Question: A waiter carries a tray full of meals across the room. Is work
being done?
My first response: We can't answer the question yet, because the question is
flawed! Questions about work only make sense when they ask: Does (something)
do work on (some object)? Also, questions only make sense when the motion
is precisely described. So let's restate the question. In fact, let's ask
three different questions.
A. Does the waiter do work on the tray, as he starts from rest and then
reaches some final velocity? YES
B. Does the waiter do work on the tray, as he slows down to a stop? YES
C. Does the waiter do work on the tray, as he moves at constant velocity?
NO. To be more precise, NO NET WORK is done by the waiter on the tray.
But here is what I want to examine: "While moving at a constant velocity,
isn't friction between the waiter and the floor doing work on the waiter?"
I want to say "Yes, the friction force between the waiter and the floor
constantly retards the motion of the waiter (and thus also would retard the
motion of the tray.) The friction force acts over the distance that the
waiter is traveling;
the friction force thus does work on the waiter."
Is this correct to say? Can I say that the friction force effectively doing
work on the waiter's muscles?
I also want to say "However, the waiter constantly uses his muscles to
overcome this friction force, and continue moving forward at constant speed.
The waiter thus does work that is equal to the work of the friction force,
but in the opposite direction."
Can I say that he does work on, or within, his own muscles?
As you can see, I wish to explain something like: The work of A on B is
cancelled out by the work of B on A, hence the NET work on the TRAY comes
out to zero.
But how specifically should I describe this? Is my description ok? I have
the feeling that it is almost correct, but I just want to be as precise in
my wording as possible. (I've seen too many questions that were worded, or
answered vaguely, even in textbooks.)
Robert
> Question: A waiter carries a tray full of meals across the room. Is work
> being done?
http://scienceworld.wolfram.com/physics/Work.html
The tray moved with respect to the room... force was
involved. Do the calculations.... in 3D... include
the raising and lowering... quivering, etc.
> Question: A waiter carries a tray full of meals across the room. Is work
> being done?
[quoted text clipped - 3 lines]
> do work on (some object)? Also, questions only make sense when the motion is
> precisely described.
Or when the unstated conventions are known through experience from other
questions. My first response would be that no work is done on the tray,
since it starts from rest and finishes at rest. The waiter probably does
negative work on the tray since it probably starts off higher than the
table it's delivered to (so the gravitational potential energy of the tray
decreases).
> So let's restate the question. In fact, let's ask three
> different questions.
[quoted text clipped - 6 lines]
> C. Does the waiter do work on the tray, as he moves at constant velocity? NO.
> To be more precise, NO NET WORK is done by the waiter on the tray.
Sure, as far as the horizontal forces are concerned.
> But here is what I want to examine: "While moving at a constant velocity,
> isn't friction between the waiter and the floor doing work on the waiter?"
[quoted text clipped - 14 lines]
>
> Can I say that he does work on, or within, his own muscles?
While the waiter is accelerating, the friction force must be doing work on
the waiter. When stopping, negative work.
What about when the waiter is gliding along at constant velocity like a
sliding block ("let there be a frictionless cube-shaped waiter ...")? One
foot must be pushed forward by the floor. But, on average, the other foot
is being pushed the other way. The work done by these two forces must
cancel. At each foot, the waiter must be doing opposite amounts of work on
the floor. But the pushing-off foot gets that energy from (very
inefficient) muscles, and the landing foot loses much of that energy (some
will be stored in elastic tendons such as the achilles tendon). Result:
not only are the muscles inefficient, but they don't regain much of the
expended energy with each step.
On an individual muscle level (or individual muscle cells if you want to
go to that level), work is being done. Overall, the total work done on the
tray is zero. What about the entire system, tray + Earth? This is the
change in gravitational potential energy.
> As you can see, I wish to explain something like: The work of A on B is
> cancelled out by the work of B on A, hence the NET work on the TRAY comes out
[quoted text clipped - 4 lines]
> wording as possible. (I've seen too many questions that were worded, or
> answered vaguely, even in textbooks.)
Largely, except that the waiter can't do work on himself, so the muscles
can't oppose the work done by friction on the pushing-off foot - this is
opposed by the work on the landing foot.
Almost certainly, you're not intended to go into this much detail, just
give a simple "no". Going into this much detail isn't, in itself, a bad
thing. Positively good even, since it shows you're thinking about it
instead of just memorising the expected response.

Signature
Timo Nieminen - Home page: http://www.physics.uq.edu.au/people/nieminen/
E-prints: http://eprint.uq.edu.au/view/person/Nieminen,_Timo_A..html
Shrine to Spirits: http://www.users.bigpond.com/timo_nieminen/spirits.html
Sam Wormley - 31 Dec 2007 04:59 GMT
> While the waiter is accelerating, the friction force must be doing work
> on the waiter. When stopping, negative work.
:-(
> Question: A waiter carries a tray full of meals across the room. Is work
> being done?
Arms and arm muscles are not cables and pulleys. These tiny muscle
cells are constantly twitching and that uses energy.
Dwib