Natural Science Forum / Physics / General Physics / July 2008

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MIRRORS OF MICHELSON: An analysis materialist

An ANALYSIS MATERIALIST Of a PSEUDO RELATIVISTIC EXPERIMENT
MIRRORS OF MICHELSON

by Yanick Toutain
Saturday July 19, 2008
19/07/08 21:08

LANG=en
ABSTRACT: The einsteinists swindlers off the relativity, frequently,
show you has pseudo-experiment.
They Tel. you again and again: it is the proof off the relativity.
The experiment off Albert Michelson.
With laser two rays with two different travels emitted.
They say that the rays will arrives At the same place.
They will arrives goal, yew there is year anisotropy off space, the
different delays off the different rays will produce interference
rays.
Goal being unaware of Michelson didn' T know the speed off the sun: He
was ignoramus that the sun travelled with has revolution speed: 250 km/
s.
He ignored what Herschel cuts understood: the sun cuts has relative
motion 19.6 off km/s.
Goal being unaware of relativists is unaware of the speed off the
Galaxy: they is unaware of the speed off the Milky Way.
Yew the speed off the Milky Way is 5000 km/s, the rays WILL NOT
ARRIVES AT THE SAME PLACES!

LANG=fr
Two signals are emitted at the same time.
They traverse two ways and meet at the end to form interference
rings.
One sees on the drawing of conclusion the points of impacts of the two
photons:

The green feature clearly figure the difference between the center of
the final target and the place which the photon came to run up
against.
It is seen well that it does not touch the center of the target.

One will see in lower part that
longG = 1,143250689
It is the difference between the point of impact and the center of the
final target. (the sensor)
As for the second photon, it made a longer way and thus, it comes to
impact later, more than one billionth of seconds later, (1.00506E-09
S)
This time is sufficient so that the target moved.
The center of the target is not any more at the same place.
The dark green feature thus appears the difference between the center
of the target (the sensor) (which is on y=2 X=11,42109233)
and the point of impact of the second photon. (X=11,52488335
Y=2,077843261)
It is thus noted that the difference between the two photons, at the
moment when they reach the target is equal to
variation outdistances = 1,086383391 (m)
How two photons (two luminous rays) which reaches two different places
at two different moments could answer waitings, with the claims of
Albert Michelson?
The argument which it is about a description based on a device moving
(fictitiously, for teaching reasons of visibility of graphics) with a
third speed of light does not hold.
If I use the assumption Ain Al Rami and that I suppose that the
displacement of the Sun would be of 1/60° speed of light, I obtain the
following results:
variation time 1,00685E-11 S
variation outdistances 0,226361982 m
They come to impact with 22 centimetres one of the other and with a
variation in the time of a hundredth of billionth of second.
Variations of the points of impact compared to the center of the
target-sensor
longD 0,096945986 m
longG 0,129375748 m
With an absolute velocity of approximately 5000 kilometers a second,
the first photon touches the target on the right, with 9 centimetres
of the center.
and the second, touches the target on the left, with 13 centimetres of
the center.
How do you imagine to obtain interference rings with similar such an
absurd device?
========
Detail
All the graphs are made with an absolute translation of C/3 so that
the details are visible.
FIRST PHOTON
IMPACT HAS

As in point 0,0, a photon (yellow) is emitted.
Its direction forms an angle alpha (36.87 degrees) compared to the
absolute translation of the device. (milked yellow)
To facilitate, it is seen that cosalpha=0.8 and sinalpha=0.6
It moves towards the first mirror.
This one forming an angle of 45 degrees compared to the device, it
thus forms an angle of 36.87+45 degrees compared to the absolute
translation. (cosalphap45 =0.1414 sinalphap45=0.9899)
It will advance during
your = 6,25433E-08 S
{ta=3,41533E-08 S}
For this length of time, the device moves in the vacuum at a speed S
By arbitrary and teaching choice
S = C/3
{S = C/60 One has in this type of hooks the results with a speed of
approximately 5000 kilometers a second. What the author calls the
assumption Ain Al Rami and which must approximate our true speed in
the vacuum}
And thus
S * your = 6,25 m
{S * your = 0,170648464 m}
The device and thus its center made a translation of 6.25 meters
{17 centimetres. }
It is the blue feature.
One refers thus mauve to appear what the way of the photon would have
been in the event of inertia: this mauve way moved during the
displacement of the device.
This mauve way connects the laser place of emission to the center of
the central mirror.
One sees well that the impact did not take place in the center, but at
a distance
longA 5,303300859 m
{longA = 0,144800023 m}
of this center.
The impact takes place with 5.3 meters of the center of the first
mirror.
{14 centimetres}
It is thus starting from this point of shifted impact that it is
necessary to calculate the trajectory of this photon.

IMPACT B

One notices on this drawing that the way of the photon towards the
second mirror is very short.
It only lasts
Tb = 3,47463E-09 S
{Tb = 1,61749E-08 S}
And the photon only traverses
C Tb =1,041666667 m
{C Tb =4,849119724 m}
Indeed, it comes to run up against the second mirror far from the
center of this one
LongB = 3,472222222 m
{longB = 0,037734149 m}
Because during the time of the way since the impact has towards the
impact B, the device (and thus the center of the second mirror has
advanced
S Tb = 0,347222222 m
{S Tb =0,080818662 m}
One sees the dark green feature which represents the difference
between the center of the second mirror and the point of impact.
This feature is directed according to an angle of alpha + 90 degrees
compared to absolute advance.
It is this orientation which justifies the brevity of the second way.
IMPACT D
(The letter C is neutralized in my texts to be strictly reserved for
speed of light)

This third impact of the first photon is thus the final shock on the
target, on the sensor.
It is the latter way which is supposed to form interference rings.
(according to the project of Michelson)
One thus sees the photon reconsidering his steps (in absolute space)
***
It will move (milked yellow downwards)
td = 4,16955E-08 S
{td =3,36933E-08}
and to traverse C td = 12.5 meters
{C td = 10,1010101 m}
But the target traversed
S td = 4,166666667 m
{S td = 0,168350168 m}
The blue feature very clearly represents this projection of the center
of the sensor.
It thus will run up against the sensor against a distance
longD= - 0,138888889
It runs up against the sensor on the left center of this one.
{longD = 0,096945986 Mr.
He runs up, to C/60, the sensor on the right of the center}
This low value strictly depends on the values on S, alpha, I, J, and L
and can thus be much larger in certain provisions., If, for example,
alpha = 53, the variation longD becomes equal to -2.27 Mr.
{0,012 m smaller in this case}
========================
SECOND PHOTON
IMPACT E

The photon which is emitted at the same time as the first will pass
through the first mirror and will cross all the length of the device.
It will run up against a mirror laid out with right angle of its
trajectory. It is the orange feature in dotted line.
Te = 6,8229E-08 S
C you = 20,45454545 m
It crossed more than 20 Mr.
{you = 5,07108E-08 S
C you =15,2027027 m
It crossed more than 15,2 m}
But, during this time, the device will have advanced
S you =6,818181818 m
{S you =0,253378378 m}
It is the blue feature which appears this objective projection of the
device in the vacuum.
The mauve feature represents the distance between the central mirror
and the center of the perpendicular mirror of the impact E.
But the shock does not take place in the center.
The green feature represents the difference between the center of the
mirror E and the point of impact E.
Skirt = 4,090909091 m
{skirts = 0,152027027 m
The curious and open materialist will notice the importance of this
value: 15 centimetres.
In this configuration, the impact takes place with more 15 centimetres
of the center of this mirror.
How much did the mirrors of Michelson measure?
Did they let pass the photons to side?
}
IMPACT F

There still, the photon reconsiders its steps. (milked orange
continuous end)
But it meets the central mirror which made a translation (in blue) of
S tf = 0,20661157 m
{S tf = 0,078957215 m}
He will thus have traversed only
C tf = 0,619834711 m
{C tf =4,737432873 m}
in a time
tf = 2,06755E-09 S
{tf = 1,58024E-08 S}
It thus runs up against the central mirror against a distance from
LongF = 5,96073485 m of its center. (milked green end)
{longF = 0,281996102 m
One sees here still whom the current configuration imposes of the
mirrors broader than 29 centimetres. If not the photons pass to
side! }
IMPACT G

The new orange feature into dotted appears the last section.
Tg = 3,84219E-08 S
longG = 1,143250689 m
heureG = 1,08718E-07 S
C tg = 11,51859504 m
S tg = 3,83953168 m

{tg = 1,75185E-08 S
longG = 0,129375748 m
heureG= 8,40317E-08 S
C tg = 5,251920561 m
S tg = 0,087532009 m
}
The photon runs up against the target against 1.14 meters of the
center of this one.
On the assumption Ain Al Rami, the shock takes place with 13
centimetres on the left.
IMPACT EFG and D
One sees on this image the enormous difference between the
trajectories of two photons (yellow and orange)

The image of detail presented to the beginning proves to us that the
difference between the two photons, at the time of the impacts is
equal to
variation outdistances = 1,086383391 m
{variation outdistances = 0,226361982 m}

*** This absolute return on its steps could let suppose a possible
collision with the photons emitted just afterwards.
The answer is not: for the same reasons that previously, the analysis
materialist makes it possible to understand that the following photons
emitted by the laser will be emitted of a different absolute place.
Calculation on Excel spreadsheet
(the graphs are directly obtained from these calculations and are
drawn by the spreadsheet itself)
TEACHING PRESENTATION (S = C/3)

APPROXIMATE PRESENTATION OF REALITY (S = C/60 (assumption Ain Al
Rami))