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zincnews123@tiscali.c123o.u123k
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>Is this a general thing in maths that if a function contains a sum then a
>product of that function (with its complex conjugate in this case)requires 2
>separate indices.
Yes. To see this, simply write out the sum(s) and perform the indicated
multiplication. Use a a small, finite number of terms in the sum to make
the algebra manageable. For example, let f = f_1 + f_2 + f_3. Then
f*f = (f_1 + f_2 + f_3)*(f_1 + f_2 + f_3)
f*f = f_1*f_1 + f_1*f_2 + f_1*f_3
+ f_2*f_1 + f_2*f_2 + f_2*f_3
+ f_3*f_1 + f_3*f_2 + f_3*f_3
Writing the product using f in summation form, if you try to use a single
index you get
f*f = sum(f_n*f_n)
f*f = f_1*f_1 + f_2*f_2 + f_3*f_3
which is very different from what I wrote above. On the other hand if you
have two indices, that indicates a "double sum" (even though we may write
it as a single summation for brevity):
f*f = sum over m (sum over n (f_m*f_n))
f*f = sum over m (f_m*f_1 + f_m*f_2 + f_m*f_3)
f*f = f_1*f_1 + f_1*f_2 + f_1*f_3
+ f_2*f_1 + f_2*f_2 + f_2*f_3
+ f_3*f_1 + f_3*f_2 + f_3*f_3
which is what I wrote first above.

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Jon Bell <jtbell@presby.edu> Presbyterian College
Dept. of Physics and Computer Science Clinton, South Carolina USA