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Natural Science Forum / Physics / Particle Physics / December 2007question about light
If 2 beams of light are in the same path and in the same direction and of the same frequency and seen as a wave they are 180deg out of phase, then do they cancel out? and if so does energy dissapear? > If 2 beams of light are in the same path and in the same direction > and of the same frequency and seen as a wave they are 180deg out > of phase, then do they cancel out? and if so does energy dissapear? disappear Why would there be energy there first? >> If 2 beams of light are in the same path and in the same direction >> and of the same frequency and seen as a wave they are 180deg out >> of phase, then do they cancel out? and if so does energy dissapear? > disappear > > Why would there be energy there first? E=hv > >> If 2 beams of light are in the same path and in the same direction > >> and of the same frequency and seen as a wave they are 180deg out [quoted text clipped - 4 lines] > > E=hv 0 = h0 > If 2 beams of light are in the same path and in the same direction > and of the same frequency and seen as a wave they are 180deg out > of phase, then do they cancel out? and if so does energy dissapear? Yes, they cancel out. That's what an AR coating on eyeglasses does: produces two beams of light in the same path and in the same direction and of the same frequency and 180 degrees out of phase. And it will generally cost you about $20 to have that applied to your glasses. No, the energy does not disappear. It goes someplace else other than the light beam in that path in that direction. (In the case of AR coatings, where do you suppose that goes, and then why is that useful?) PD > > If 2 beams of light are in the same path and in the same direction > > and of the same frequency and seen as a wave they are 180deg out [quoted text clipped - 11 lines] > > PD yes the above - does not disapear one of the basics of physics is conservation of energy so the satrt point to search is *to what kind of another energy it was transformed* my guess is heat waves (with a completely different wave lenght) ATB Y.Porat -------------------------- > > > If 2 beams of light are in the same path and in the same direction > > > and of the same frequency and seen as a wave they are 180deg out [quoted text clipped - 17 lines] > so the satrt point to search is > *to what kind of another energy it was transformed* OK, so far. > my guess is > heat waves (with a completely different wave lenght) Not with eyeglasses, no. > ATB > Y.Porat > -------------------------- > > > > If 2 beams of light are in the same path and in the same direction > > > > and of the same frequency and seen as a wave they are 180deg out [quoted text clipped - 32 lines] > > - Show quoted text - --------------- so where does the energy in eyeglasses 'disapear'? Y.Porat ----------------------------------- > > > > > If 2 beams of light are in the same path and in the same direction > > > > > and of the same frequency and seen as a wave they are 180deg out [quoted text clipped - 38 lines] > Y.Porat > ----------------------------------- It doesn't disappear. The transmission coefficient through the glasses improves. That's that an AR coating does. It's a simple technology used the world wide. PD > > > > > > If 2 beams of light are in the same path and in the same direction > > > > > > and of the same frequency and seen as a wave they are 180deg out [quoted text clipped - 46 lines] > > - Show quoted text - ------------ so ?? is the imput energy of light coming to the coating is **exactly** the output energy that cames out ?? no losses ?? and if some losses where do they go ?? TIA Y.Porat ------------------------ |
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