> Could someone please give me an explanation for the fact that spin 1/2
> Baryons in the octet
> cannot consist of three quarks of the same flavor as the Delta++ for
> example.
The spin of u is +1/2, so three of them make +3/2. Alike quarks repel,
so they don't orbit withwise to make +.5+.5-.5. Besides, the Deltas
decay into a nucle?n (1/2) and a pi?n (1), so a Delta is not a
nucle?n by definition.
-Aut
Jim King Wrote:
> Hello,
>
[quoted text clipped - 6 lines]
> THX
> Jim.
The three fermion quarks in a baryon are in a completely antisymmetri
state with respect to color. The Pauli principle then requires tha
the spin-space wave function be completely symmetric with respect t
quark interchange for three identical u quarks. The assumption is mad
that the spatial wave function is completely symmetric and has n
internal or total orbital angular momentum. This means that the spi
state for the three u quarks must be completely symmetric under quar
interchange, and the quark spins must add up to the spin of th
baryon.
The spin state for 1/2+1/2+1/2=3/2 is completely symmetric an
corresponds to the Delta++.
The spin state for 1/2+1/2+1/2=1/2 has mixed symmetry, and so canno
exist for three u quarks
--
Meir Achuz
Jim King - 06 Dec 2006 19:38 GMT
Thank You Meir,
But why cant the Baryon spin state for quark flavors (u,u,u) be this
symmetric combination.
(++-) + (+-+) + (-++)
?
> Jim King Wrote:
>> Hello,
[quoted text clipped - 20 lines]
> The spin state for 1/2+1/2+1/2=1/2 has mixed symmetry, and so cannot
> exist for three u quarks.
Autymn D. C. - 06 Dec 2006 23:34 GMT