Home | Contact Us | FAQ | Search & Site Map | Link to Us
Sign In | Join | Other 45 Sites in Network
Home
Discussion Groups
Biology
BiologyBotanyMicrobiologyEntomologyEvolutionPaleontology
Chemistry
General ChemistryAnalytical ChemistryElectrochemistryOrganic Synthesis
Earth Science
GeologyMineralogyOceanographyMeteorologyEarthquakes
Physics
General PhysicsResearchRelativityParticle PhysicsElectromagnetismFusionOpticsAcousticsNew Theories

Natural Science Forum / Physics / Particle Physics / October 2006



Tip: Looking for answers? Try searching our database.

rpasken@eas.slu.edu , You  have made comments that Momentum is not Conserved in my PAPER. It is not CORRECT. It is explained in 100 Years of E=mc2

Thread view: 
Enable EMail Alerts  Start New Thread
Thread rating: 
AJAY SHARMA - 02 Oct 2006 13:50 GMT
rpasken@eas.slu.edu , You  have made comments that Momentum is not
Conserved in my PAPER. It is not CORRECT. It is explained in 100 Years
of E=mc2

rpasken@eas.slu.edu
See how Momentum is conserved in my paper. All references are given in
the end.
                         Part I
General meaning , explained in 11th class Physics.
The law of momentum conservation,
         * In an isolated system, the momentum of system must be
conserved.*

Mathematically implies that
       Initial Momentum = Final Momentum
                       mu=mv    (1)
As mass remains same in classical mechanics.
So   u=v
which is Newton’s First law of motion.

Application of momentum conservation.
When body emits energy ( in this cases light energy)
then it recoils .Thus it is used to calculate the velocity of recoil.
It can be applied to following two cases.

------ Light bullet fired from TOY Gun, system remains at rest.
        ( body does not recoil with  noticeable velocity, it tends to
recoil)
The velocity cam be calculated but may be of the order of
1/100000000000000000000000000000000000 m/s  or 10-^40m/s
This case resembles with Einstein’s two waves of equal energy emitted
in opposite directions.

-----Shot fired from gun, gun moves backward.
the velocity can  be calculated from conservation of momentum i.e.

                   initial momentum =final momentum
  Vrecoil =  mv/M  ~  5m/s (say)
Thus after emission of energy BODY MAY REMAIN AT REST OR MOVE, the
Momentum is Conserved. It is basic physics of 11th standard.
If some one does not want to understand this then it his problem.
Einstein did all calculation under Classical conditions of velocity (v
<<c, her v is relative velocity between two systems i.e. system in
which body emits light and second system in which energy is measured.

                                                  Part II
The law of conservation of momentum is obeyed in my paper.

https://www.novapublishers.com/catalog/product_info.php?cPath=23_48_324&products
_id=4554


  When two waves are emitted. The body recoils with velocity v , with
magnitude of the order of  10^-32 m/s i.e.
V (recoil)=1/10000000000000000000000000000000000000000000000000
It can be easily calculated.

  When two waves of different energies are emitted. If body emits two
light waves of slightly different energies i.e.  0.5001L and 0.4999L
(Einstein has used light waves of energy 0.5L and 0.5L) in opposite
directions. Now using the law of conservation of momentum, it can be
easily justified that in this case body remains at rest.
                                       Let the body  of mass 10kg
emits  light energy in two waves  in visible region equal to
7.9512×10^-19 J, this energy corresponds to TWO  light waves  in
visible region having wavelength  5000ºA  or  energy,  2hc/λ  or
7.9512×10^-19 J.
Let towards the observer the body emits light energy 0.5001L i.e.
3.97639512×10^-19 J i.e. will have momentum ( p1 = E/c)
1.32546504×10^-27 m/s.
Secondly,  the body emits light wave of energy 0.4999L i.e.
3.97480488×10^-19 J, away from the observer  (φ= 180º)  i.e. will
have momentum ( p2 = E/c)  1.32493496×10^-27 m/s. Let us assume that
when the body emits light waves of energy and moves (if it actually
does) with velocity Vb , then according to law of conservation of
momentum  we get
                     0 = p1 +p2 +MbVb   or    Vb =  -(p1 +p2) /Mb =
–5.3×10^-32 m/s        (2)
                     0 = p1 +p2 +MbVb   or    Vb =  -(p1 +p2) /Mb =
–5.3×10^-32 m/s        (3)
Thus conservation of momentum requires that body should move with
velocity –5.3×10^-32 m/s  opposite to observer.  Thus body will
tend to move  with velocity  5.3×10^-32 m/s  ( away from the observer)
which is immeasurably  small by all means,  hence the body remains at
rest. Due to this uniform relative velocity v of the system (ξ, η, ζ
)  will not change, if body  moves then v will vary accordingly.
 =========Einstein’s Sep 1905 paper===========
The first and basic equation in Einstein’s paper  is
 l* = l{1 – v/c cos φ } /√[1 – v2 /c2]       (1)
In eq.(1) v is the relative velocity between light emitting body and
the measuring system i.e.  system (ξ, η, ζ ).  If body moves after
emission with velocity v’ away from the observer, then relative
velocity will be v+v’ (say V). Thus in this case eq.(1) becomes
ℓ* = ℓ{1 – (v+v’) cos φ/c } /√[1 –  (v+v’)2 /c2]
                                 (1a)
The rest of the calculations remain the same. Thus Einstein’s
derivation is also valid if the body moves, Einstein has considered the
simplest case when velocity v’ is zero (V= v+v’ =v), which is
special case. Also experimentally the law of inter conversion of mass
energy holds good in all possible cases.

Hence you cannot say that LAW OF CONSERVATION OF MOEMTUM IS NOT TAKEN
IN ACCOUNT IN MY PAPER.
It is your MISPERCEPTION.

AJAY      SHARMA   2ND Oct 2006

References of Einstein’s work
.
A.Einstein,   Annalen der Physik     18      (1905) 639-641.
.  DOES THE INERTIA OF A BODY DEPEND
UPON ITS ENERGY-CONTENT?
Weblink is
Einstein’s 27 Sep 1905 paper available at
http://www.fourmilab.ch/etexts/einstein/E_mc2/www/

                                PartII
   References of Ajay Sharma’s work

My work is available at
A. Sharma,  Physics Essays, 17   (2004) 195-222.
”The Origin of Generalized Mass-Energy Equation E = Ac2 M; and
its applications   in General physics and Cosmology”.
http://www.burningbrain.org/pdf/ajaysharma_einstein.pdf
For details
https://www.novapublishers.com/catalog/product_info.php?cPath=23_48_324&products
_id=4554


                                 International Conferences
It has been accepted for presentation over 55 conferences all over the
world
--------------------------------------few of them
1.  Sharma, A. presented in 19th International Conference on the
Applications  of  Accelerators  in Research and Industry ,  20-25
August , 2006 Fort Worth Texas,  USA

 2.  A. Sharma,   Abstract Book  38th European Group of Atomic Systems
(
Euro physics   Conference)   Isachia (Naples)   Italy   (2006) 53.

3. A. Sharma  , Abstract Book , A Century After Einstein Physics 2005 ,

10-14 April 2005 (  Organizer  Institute of Physics , Bristol )
University of Warwick , ENGLAND

4. A. Sharma  presented in 5th British gravity Conference , OXFORD
ENGLAND

5.  A. Sharma,. Proc.  Int. Conf. on Computational Methods in
        Sciences  and Engineering 2003 World Scientific Co. USA ,
(2003) 585.

6.  A. Sharma,  Proc. Int. Conf. on Number, Time, Relativity United
        Physical Society of Russian Federation, Moscow ,  (2004) 81
 plus more
--------------------------------------
                                Journals
This paper
”The Origin of Generalized Mass-Energy Equation E = Ac2 M; and
its applications   in General physics and Cosmology”.
is published in journal
  Physics Essays , CANADA
www.physicsessays.com
The paper
The past ,present and future of E=mc2
will be published in 2007 Galilean Electrodynamics, Massachusetts,
USA.
In parts it is published in various others journals.
----------------------
                              Book    100 Years of E=mc2
For details
https://www.novapublishers.com/catalog/product_info.php?cPath=23_48_324&products
_id=4554

dockiers - 04 Oct 2006 13:21 GMT
> rpasken@eas.slu.edu , You  have made comments that Momentum is not
> Conserved in my PAPER. It is not CORRECT. It is explained in 100 Years
[quoted text clipped - 165 lines]
> For details
> https://www.novapublishers.com/catalog/product_info.php?cPath=23_48_324&products
_id=4554
 
Sign In
Join
My Latest Posts
My Monitored Threads
My Blog
My Photo Gallery
My Profile
My Homepage

Start New Thread
Enable EMail Alerts
Rate this Thread



©2009 Advenet LLC   Privacy Policy - Terms of Use
This website includes both content owned or controlled by Advenet as well as content owned or controlled by third parties.