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Natural Science Forum / Physics / Particle Physics / May 2008Could somebody explain to me why the degree of freedom of graviton is D(D-3)/2??
Could somebody explain to me why the degree of freedom of graviton is D(D-3)/2? Thanks in advance Youngsub On 4 Maj, 22:30, yy...@fas.harvard.edu wrote: > Could somebody explain to me why the degree of freedom of graviton is > D(D-3)/2? The metric is a symmetric 2-tensor with D(D+1)/2 components. Diffeomorphisms give D constraints. Since these constraints are first class, they count twice (constraint + gauge fixing condition). D(D+1)/2 - 2D = D(D-3)/2. |
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