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Natural Science Forum / Physics / General Physics / July 2008



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Convergent series for Exponential integral

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Leo - 22 Jul 2008 17:31 GMT
Hi
I need a little help here.
I have a function,

f = exp (i*k*sqrt(x^2+a^2)) / sqrt(x^2+a^2).

I need to integrate this function with respect to x.
As this is an exponential integral, exact integral is not possible.
what could be the convergent series for this?
Leo - 22 Jul 2008 17:33 GMT
i = sqrt (-1) and a, k are constants.
Eric Gisse - 22 Jul 2008 18:06 GMT
> Hi
> I need a little help here.
[quoted text clipped - 5 lines]
> As this is an exponential integral, exact integral is not possible.
> what could be the convergent series for this?

Asking sci.math would be better for this type of thing.

My suggestion is expand f in a power series, then integrate term by
term. I cannot promise convergence though.

However if you want to integrate along (-\infty,\infty) or [0,\infty)
I believe this can be solved exactly using contour integration.
carlip-nospam@physics.ucdavis.edu - 22 Jul 2008 19:24 GMT
> Hi
> I need a little help here.
> I have a function,

>  f = exp (i*k*sqrt(x^2+a^2)) / sqrt(x^2+a^2).

> I need to integrate this function with respect to x.
> As this is an exponential integral, exact integral is not possible.
> what could be the convergent series for this?

Do you need a definite or an indefinite integral?  If you write
x = a sinh u, you'll simplify it; the definite integral from zero
to infinity will be a comnination of Bessel functions.

Steve Carlip
Leo - 23 Jul 2008 06:23 GMT
> Do you need a definite or an indefinite integral?
I need a definite integral

int(f,x,0,1)

> If you write
> x = a sinh u, you'll simplify it; the definite integral from zero
> to infinity will be a comnination of Bessel functions.
could you elaborate?

Leo
carlip-nospam@physics.ucdavis.edu - 24 Jul 2008 01:19 GMT
> > Do you need a definite or an indefinite integral?

> I need a definite integral

> int(f,x,0,1)

That's harder...

> > If you write
> > x = a sinh u, you'll simplify it; the definite integral from zero
> > to infinity will be a comnination of Bessel functions.

> could you elaborate?

Do the change of variables, and you'll get something proportional
to an integral of exp{ika cosh u} du.  The definite integral from
u=0 to infinity is a linear combination of J_0(ka) and Y_0(ka) --
look up the integral representations of the Bessel functions.

Steve Carlip
 
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