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Natural Science Forum / Physics / Particle Physics / May 2005



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What is the principal difference between a photon and a neutrino?

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Y.Porat - 28 May 2005 04:30 GMT
The  photon is known to have no mass

The neutrino has mass

yet the  neurtino is a particle in motion-
so behaves  wave like .

and can penetrate our globe as if it was nothing.

the photon , on the other hand, cannot penertate a thin
methal plate
so what  (the heck) makes the  difference between those two??

TIA
Y.Porat
---------------
Sam Wormley - 28 May 2005 04:57 GMT
The neutrino is one of six known Leptons
   o spin = 1/2
   o non zero rest mass

photon is a Boson (force carrier)
   o spin = 1
   o zero rest mass

They behave different quantum mechanical rules and statistics.
Here's a summary chart
  http://particleadventure.org/particleadventure/frameless/chart_cutouts/particle_
chart.jpg

Y.Porat - 28 May 2005 07:04 GMT
thanks Sam
yet still those 'dry data'
does not make me  ( or you??))
to unserstand  for instance why
the neutrino is penetrating so easy matter
while a photon cannot do it??
TIA
Y.Porat
------------------------
hanson - 28 May 2005 07:30 GMT
> thanks Sam
> yet still those 'dry data'
[quoted text clipped - 5 lines]
> Y.Porat
> ------------------------
[hanson]
Yehiel,
Dearly departed Franz Heymann said many times
that a neutrino is an electron that lost its charge.
He spent many years as group leader in CERN
pondering questions like that....... ahahahaha...
Can you see the answer to your question now?
ahahaha...ahahanson
FrediFizzx - 28 May 2005 08:17 GMT
| > thanks Sam
| > yet still those 'dry data'
[quoted text clipped - 13 lines]
| Can you see the answer to your question now?
| ahahaha...ahahanson

Ya got a reference for that?  I don't ever recall Franz saying that.
Even though, it is probably close to the truth.  I would even extend it
to quarks.  Neutrinos are quarks that have lost their charges.
Neutrinos are the clue for sure.  IMHO, they are as close as we will
ever get to the bare entity that makes all fermions.  What the heck,
let's extend it even more; leptons are quarks that have lost their color
charge.  And all elementary bosons are instantaneously virtual fermionic
pairs.

FrediFizzx

http://www.vacuum-physics.com/QVC/quantum_vacuum_charge.pdf
or postscript
http://www.vacuum-physics.com/QVC/quantum_vacuum_charge.ps
Jerry - 28 May 2005 08:34 GMT
> | Yehiel,
> | Dearly departed Franz Heymann said many times
[quoted text clipped - 12 lines]
> quarks that have lost their color charge.  And all elementary
> bosons are instantaneously virtual fermionic pairs.

Franz never said that a neutrino -is- an electron that lost
its charge. Rather, he said that he often -thought- of the
neutrino in that fashion.

"I may be misleading myself, but I often think of the neutrino as
being simply a chargeless electron.  It participates in all the
interactions (W and Z exchange) in which an electron participates,
except for photon exchange, which requires a charged particle."
http://groups-beta.google.com/group/sci.physics/msg/3fa23880bf62e899?hl=en

Jerry
Y.Porat - 28 May 2005 10:31 GMT
you say 'a chargeles electron'
could be reasonable yet
is their masses  fit t othink so??
btw if that is the answwer
can we infere from it what is the mass loss that belongs to the
charge??

2 supose you are right (and it seems right that the neutrino is
chargless)
to explainits strong penetrative power

now about the  the photon --can you say that the photon is charged??
charged waht ? positively negatively ??
TIA
Y.Porat
----------------------------
hanson - 28 May 2005 16:26 GMT
> | > thanks Sam
> | > yet still those 'dry data'
[quoted text clipped - 13 lines]
> | Can you see the answer to your question now?
> | ahahaha...ahahanson

[Fredi]
> Ya got a reference for that?  I don't ever recall Franz saying that.
> Even though, it is probably close to the truth.  I would even extend it
[quoted text clipped - 8 lines]
> http://www.vacuum-physics.com/QVC/quantum_vacuum_charge.ps
>> FrediFizzx

[hanson]
Jerry just posted a reference for you where Franz was rather cautious
about it. But in private conversations and on other google archived
occasions Franz was more adamant about it. However, I could never
prey out of him his thoughts of how the physical mechanism of that
would work, nor how he pictures the property of charge to be.
BTW,
there is some ancillary possibility to this issue in my yesterdays post to
you in news:E1Ole.1727$MI4.856@newsread2.news.pas.earthlink.net.
containing issues over the mass amounts emerging from combining
measured physical constants like:
m_H = [c^2/2G]*[sqrt(hG/(2pi*c^3)]*[I_H/(f_L*F)]*(3*pi^2)*sqrt(2a)
m_e = [c^2/G] * [sqrt(hG/(2pi*c^3)]*[1/(f_L*F)] * a*pi*sqrt(3)/3
Because of the square roots appearing above in the geometric/topo
factors with the Planck lenght [sqrt(hG/(2pi*c^3)] and in [... pi*sqrt...]
a case can be made that 4! = 24 different type of charges could
possibly exist, giving matter properties that may reflect in what you
are into..... and making your vacuum charge even more intriguing
then you're so far imagining... So, by all means, keep on hacking away,
dude... I enjoy wild and crazy ideas...... ahahaha... ahahahanson

BTW: There's no such thing as instantaneous. There's a few posts on
possible max velocities in the virtual realm. IIRC it's ~ 1E+71 cm/sec
.... almost instantaneous... but not quite....... AHAHAHAHA....
FrediFizzx - 28 May 2005 19:57 GMT
| > | > thanks Sam
| > | > yet still those 'dry data'
[quoted text clipped - 34 lines]
| prey out of him his thoughts of how the physical mechanism of that
| would work, nor how he pictures the property of charge to be.

Yes, he was usually cautious about such things.  I wonder how I missed
these posts of Franz?  Anywise, our whole quantum "vacuum" charge "spin
matrix" concept is based on the fundamental entity of fermions being all
the same and it is the quantum "vacuum" configuration that determines
which fermion is which.  Charge is a purely mechanical function even if
it is quantum *mechanical*.  If there is no fundamental mass quantum,
then all mass is the result of charges interacting.  Of course weak and
strong charge to be included along with electric.  Then electric, weak,
strong plus the geometry of their interactions ---> gravity.  This
requires a dual space-time scenario where we have real fermions, virtual
fermions and "less than virtual" fermions.  "Less than virtual" being a
Dirac-like Sea modified (the quantum "vacuum").  Virtual is simply the
state of going between "real" and "less than virtual".

| BTW,
| there is some ancillary possibility to this issue in my yesterdays post to
[quoted text clipped - 10 lines]
| then you're so far imagining... So, by all means, keep on hacking away,
| dude... I enjoy wild and crazy ideas...... ahahaha... ahahahanson

I will check out and study that other thread.  BTW, I stumbled upon a
curious thing involving Planck units.  In cgs units, charge can be
expressed as sqrt(hbar*c) and current as c^3/sqrt(G).  Charge doesn't
need Newton's G and current doesn't need Planck's hbar.  ???  In units
where c = 1, charge is sqrt(hbar) and current is 1/sqrt(G).  Current is
charge per time so t = sqrt(G*hbar).  Which is Planck time in c = 1
units.

| BTW: There's no such thing as instantaneous. There's a few posts on
| possible max velocities in the virtual realm. IIRC it's ~ 1E+71 cm/sec
| .... almost instantaneous... but not quite....... AHAHAHAHA....

OK, not instantaneous. ;-)  In the future if I say instantaneous, I mean
during an extremely short time interval.  It's my bad habit of trying to
"freeze stop" everything (cheating mother nature). ;-)

FrediFizzx

http://www.vacuum-physics.com/QVC/quantum_vacuum_charge.pdf
or postscript
http://www.vacuum-physics.com/QVC/quantum_vacuum_charge.ps
Maleki - 28 May 2005 15:53 GMT
> a neutrino is an electron that lost its charge.

So charge itself is what carries the mass in electron?

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Y.Porat - 29 May 2005 06:26 GMT
> > a neutrino is an electron that lost its charge.
>
> So charge itself is what carries the mass in electron?
>
> --
---------
you are right with your remark:

th echarge is just a bypriduct of a particle

it cannot be the main body of the particle!
iow the charge is just a 'messenger' of the particle
and not its main body!!

so Frantz's description is void!

(what do you say to that old farther Uncle Al??)

all the best
Y.Porat
-----------------
PD - 28 May 2005 14:35 GMT
> The neutrino is one of six known Leptons
>     o spin = 1/2
[quoted text clipped - 7 lines]
> Here's a summary chart
>    http://particleadventure.org/particleadventure/frameless/chart_cutouts/particle_
chart.jpg

To which I would add that the photon participates in the
electromagnetic interaction, and the neutrino participates in the weak
interaction. The weak interaction being much weaker than the
electromagnetic, this explains why the neutrino has enormous range in
matter compared to the photon.

PD
Y.Porat - 28 May 2005 14:51 GMT
ok
do you want to say that if a photon is passing in an electrc field
or magmnetic field
it will be attrated somewhere??

we are not dealing with 'how it was created'
we are dealind with its behaviour after being created.

is what you say a guess or is it substantiated.
if yes - how is it substantiated??

2 both of them are wave or wave like
and the neotrino has mass so why should it not be hindered say
by the gravitational foeld ??

TIA
Y.Porat
----------------------
Y.Porat - 29 May 2005 13:25 GMT
> > The neutrino is one of six known Leptons
> >     o spin = 1/2
[quoted text clipped - 13 lines]
> electromagnetic, this explains why the neutrino has enormous range in
> matter compared to the photon.
----------------
it sounds like some answer
now lets wxamine it a bit:

in your answer there is the hideen assumption that if a particle
was created by say one force then it is only that force that can
infuence it (act on it)
say for example
if a photon is created by Em force then it is only the EM that can
affect it
or say if an electronm was emmited by Em action then it is only
the Em field that will act on it
is it a right assumption??
if an electron was emmited by Em reaction will say the gravitation
not act on it ?? will the strong force not act on it ??

so we came to another principal question:
if a particle was created( or ejected out) by one kind of forces
there will not be another kind that will act on it ???

2
supose that the answer to th e  above question is positive
now we can asume that in our globe there is alot of *weak  force
activity*

so why should not that activity show of on the neutrino
passing through our globe??

3 does the Em field act on the photon ?
sorry my ignorance and laziness
to find out the answer.

TIA
Y.Porat
-------------------

> PD
Uncle Al - 28 May 2005 17:44 GMT
> The  photon is known to have no mass
>
[quoted text clipped - 7 lines]
> the photon , on the other hand, cannot penertate a thin
> methal plate

f.cking imbecile.

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Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/qz.pdf

 
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