$$ Pendulum clock = accelerometer = altimeter:
$$ [ The reading AT *START* "falls" (drops) DURiNG "free fall". ]
$$ [ Any reading AT *START* "drops" (falls) at LOWER elevation. ]
$$ Gravity is Anti-buoyancy.
GUESS iSS GR T_uv = G_absolute/G ..TENSORs;
= F_c*r^2/G*M1*m1 ..where F_c is F_coulomb;
= F_c*r^2/k_c*q1*q2
= m1*g/G*M1*m1
= m1*g/k_c*q1*q2
= 1/(n - 1)
= G_relative
= GR = GTR = gtr = GR Tivity = Gr.
Therefore:
G*M1*m1 = k_c*q1*q2 = (n - 1)*Fc*r^2 ..F_c is PROPER notation;
= (n - 1)*m1*r^2*g
= (n - 1)*(eM + eV)*r
= (n - 1)*eG*r
= (n - 1)*m1*r*v1^2
= m1*r*vesc^2/2 ..v_escape, vesc
= mS*r^2*g ..mS is SiGNETiC mass.
$$ SiGNETiC mass mS changes, from (+) OUTgoing to (-) iNcoming.
Sue... wrote: > > Ken S. Tucker wrote: -=-
> > Take a cylinder floating in space, -=-
> > and prove gravity doesn't exist? > > LOL >
> Right!... -=- > (inertial = no forces)
> A lot of confusion abounds concerning the term "free fall"
> and acceleration. A "free falling" accelerometer does not
> read zero. -=-
$$ Pendulum clock = accelerometer = altimeter.
$$ [ The reading AT *START* "falls" (drops) DURiNG "free fall". ]
$$ [ Any reading AT *START* "drops" (falls) at LOWER elevation. ]
$$ HOPE this helps, ```Brian A M Stuckless, Ph.T (Tivity).
> -=- All the massive entities comprising the accelerometer
> have the same acceleration so it falsely indicates zero.
>
> The free falling machine's velocity wrt a barycentre increases
> expoentially and the energy transaction is revealed when it
> slams into a rock and heats it. An orbital trajectory
> is truly free fall. The velocity (averaged for a period) is
> constant and the energy is conserved. > > Sue...
Re: Invalidity of General Theory of Relativity
Re: Gravity is Anti-buoyancy.
Robert J. Kolker - 23 Feb 2006 14:34 GMT
> Re: Invalidity of General Theory of Relativity
> Re: Gravity is Anti-buoyancy.
Take your meds.
Bob Kolker
PD - 23 Feb 2006 18:41 GMT
Buoyancy is gravity at work!
PD