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Natural Science Forum / Physics / Research / July 2008



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speed/velocity c in GR

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Chalky - 16 Jun 2008 13:40 GMT
I have noticed that Einstein stresses in various places that, whereas
the speed/velocity of light is constant in SR, it is not in GR.

The reason for my current source of confusion here is that Einstein
wrote in German, where there is no linguistic distinction between
vector (velocity) and scalar (speed).

It is obvious that the vector must vary since light rays bend in
gravitational fields.

However, the situation for the scalar seems rather less clear to me,
at present.

Does anyone know of any accelerating (linear or rotating) reference
frame experiments which unambiguously resolve this question one way or
the other?

(pleaseremove spam from address for emailed response)
Igor Khavkine - 16 Jun 2008 20:54 GMT
> I have noticed that Einstein stresses in various places that, whereas
> the speed/velocity of light is constant in SR, it is not in GR.

One may hear this assertion from time to time. However, its truth
depends greatly on the definition of "speed of light" that is used.

I think it is best (that is, to avoid as much confusion as possible)
to consider the speed of light to be constant everywhere. I discussed
this issue in detail in an old post:

news:1161021765.752413.52950@h48g2000cwc.googlegroups.com
http://groups.google.ca/group/sci.physics.research/msg/5b598d3b6e4fbce7

Hope this helps.

Igor
Chalky - 02 Jul 2008 21:18 GMT
> I think it is best (that is, to avoid as much confusion as possible)
> to consider the speed of light to be constant everywhere.

I am inclined to agree. It certainly makes matters simpler.

I have often thought that, given  all our observations of the
constancy of c were made in the accelerating frames we actually
inhabit, it seems a bit peculiar to conclude from this that c is
constant in inertial frames but perhaps not in accelerating frames.
Tom Roberts - 05 Jul 2008 14:44 GMT
>> I think it is best (that is, to avoid as much confusion as possible)
>> to consider the speed of light to be constant everywhere.
>
> I am inclined to agree. It certainly makes matters simpler.

It's not a question of opinion, or of making things "simpler" ("Keep
things as simple as possible, BUT NO SIMPLER." -- A. Einstein). It's a
question of how this is measured and modeled. In our current best model,
General Relativity, there's no question: over a non-local path the
vacuum speed of light need not be c (even though the local speed of
light is c at each point along the path). This is a basic instance of
the curvature of spacetime.

To see this there's no need to consider light bending around the sun
(though that's an experimental confirmation of the model). One need not
even worry about synchronization of distant clocks. In Schwarzschild
spacetime and Schw. coordinates, for a clock at A and a mirror at B
directly above A, the round-trip vacuum speed of light is not c, where
speed means twice the number of standard meter sticks that can be laid
between A and B divided by the elapsed time during the light's flight
measured by a standard clock at point A. Adding another clock and
mirror, the speed for B->A->B differs from A->B->A; adding a mirror C an
equal number of meter sticks below A, the speed for A->C->A is different
from either of them. Unfortunately, for the earth and sun these
differences are too small to measure directly, and interference methods
suffer from the impossibility of making a Michelson interferometer rigid
enough to rotate in a vertical plane.

    Hmmm. I wonder if it could be sensitive enough to rotate in
    a horizontal plane on earth, and measure the effect due to
    the sun? Probably not, as these interferometers are
    notoriously unstable.... And, of course, Kennedy and
    Thorndike (and similar experiments) could have seen
    at least some fraction of it.

> I have often thought that, given  all our observations of the
> constancy of c were made in the accelerating frames we actually
> inhabit, it seems a bit peculiar to conclude from this that c is
> constant in inertial frames but perhaps not in accelerating frames.

The accelerations involved are so small they are inconsequential. The
math of GR is quite clear: the vacuum speed of light is locally c in any
locally inertial frame (using standard clocks and rulers). In an
accelerated system the speed of light cannot be isotropic, whether
measured one-way or round-trip [#]. But for tiny accelerations the
difference is smaller than tiny, and in practice here on earth,
unmeasurable.

    The relevant scale is c^2/g, and for earth's gravity
    that is about a lightyear.

    [#] One-way measurements have great difficulties with
    clock synchronization.

Tom Roberts
Chalky - 08 Jul 2008 11:31 GMT
> >> I think it is best (that is, to avoid as much confusion as possible)
> >> to consider the speed of light to be constant everywhere.
[quoted text clipped - 21 lines]
> from either of them. Unfortunately, for the earth and sun these
> differences are too small to measure directly,

I note from http://en.wikipedia.org/wiki/Schwarzschild_coordinates
that the Schwartzchild chart does not represent radial distances
accurately. Given this, it is difficult to see how the use of such a
coordinate system can prove the reality of effects which are beyond
the limits of observation.
Tom Roberts - 10 Jul 2008 03:20 GMT
>> In our current best model,
>> General Relativity, there's no question: over a non-local path the
[quoted text clipped - 5 lines]
> that the Schwartzchild chart does not represent radial distances
> accurately.

Of course not! The only usage I made of Schw. coordinates is to specify
that the clock, mirror, and rulers are at rest in them (at least that
was my intent, I see my words do not precisely say that). To compute the
distance from A to B one must, of course, integrate the metric along the
path of the ruler. Etc.

> Given this, it is difficult to see how the use of such a
> coordinate system can prove the reality of effects which are beyond
> the limits of observation.

Look again -- I defined "speed" as the ratio of meter sticks laid along
the path to the elapsed time on a single clock, and that is completely
independent of coordinates (but not independent of how the objects move,
so I mentioned Schw. coordinates to specify how they [don't] move).

> Consider points a  and b in an accelerating
> frame accelerating in the direction a to b, and generated by starting
> the acceleration of a and b at the same point in time, with the same
> separation.
> Observers at both a and b can confirm observationally that clocks on b
> run faster than clocks on a.

Yes. Assuming Minkowski spacetime.

> Now, are you saying that for b,  c is < 1, for the round photon trip
> bab, and for a, c is >1 for the round photon trip aba, so that they
> can also agree on separation?

Yes, as long as one uses meter sticks undergoing Born rigid motion to
measure the distance used in the computation of speed (as in the Schw.
example above -- meter sticks at rest in Schw. spacetime naturally
undergo Born rigid motion).

> And is that difference effective on the
> outward photon trip, the return photon trip, or both?

That is a question without a definite answer, because to answer it one
must synchronize two clocks at different locations. But clocks at a and
b will not remain synchronized! The key point about the Schw. example
and yours is that they are round-trip so one need not synchronize
clocks. One-way speeds are ALWAYS subject to variation depending on how
you happen to synchronize the clocks.

Also, please avoid "photons" in such discussions, as they inherently
introduce quantum issues that are not relevant. Discuss light pulses
instead so one can use the geometrical optics (or in some cases the wave
optics) approximation.

> Now consider an accelerating frame where both a and b start
> accelerating from the same point in spacetime (but in different
> spatial directions). Both will then find observationally that clocks
> on the other are running slower.
> Is c then>or<1 for either / both round trips?

I don't know -- work it out for yourself.

> Finally, and potentially more subversively, since we cannot tell,
> experimentally, whether c is constant in inertial or accelerating
> frames,

This is not true. We CAN tell for round-trip speed. For measurements of
round-trip speed, c is constant in locally-inertial frames occupied by
labs on earth; this has been measured literally zillions of times. Of
course the accuracy and validity of a locally-inertial frame depends on
lots of things, but one can use GR to compute how good this
approximation is, and for such measurements here on earth it is FAR
better than experimental resolutions.

In accelerating frames there is no reason to think the speed of light
would be constant. AFAIK no measurements have been made for systems with
SIGNIFICANT acceleration, except possibly measurements of Shapiro time
delay (but that's a PUN on "acceleration"...).

Tom Roberts
Chalky - 10 Jul 2008 16:40 GMT
> > Finally, and potentially more subversively, since we cannot tell,
> > experimentally, whether c is constant in inertial or accelerating
[quoted text clipped - 3 lines]
> round-trip speed, c is constant in locally-inertial frames occupied by
> labs on earth; this has been measured literally zillions of times.

I don't see how you can describe as 'locally inertial', a frame where
inertial bodies achieve speeds of > 15 feet/sec in less than one
second, if you stop applying force to keep them 'stationary'.

Your argument appears to fly in the face of the general postulate (aka
principle of equivalence)
Tom Roberts - 13 Jul 2008 19:53 GMT
>> For measurements of
>> round-trip speed, c is constant in locally-inertial frames occupied by
[quoted text clipped - 3 lines]
> inertial bodies achieve speeds of > 15 feet/sec in less than one
> second, if you stop applying force to keep them 'stationary'.

Remember that physics is a QUANTITATIVE science. The phrase "locally
inertial" is always an approximation. But in practice, for labs on earth
and for tabletop light-speed measurements (mentioned above), that
approximation is FAR better than the experimental resolutions. As the
apparatus is supported against gravity, one normally analyzes such
experiments in the locally-inertial frame that is initially at rest
relative to the apparatus.

    Exercise for the reader: Consider a lab measurement of the
    round-trip speed of light over a 10 meter path. To estimate
    the error induced by ignoring the acceleration of gravity:
    A) compute the time duration of the round-trip light path
    B) compute how far an object would fall during that time,
       given it is initially at rest (hint: L = 0.5 g t^2).
       This is an overestimate, as there is a better inertial
       frame to use (at rest when the light is in the middle).
    C) now compute the difference between the assumed
       (horizontal) path and the actual path due to that
       distance fallen (hint: neglect the curvature of the path
       and add the vertical fall to the horizontal distance;
       this clearly overestimates the actual path length).
    D) now relate that error in path length to an error in the
       measured speed (hint: fractional errors are the same).
    Compare to a typical experimental resolution of ~0.1 parts
    per billion.

    This is only an (over) ESTIMATE. For real experiments you
    need to look them up and read their error analysis.

> Your argument appears to fly in the face of the general postulate (aka
> principle of equivalence)

No. It merely includes the fact that physics is a quantitative science,
and for this specific physical situation the acceleration due to gravity
is completely negligible.

> Well, I don't trust Born rigid rulers because they are totally
> artificial constructs embodying too many logical contradictions.

Not at all! For a ruler, Born rigid motion means that in a steady state
the atoms of the ruler arrange themselves so that the inter-atomic
distances have their usual values. Yes, this only applies to
accelerations small enough so that the stain is negligible, but that was
included in the original physical situation.

> If you start two separate bodies (or two ends of
> the same body) accelerating at the same rate, at the same time, it is
> obvious that they will both have the same velocity at all subsequent
> times, in that original inertial frame.

This is not Born rigid motion. It is not "rigid" in any sense. Born
rigid motion is such that for every pair of points in the object the
proper distance between them remains constant -- that is normally what
one means by "rigid". But it should be clear that this can only be
applied to "small" objects, where the actual size limit depends on the
acceleration applied and the (in)elastic properties of the object.

To induce Born rigid motion in a solid object, you must either:
    a) attach the acceleration to a single point and let any
       startup transients damp out, making sure the acceleration
       is small enough so strain is negligible.
or:
    b) couple the acceleration to every individual atom, varying
       it appropriately for each atom so the proper distances
       remain constant.

For a steel ruler standing up on the surface of the earth, these
approximations are good enough for most practical purposes.

Tom Roberts
Chalky - 14 Jul 2008 19:19 GMT
> >> For measurements of
> >> round-trip speed, c is constant in locally-inertial frames occupied by
[quoted text clipped - 39 lines]
> and for this specific physical situation the acceleration due to gravity
> is completely negligible.

My original argument was that we can't tell the difference, and you
objected to that. You are now confirming my argument, quantitatively.
Can't you see that?
Chalky - 14 Jul 2008 19:19 GMT
> To induce Born rigid motion in a solid object, you must either:
>      a) attach the acceleration to a single point and let any
>         startup transients damp out, making sure the acceleration
>         is small enough so strain is negligible.

So, what (preferably physical) mechanism are you proposing to 'damp
out' the consequences of such 'startup transients' ?

> or:
>      b) couple the acceleration to every individual atom, varying
>         it appropriately for each atom so the proper distances
>         remain constant.

Ditto
Chalky - 15 Jul 2008 18:38 GMT
> > Well, I don't trust Born rigid rulers because they are totally
> > artificial constructs embodying too many logical contradictions.
>
> Not at all! For a ruler, Born rigid motion means that in a steady state
> the atoms of the ruler arrange themselves so that the inter-atomic
> distances have their usual values.

Which is un-physical. If the rulers are laid out vertically, the force
inducing acceleration transfers through the rulers at the speed of
sound in that material. Consequently, rulers DO stretch if hung from
the ceiling, and compress if stacked up from the floor, when
acceleration is induced.

This would even be the case (but on a smaller scale) for an 'ideal'
ruler where the speed of sound in the material equals the vacuum speed
of light, and the rulers are completely inelastic in every other
sense.

It is pointless arguing that these differences are negligible when the
rulers are short and the g forces small, if you then apply huge
numbers of them stacked end on end to 'prove' that c is not constant
in gravitational fields.
Tom Roberts - 18 Jul 2008 20:32 GMT
>> For a ruler, Born rigid motion means that in a steady state
>> the atoms of the ruler arrange themselves so that the inter-atomic
[quoted text clipped - 5 lines]
> the ceiling, and compress if stacked up from the floor, when
> acceleration is induced.

Sure. But read the very next sentence I wrote, and the entire theme of
that post -- this APPROXIMATION is useful for many applications. How
many carpenters use different rulers for vertical and horizontal
measurements, and adjust the former for altitude?

Experimental physics is always an approximation, not the abstract
discussion you are pursuing. The key is to know which approximations are
useful and which are not. Born rigid motion is useful in many
applications; but not all. Locally inertial frames on earth are accurate
for many physical situations, but not all.

Tom Roberts
Chalky - 21 Jul 2008 18:41 GMT
> How
> many carpenters use different rulers for vertical and horizontal
> measurements, and adjust the former for altitude?

None. You have missed the point. The golden rule of carpentry is
measure twice, cut once. This applies generally when we are "on the
tools". For example, with a spirit level, you turn it round and
measure again, both for vertical and horizontal applications. This is
because experience shows it often makes a difference.
Chalky - 10 Jul 2008 16:40 GMT
> > Consider points a =A0and b in an accelerating
> > frame accelerating in the direction a to b, and generated by starting
[quoted text clipped - 11 lines]
> Yes, as long as one uses meter sticks undergoing Born rigid motion to
> measure the distance used in the computation of speed

Well, I don't trust Born rigid rulers because they are totally
artificial constructs embodying too many logical contradictions.

To be perfectly honest, I can't even understand why they were invented
in the first place. If you start two separate bodies (or two ends of
the same body) accelerating at the same rate, at the same time, it is
obvious that they will both have the same velocity at all subsequent
times, in that original inertial frame.  Consequently, I can see no
reason for postulating that one must accelerate harder than the other,
for their separations to remain constant subsequently. Sure, their
separation in the original inertial frame may become relativistically
shrunk in due course, but that is irrelevant because the lengths of
co-moving rulers would shrink by the same amount.

> > Finally, and potentially more subversively, since we cannot tell,
> > experimentally, whether c is constant in inertial or accelerating
[quoted text clipped - 3 lines]
> round-trip speed, c is constant in locally-inertial frames occupied by
> labs on earth; this has been measured literally zillions of times.

If what you say is true (ignoring your oxymoronic frame definition),
then, via the general postulate (strong principle of equivalence),
that is literally zillions of lab verifications that c is constant in
accelerating frames.
Chalky - 11 Jul 2008 15:01 GMT
> If you start two separate bodies (or two ends of
> the same body) accelerating at the same rate, at the same time, it is
[quoted text clipped - 5 lines]
> shrunk in due course, but that is irrelevant because the lengths of
> co-moving rulers would shrink by the same amount.

On further reflection, this argument of mine is unsound. AFAICT the
separation should remain constant in the original inertial frame.
Consequently, with relativistic shrinking of rulers in the co-moving
frame, the accelerating observer SHOULD see separations increase, if
both accelerations are the same.
Chalky - 09 Jul 2008 07:15 GMT
> >> I think it is best (that is, to avoid as much confusion as possible)
> >> to consider the speed of light to be constant everywhere.
[quoted text clipped - 51 lines]
>
> Tom Roberts

This IS rather confusing. Consider points a  and b in an accelerating
frame accelerating in the direction a to b, and generated by starting
the acceleration of a and b at the same point in time, with the same
separation.

Observers at both a and b can confirm observationally that clocks on b
run faster than clocks on a.

Now, are you saying that for b,  c is < 1, for the round photon trip
bab, and for a, c is >1 for the round photon trip aba, so that they
can also agree on separation?  And is that difference effective on the
outward photon trip, the return photon trip, or both?

Now consider an accelerating frame where both a and b start
accelerating from the same point in spacetime (but in different
spatial directions). Both will then find observationally that clocks
on the other are running slower.

Is c then>or<1 for either / both round trips?

Finally, and potentially more subversively, since we cannot tell,
experimentally, whether c is constant in inertial or accelerating
frames, is not a decision that one is true in preference to the other,
anything more than an irrational (historically predicated)  preference
for brand A over brand B?
Chris H. Fleming - 16 Jun 2008 20:54 GMT
> I have noticed that Einstein stresses in various places that, whereas
> the speed/velocity of light is constant in SR, it is not in GR.
[quoted text clipped - 14 lines]
>
> (pleaseremove spam from address for emailed response)

The speed of light is constant locally... where it matters.

Take the Schwarzschild line element for light ds=0 and solve for dr/
dt. It is not c except at r=inf where the local observers are.

This also happens in SR. Switch to an accelerating frame and do a
similar analysis.

The difference is that in SR there is a global inertial frame which
gives you an unambiguous way to compare speeds across different
locations on the manifold. Whereas in GR there are only local inertial
frames.

There are alternate theories of gravity that have a variable speed of
light (VSL). They are generally hogwash or merely a coordinate
transformation and not physical.
festusbyrne@btinternet.com - 17 Jun 2008 19:33 GMT
> > I have noticed that Einstein stresses in various places that, whereas
> > the speed/velocity of light is constant in SR, it is not in GR.
[quoted text clipped - 33 lines]
>
> - Show quoted text -

So why is the speed of light different is materials?

Does it always seems to be slower according to the refractive index of
the material its passing through?
Igor Khavkine - 17 Jun 2008 23:47 GMT
On Jun 17, 2:33 pm, festusby...@btinternet.com wrote:

> > The speed of light is constant locally... where it matters.

> So why is the speed of light different is materials?
>
> Does it always seems to be slower according to the refractive index of
> the material its passing through?

The speed of light in a material differs from the speed of light in
vacuum. This fact is independent of either special or general
relativity.

Inside a material, light gets scattered. In a sense, microscopically,
it no longer travels in a straight line, but bounces from atom to
atom. Take two pairs of points that are the same distance apart. If
one pair is in vacuum, light can cover the distance between them in a
straight line. If the other pair is inside a material, then light will
have to bounce around while traveling from one point to the other.
Thus, necessarily, it must travel slower in a material than in vacuum.

On a coarser, macroscopic level, the bouncing light waves interfere in
a way that light appears to propagate in straight lines. The only
signature of the microscopic behavior is refraction, a sharp change of
direction of a light ray when crossing the boundary between two
materials of different optical properties.

Hope this helps.

Igor
festusbyrne@btinternet.com - 18 Jun 2008 09:35 GMT
> On Jun 17, 2:33 pm, festusby...@btinternet.com wrote:
>
[quoted text clipped - 25 lines]
>
> Igor

Yes that's very helpful, Thank you.

Also when space-time is said to be curved, does this mean that a spin
of a body is actually causing the curviture in space-time?

If you toss a massive body in flat space-time, will it have a choice
not to be become curved, if there is no rotation?

In other words is curviture in space-time controlled by the presence
of the mass?

Or does the angular momentum of a body contribute to this curviture?

Thanks
Igor Khavkine - 21 Jun 2008 10:59 GMT
On Jun 18, 4:35 am, festusby...@btinternet.com wrote:

> Also when space-time is said to be curved, does this mean that a spin
> of a body is actually causing the curviture in space-time?

Hmm, it's a bit of a jump from light refraction to space-time
curvature. :-) So this is a completely different topic now. The short
answer is Yes, but I'm not sure why your question is specific to spin.

> If you toss a massive body in flat space-time, will it have a choice
> not to be become curved, if there is no rotation?

In the context of general relativity, the presence of matter (of any
kind, including light) induces space-time curvature. This dependence
is expressed as the Einstein equations.

> In other words is curviture in space-time controlled by the presence
> of the mass?

Let me make my last point more explicit. The presence of matter
implies, for any point in space-time, (i) an energy density (including
heat, rest mass, electromagnetic energy, etc.), (ii) a momentum
density (including heat flux, and the electromagnetic Pointing
vector), (iii) pressure and other internal stresses (including shear
stresses). All of these influence space-time curvature.

> Or does the angular momentum of a body contribute to this curviture?

In a rotating extended object, each unit volume of the body (except
possibly directly on the axis of rotation) has a non-zero velocity and
hence a non-zero momentum density. This momentum density falls into
category (ii) above. Therefore, a rotating object will affect
curvature differently than the same object if it is not rotating.

Hope this helps.

Igor
Uncle Al - 23 Jun 2008 21:34 GMT
[snip]

> In a rotating extended object, each unit volume of the body (except
> possibly directly on the axis of rotation) has a non-zero velocity and
> hence a non-zero momentum density. This momentum density falls into
> category (ii) above. Therefore, a rotating object will affect
> curvature differently than the same object if it is not rotating.

There have been many attempts to directly observe spin effects upon
gravitation from lab to cosmic scales - all of them unsuccessful to
date including gyroballs and polarized spin test masses.  Gravity
Probe B was to observe local exceedingly small gravitomagnetic
effects.

There are no observed orbital anomalies associated with 2.15 msec
rotation, 1.74 solar-mass pulsar PSR J1903+0327 in a 95.17-day
0.44-eccentricity orbit with its 1.05 solar-mass companion.  Large
divergences of gravitational binding energy (27% vs. 1.4x10^(-4)%),
strong and weak field (1.8x10^11 vs. ~30 surface gees), composition
(neutrons and exotica vs. protons and electrons); pulsar equatorial
spin greater than 0.11 lightspeed, 2x10^8 gauss magnetic field... are
inert within observational error.

http://arXiv.org/abs/0805.2396

It is a difficult measurement.

Signature

Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/lajos.htm#a2

Phillip Helbig---remove CLOTHES to reply - 18 Jun 2008 07:41 GMT
In article
<be106d44-274f-48a6-bbd4-6aa0a24208d6@e53g2000hsa.googlegroups.com>,
festusbyrne@btinternet.com writes:

> So why is the speed of light different is materials?

This has nothing to do with the issue being discussed, where implicitly
the speed of light in vacuum is what matters.  

> Does it always seems to be slower according to the refractive index of
> the material its passing through?

Yes.

[Moderator's note:  See Igor's post for more details.  -P.H.]
Tom Roberts - 20 Jun 2008 22:54 GMT
> I have noticed that Einstein stresses in various places that, whereas
> the speed/velocity of light is constant in SR, it is not in GR.

The underlying issue is what one means by "speed" in GR. This is nontrivial.

But for the case of the earth orbiting the sun, the difficulties can be
avoided and a definite measurement and analysis can be made, basically
due to the fact that the fields are quite small. So one can construct
background Minkowski coordinates that are valid throughout the region of
interest, and measure speed relative to them.

> It is obvious that the vector must vary since light rays bend in
> gravitational fields.

At the same level of precision in wording, they also slow down. This is
known as the "Shapiro delay", and has been measured accurately for light
passing close to the sun; for known pulsed sources like pulsars,
spacecraft, or round-trip reflections, the delay can usually be measured
much more accurately than the bending.

> However, the situation for the scalar seems rather less clear to me,
> at present.

It has been measured, to sufficient accuracy to solidly demonstrate that
the prediction of GR applies to the world we inhabit. Of course the
effect is quite small, being just a few hundred microseconds for a path
earth->mars->earth that passes close to the sun.

Tom Roberts
Chalky - 23 Jun 2008 23:09 GMT
> > I have noticed that Einstein stresses in various places that, whereas
> > the speed/velocity of light is constant in SR, it is not in GR.
[quoted text clipped - 25 lines]
>
> Tom Roberts

Hmmm....I'm not too sure about this one. If light takes a curved path
around the Sun, it is obvious that it will take longer to travel that
extra distance. However, that doesn't necessarily mean that speed  (dx/
dt) has altered. Can anyone clarify?
Pmb - 23 Jun 2008 21:34 GMT
> I have noticed that Einstein stresses in various places that, whereas
> the speed/velocity of light is constant in SR, it is not in GR.

Its true. When that is said it refers to the coordinate speed of light. It
can't refer to the proper speed of light since there is no such thing when
it comes to light.

> The reason for my current source of confusion here is that Einstein
> wrote in German, where there is no linguistic distinction between
> vector (velocity) and scalar (speed).

A 4-velocity for light cannot be defined.

> Does anyone know of any accelerating (linear or rotating) reference
> frame experiments which unambiguously resolve this question one way or
> the other?

Sure. See http://www.geocities.com/physics_world/gr/c_in_gfield.htm

Pete
jacques - 08 Jul 2008 11:31 GMT
> I have noticed that Einstein stresses in various places that, whereas
> the speed/velocity of light is constant in SR, it is not in GR.
[quoted text clipped - 14 lines]
>
> (pleaseremove spam from address for emailed response)

In GR, along a null geodesic, locally at each point of the geodesic,
in the local tangent space, velocity of the light vector is "c".
Regarding a distant vector in a curved space, for knowing its
magnitude you shoud perform a parallel transport up to your local
space and as the result may depend on the path followed, usually one
says that it's a nonsense to speak about celerity of a distant vector.
One observer may measure the celerity of a speed vector only in his
local space!
Jacques
 
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