speed 7 x 10^21/ 3 x 10^8
times faster than light then for the same number
of wavelengths it must have (3 x 10^8/ 7 x 10^21) times the
amplitude, for its electric and magnetic field vectors to have the same
total energy as the electric force carrier ( it is less energetic per
unit length).Squaring the amplitude gives the intensity.
So the gravitional force carrier has an intensity (3 x 10^8/ 7 x
10^21)^2 times less than the electric force carrier.
With an amplitude averaging 7 x 10^21/ 3 x 10^8 times smaller it must
be 1/  (7 x 10^21/ 3 x 10^8)  times less likely to be absorbed by a
spherical charge (the amplitude will be a measure of how positive and
negative charges are seperated within the electrically neutral bosons,
and hence of how
unscreened a charge is and how able it is to interact with the
charges of a larger spherical charge such as a proton).
Combining the amplitude squared and the amplitude gives a reduction in
intensity for gravity of 7 x 10^ - 39.
alistair@goforit64.fsnet.co.uk - 14 Dec 2004 23:25 GMT
force of gravity/force of electricity =

{10^-38 = 8pih/v^3 x f ^ 3 / [e ^ (hf/kT) - 1]}divided by

{ 8pih/c^3 x f ^ 3 / [e ^ (hf/kT) - 1]}
v = 10^21 m/s

Using a more accurate value of Fg/Fe ( 7 x 10^-39)
we get v = 5.7 x 10^21 m/s.

This speed makes sense for the following reason:

The gravitational force carrier has the same energy as the electric
carrier but if it has a speed 7 x 10^21/ 3 x 10^8
times faster than light then for the same number
of wavelengths it must have (3 x 10^8/ 7 x 10^21) times the
amplitude, for its electric and magnetic field vectors to have the same
total energy as the electric force carrier ( it is less energetic per
unit length).Squaring the amplitude gives the intensity.
So the gravitional force carrier has an intensity (3 x 10^8/ 7 x
10^21)^2 times less than the electric force carrier.
With a wavelength 7 x 10^21/ 3 x 10^8 times greater it is
1/  (7 x 10^21/ 3 x 10^8)  times less likely to be absorbed
by a spherical charge { probability proportional to
tan^-1[(L1 - 2L2)/ L1 ] ( L1/L2 cos theta )
where L2 is radius of sphere and L1 is wavelength of force carrier -
deduced using idea that electrically neutral bosons are made from one
positive and one negative charge which oscillate and have to pass
through a spherical "slit" at different angles relative to the "slit"}.
Combining the reduction for the amplitude squared and the wavelength,we
get a reduction in intensity for gravity
of 7 x 10  ^ -39.
alistair@goforit64.fsnet.co.uk - 14 Dec 2004 23:29 GMT
force of gravity/force of electricity =

{10^-38 = 8pih/v^3 x f ^ 3 / [e ^ (hf/kT) - 1]}divided by

{ 8pih/c^3 x f ^ 3 / [e ^ (hf/kT) - 1]}
v = 10^21 m/s

Using a more accurate value of Fg/Fe ( 7 x 10^-39)
we get v = 5.7 x 10^21 m/s.

This speed makes sense for the following reason:

The gravitational force carrier has the same energy as the electric
carrier but if it has a speed 7 x 10^21/ 3 x 10^8
times faster than light then for the same number
of wavelengths it must have (3 x 10^8/ 7 x 10^21) times the
amplitude, for its electric and magnetic field vectors to have the same
total energy as the electric force carrier ( it is less energetic per
unit length).Squaring the amplitude gives the intensity.
So the gravitional force carrier has an intensity (3 x 10^8/ 7 x
10^21)^2 times less than the electric force carrier.
With a wavelength 7 x 10^21/ 3 x 10^8 times greater it is
1/  (7 x 10^21/ 3 x 10^8)  times less likely to be absorbed
by a spherical charge { probability proportional to
tan^-1[(L1 - 2L2)/ d ] ( L1/L2 cos theta )
where L2 is radius of sphere and L1 is wavelength of force carrier -
deduced using idea that electrically neutral bosons are made from one
positive and one negative charge which oscillate and have to pass
through a spherical "slit"}.

Combining the amplitude squared and the wavelength factor gives a
reduction in intensity for gravity of 7 x 10^ - 39.
alistair@goforit64.fsnet.co.uk - 14 Dec 2004 23:49 GMT
force of gravity/force of electricity =

{10^-38 = 8pih/v^3 x f ^ 3 / [e ^ (hf/kT) - 1]}divided by

{ 8pih/c^3 x f ^ 3 / [e ^ (hf/kT) - 1]}
v = 10^21 m/s

Using a more accurate value of Fg/Fe ( 7 x 10^-39)
we get v = 5.7 x 10^21 m/s.

This speed makes sense for the following reason:

The gravitational force carrier has the same energy as the electric
carrier but if it has a speed 7 x 10^21/ 3 x 10^8
times faster than light then for the same number
of wavelengths it must have (3 x 10^8/ 7 x 10^21) times the
amplitude, for its electric and magnetic field vectors to have the same
total energy as the electric force carrier ( it is less energetic per
unit length).Squaring the amplitude gives the intensity.
So the gravitional force carrier has an intensity (3 x 10^8/ 7 x
10^21)^2 times less than the electric force carrier.
With a wavelength 7 x 10^21/ 3 x 10^8 times greater it is
1/  (7 x 10^21/ 3 x 10^8)  times less likely to be absorbed
by a spherical charge { probability for absorption proportional to
speed}
Combining the amplitude squared and the wavelength (speed) factor gives
a reduction in intensity for gravity of 7 x 10^ - 39.
alistair@goforit64.fsnet.co.uk - 14 Dec 2004 23:50 GMT
force of gravity/force of electricity =

{10^-38 = 8pih/v^3 x f ^ 3 / [e ^ (hf/kT) - 1]}divided by

{ 8pih/c^3 x f ^ 3 / [e ^ (hf/kT) - 1]}
v = 10^21 m/s

Using a more accurate value of Fg/Fe ( 7 x 10^-39)
we get v = 5.7 x 10^21 m/s.

This speed makes sense for the following reason:

The gravitational force carrier has the same energy as the electric
carrier but if it has a speed 7 x 10^21/ 3 x 10^8
times faster than light then for the same number
of wavelengths it must have (3 x 10^8/ 7 x 10^21) times the
amplitude, for its electric and magnetic field vectors to have the same
total energy as the electric force carrier ( it is less energetic per
unit length).Squaring the amplitude gives the intensity.
So the gravitional force carrier has an intensity (3 x 10^8/ 7 x
10^21)^2 times less than the electric force carrier.
With a wavelength 7 x 10^21/ 3 x 10^8 times greater it is
1/  (7 x 10^21/ 3 x 10^8)  times less likely to be absorbed
by a spherical charge { probability for absorption proportional to
speed}
Combining the amplitude squared and the wavelength (speed) factor gives
a reduction in intensity for gravity of 7 x 10^ - 39.
alistair@goforit64.fsnet.co.uk - 15 Dec 2004 00:10 GMT
force of gravity/force of electricity =

{10^-38 = 8pih/v^3 x f ^ 3 / [e ^ (hf/kT) - 1]}divided by

{ 8pih/c^3 x f ^ 3 / [e ^ (hf/kT) - 1]}
v = 10^21 m/s

Using a more accurate value of Fg/Fe ( 7 x 10^-39)
we get v = 5.7 x 10^21 m/s.

This speed makes sense for the following reason:

The gravitational force carrier has the same energy as the electric
carrier but if it has a speed 7 x 10^21/ 3 x 10^8
times faster than light then for the same number
of wavelengths it must have (3 x 10^8/ 7 x 10^21) times the
amplitude, for its electric and magnetic field vectors to have the same
total energy as the electric force carrier ( it is less energetic per
unit length).Squaring the amplitude gives the intensity.
So the gravitional force carrier has an intensity (3 x 10^8/ 7 x
10^21)^2 times less than the electric force carrier.
With an amplitude averaging 7 x 10^21/ 3 x 10^8 times smaller it must
be 1/  (7 x 10^21/ 3 x 10^8)  times less likely to be absorbed by a
spherical charge (the amplitude will be a measure of how positive and
negative charges are seperated within the electrically neutral bosons,
and hence of how
unscreened a charge is and how able it is to interact with the
charges of a larger spherical charge such as a proton).
Combining the amplitude squared and the wavelength factor gives a
reduction in intensity for gravity of 7 x 10^ - 39.
alistair@goforit64.fsnet.co.uk - 15 Dec 2004 00:22 GMT
force of gravity/force of electricity =

{10^-38 = 8pih/v^3 x f ^ 3 / [e ^ (hf/kT) - 1]}divided by

{ 8pih/c^3 x f ^ 3 / [e ^ (hf/kT) - 1]}
v = 10^21 m/s

Using a more accurate value of Fg/Fe ( 7 x 10^-39)
we get v = 5.7 x 10^21 m/s.

This speed makes sense for the following reason:

The gravitational force carrier has the same energy as the electric
carrier but if it has a speed 7 x 10^21/ 3 x 10^8
times faster than light then for the same number
of wavelengths it must have (3 x 10^8/ 7 x 10^21) times the
amplitude, for its electric and magnetic field vectors to have the same
total energy as the electric force carrier ( it is less energetic per
unit length).Squaring the amplitude gives the intensity.
So the gravitional force carrier has an intensity (3 x 10^8/ 7 x
10^21)^2 times less than the electric force carrier.
With an amplitude averaging 7 x 10^21/ 3 x 10^8 times smaller it must
be 1/  (7 x 10^21/ 3 x 10^8)  times less likely to be absorbed by a
spherical charge (the amplitude will be a measure of how positive and
negative charges are seperated within the electrically neutral bosons,
and hence of how
unscreened a charge is and how able it is to interact with the
charges of a larger spherical charge such as a proton).
Combining the amplitude squared and the wavelength factor gives a
reduction in intensity for gravity of 7 x 10^ - 39.
alistair@goforit64.fsnet.co.uk - 15 Dec 2004 00:58 GMT
force of gravity/force of electricity =

{10^-38 = 8pih/v^3 x f ^ 3 / [e ^ (hf/kT) - 1]}divided by

{ 8pih/c^3 x f ^ 3 / [e ^ (hf/kT) - 1]}
v = 10^21 m/s

Using a more accurate value of Fg/Fe ( 7 x 10^-39)
we get v = 5.7 x 10^21 m/s.

This speed makes sense for the following reason:

The gravitational force carrier has the same energy as the electric
carrier but if it has a speed 7 x 10^21/ 3 x 10^8
times faster than light then for the same number
of wavelengths it must have (3 x 10^8/ 7 x 10^21) times the
amplitude, for its electric and magnetic field vectors to have the same
total energy as the electric force carrier ( it is less energetic per
unit length).Squaring the amplitude gives the intensity.
So the gravitional force carrier has an intensity (3 x 10^8/ 7 x
10^21)^2 times less than the electric force carrier.
With a wavelength 7 x 10^21/ 3 x 10^8 times greater it is
1/  (7 x 10^21/ 3 x 10^8)  times less likely to be absorbed
by a spherical charge { probability proportional to
tan^-1[(L1 - 2L2)/ d ] ( L1/L2 cos theta )
where L2 is radius of sphere and L1 is wavelength of force carrier -
deduced using idea that electrically neutral bosons are made from one
positive and one negative charge which oscillate and have to pass
through a spherical "slit"}.

Combining the amplitude squared and the wavelength factor gives a
reduction in intensity for gravity of 7 x 10^ - 39.
alistair@goforit64.fsnet.co.uk - 15 Dec 2004 19:03 GMT
force of gravity/force of electricity =

{10^-38 = 8pih/v^3 x f ^ 3 / [e ^ (hf/kT) - 1]}divided by

{ 8pih/c^3 x f ^ 3 / [e ^ (hf/kT) - 1]}
v = 10^21 m/s

Using a more accurate value of Fg/Fe ( 7 x 10^-39)
we get v = 5.7 x 10^21 m/s.

This speed makes sense for the following reason:

The gravitational force carrier has the same energy as the electric
carrier but if it has a speed 7 x 10^21/ 3 x 10^8
times faster than light then for the same number
of wavelengths it must have (3 x 10^8/ 7 x 10^21) times the
amplitude, for its electric and magnetic field vectors to have the same
total energy as the electric force carrier ( it is less energetic per
unit length).Squaring the amplitude gives the intensity.
So the gravitional force carrier has an intensity (3 x 10^8/ 7 x
10^21)^2 times less than the electric force carrier.
With an amplitude averaging 7 x 10^21/ 3 x 10^8 times smaller it must
be 1/  (7 x 10^21/ 3 x 10^8)  times less likely to be absorbed by a
spherical charge (the amplitude will be a measure of how positive and
negative charges are seperated within the electrically neutral bosons,
and hence of how
unscreened a charge is and how able it is to interact with the
charges of a larger spherical charge such as a proton).
Combining the amplitude squared and the amplitude gives a reduction in
intensity for gravity of 7 x 10^ - 39.
(essentially I am saying that the electric and gravitational forces
between particles with rest mass are caused by electromagnetic waves
and gravitational waves.
alistair@goforit64.fsnet.co.uk - 11 Dec 2004 11:28 GMT
If you allow virtual particles, then you also have to allow for "less
than
virtual" particles. These are the particles in a modified Dirac sea.

FrediFizzx

http://www.vacuum-physics.com/QVC/quantum_vacuum_charge.pdf
or postscript
http://www.vacuum-physics.com/QVC/quantum_vacuum_charge.ps
Reply

Thanks for the references.

Alistair
 
Sign In
Join
My Latest Posts
My Monitored Threads
My Blog
My Photo Gallery
My Profile
My Homepage

Start New Thread
Enable EMail Alerts
Rate this Thread



©2009 Advenet LLC   Privacy Policy - Terms of Use
This website includes both content owned or controlled by Advenet as well as content owned or controlled by third parties.