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Natural Science Forum / Physics / General Physics / July 2008



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Magnetically Coupled Resonance

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copiousergs@gmail.com - 26 Jul 2008 19:03 GMT
I was reading about magnetically coupled resonance recently, and a
question came to me. How is MCR any different than a radio transmitter
and receiver?
kronecker@yahoo.co.uk - 26 Jul 2008 22:07 GMT
On Jul 27, 6:03 am, copiouse...@gmail.com wrote:
> I was reading about magnetically coupled resonance recently, and a
> question came to me. How is MCR any different than a radio transmitter
> and receiver?

One has just a megnetic field whilst radio waves have an electric
field too.

K
copiousergs@gmail.com - 27 Jul 2008 04:08 GMT
On Jul 26, 4:07 pm, kronec...@yahoo.co.uk wrote:
> On Jul 27, 6:03 am, copiouse...@gmail.com wrote:
>
[quoted text clipped - 6 lines]
>
> K

But if you have an oscillating magnetic field, you have a radio
transmitter. If you have an oscillating electric field, you have a
radio transmitter. Rapidly changing either type of field creates
electromagnetic waves. The typical transmitter uses a rapidly changing
electric field, and MCR uses a magnetic field, but the result is the
same, is it not.

In other words, how is one way better than the other for transferring
energy through space?
hhc314@yahoo.com - 27 Jul 2008 16:07 GMT
On Jul 26, 11:08 pm, copiouse...@gmail.com wrote:
> On Jul 26, 4:07 pm, kronec...@yahoo.co.uk wrote:
>
[quoted text clipped - 18 lines]
> In other words, how is one way better than the other for transferring
> energy through space?

Actually, since you appear to be acquainted with Maxwell, you know
that time variant electric or magnetic fields are idential, since they
both produce what (Dhuh) are known as electromagnetic waves.  Most
people learn this in their first of second year in college, unless
they are majoring in the liberal arts.

I'm still waiting for you to post your explanation of what "MCR" is,
and the basis for your confusion. My guess is that you actually mean
MRI of NMR, and are wondering about why that big magnetic field is
needed.  Right?

Harry C.
copiousergs@gmail.com - 27 Jul 2008 16:42 GMT
On Jul 27, 10:07 am, "hhc...@yahoo.com" <hhc...@yahoo.com> wrote:
> On Jul 26, 11:08 pm, copiouse...@gmail.com wrote:
>
[quoted text clipped - 33 lines]
>
> Harry C.

MCR = Magnetically Coupled Resonance. I was reading about MIT's
experiment powering a light bulb remotely by MCR. And how this could
some day mean "wireless electricity". The first thing that occurred to
me is that this is nothing new, but wasn't sure. It seems to me that
instead of using a rapidly varying an electric field to produce EM
radiation, they are rapidly varying a magnetic field. Like you said,
they are identical, so what's the new thing about MCR?
Darwin123 - 27 Jul 2008 17:35 GMT
On Jul 27, 11:42 am, copiouse...@gmail.com wrote:
> On Jul 27, 10:07 am, "hhc...@yahoo.com" <hhc...@yahoo.com> wrote:
>
[quoted text clipped - 7 lines]
> > > > > question came to me. How is MCR any different than a radio transmitter
> > > > > and receiver?
     I think in MCR the antennae is larger than the house or city
that uses the power.

> > > > One has just a megnetic field whilst radio waves have an electric
> > > > field too.

Radio waves per se exist only under the far field condition. The
Electric and magnetic fields obey the laws of optics only at distances
far from the antennae. Close to and inside the antennae, the electric
and magnetic fields are distinguishable. Although called waves, the
term "wave" is technically correct only at a few qwavelengths from the
antennae with the electric current.

> > > But if you have an oscillating magnetic field, you have a radio
> > > transmitter. If you have an oscillating electric field, you have a
> > > radio transmitter. Rapidly changing either type of field creates
> > > electromagnetic waves.
   Not under the near field condition. Inside a radio antennae, the
electric and magnetic fields are distinguishable. The reason is that
the electric current that generates them is close by the fields.

> MCR = Magnetically Coupled Resonance. I was reading about MIT's
> experiment powering a light bulb remotely by MCR. And how this could
> some day mean "wireless electricity". The first thing that occurred to
> me is that this is nothing new, but wasn't sure.
   I think that Tesla did a lot of experiments in this direction,
somewhere at the turn of the twentieth century. Poor Tesla was way
ahead of his time, and was shamelessly exploited. I suspect MIT is
"rediscovering" his work.
> It seems to me that
> instead of using a rapidly varying an electric field to produce EM
> radiation, they are rapidly varying a magnetic field. Like you said,
> they are identical, so what's the new thing about MCR?
   They are not identical in the near field approximation. Although I
haven't read up on the MIT experiments, I can make an educated guess
based on your description.
    What the MIT people may be doing is using HUGE coils to transmit
the electricity. When I mean huge, I mean the user of the electricity
is near the center of the coil. Under those conditions, the near field
approximation is valid. So the idea may be like this:
    Take a city that now uses electric wires to directly carry power
to the home. Tear out most of the wiring on all the homes. Use some of
the torn out wiring to make a huge circular coil, much larger than the
city. Place the city at dead center to this coil. Transmit an
oscillating electric current through this super large coil. Use
relatively low frequency of oscillation, which ensures that the near
field condition holds. This super huge coil is the transmitter.
     Now, each home has kept a small amount of wire to make a
receiving coil. Orient that receiving coil with the magnetic field of
the transmitting coil. Now the magnetic field will induce a current in
the receiving coil.
    Note there are thousands of receiving coils, and only one
transmitting coil. Also note that the power is not being transmitted
by a true electromagnetic wave. The power is being transmitted through
an oscillating magnetic field, with no measurable electric field. The
difference is the huge coil. Because the receiving coils are near the
center of the huge super coil, the system satisfies the near field
condition.
    I am not sure of the advantage of this over the present system.
In any case, the electric current has to be transmitted though a large
amount of wires. My best guess is that there is less wiring required
for the super coil than for the myriad of subsystems needs to send
electricity to each and every home.
hhc314@yahoo.com - 28 Jul 2008 05:41 GMT
On Jul 27, 11:42 am, copiouse...@gmail.com wrote:
> On Jul 27, 10:07 am, "hhc...@yahoo.com" <hhc...@yahoo.com> wrote:
>
[quoted text clipped - 45 lines]
>
> - Show quoted text -

OK, I belive that I understand respect your explanation which seems to
explain the concept of how my electric toothbrush gets charged when I
sit it on its stand at night.  Realize that this is simply an air
cored transformer and has nothing to do with resonance priciples. A
transformer is simply a tranformer. Its winding are simply coupled
magnetically.

I'm not quite sure of what article you read that was citing an MIT
experiment, but let me share with you the fact that MIT students are
not incapable of a little leg pulling.

There are many reasons why electrical power is not transmitted to
wireless consumers.  Not the least of these reason is that you cannot
control the electromagnetic radiation pattern, only focus it to a
small extent.  Another reason is that you would possibly 'fry the
brains' of anyone who happend to be in the transmission path.  Rather
nasty lawsuits could result.

In his 'declining' years, Tesla proposed such an energy transmission
scheme.  I am not sure if he was insane at that time, or had never
learned the basics of electromagnetic wave radiation.

Harry C.
Darwin123 - 29 Jul 2008 00:23 GMT
On Jul 28, 12:41 am, "hhc...@yahoo.com" <hhc...@yahoo.com> wrote:
> On Jul 27, 11:42 am, copiouse...@gmail.com wrote:
>
[quoted text clipped - 58 lines]
> experiment, but let me share with you the fact that MIT students are
> not incapable of a little leg pulling.
    I didn't look up any article on the wireless transmission of
energy. I was making an educated guess based on copiouse's incomplete
description. He did start out stating he didn't understand what
magnetic coupling was. I was addressing that point of confusion,
rather than the specific point of how to transmit power without wires.
The problem may be one of semantics.
      Under near field conditions, the transmission of
electromagnetic energy isn't properly described by electromagnetic
waves. For example: If an observer is you are very close to a radio
antennae, within less than half a wavelength of the radio wave sent
out by the antennae, the flow of energy can not be described by the
wave equation. Therefore, true radio waves only form at a distance
from that antennae. Therefore, the transmission of energy close to the
antennae shouldn't be referred to as "radio wave transmission." I
think that is this semantic point that confuses him.
     He seems to think that all electromagnetic energy is carried by
"electromagnetic waves." I want primarily to dispel this misconception
before discussion starts as to how serious the proposal is.

> There are many reasons why electrical power is not transmitted to
> wireless consumers.  Not the least of these reason is that you cannot
> control the electromagnetic radiation pattern, only focus it to a
> small extent.
    Ahh, but the energy doesn't have to be carried by
"electromagnetic radiation" if by radiation you mean waves. In fact,
now that I think about it, electromagnetic waves are a lot harder to
control than the electromagnetic field near a current or charge. The
magnetic energy generated by a solenoid coil is concentrated inside
the magnetic field within the solenoid coil. The electromagnetic
energy in a capacitor stays in the electric field of the capacitor.
The radio waves from an antennae travel outward in all directions.
That is why there is an inverse square law in intensity. The radio
waves don't stay in place.
    It makes sense to me that someone may try to utilize ways of
transmitting power that don't depend on true "waves." So I suspect
there may be some truth to his story. If I get this point across,
maybe he can research the idea better.
>Another reason is that you would possibly 'fry the
> brains' of anyone who happend to be in the transmission path.
     If one tried to transmit power with radio waves, this would
probably be true. The reason is that radio waves carry half their
energy in an electric field, and half their energy in a magnetic
field. The electric field interacts with conductors (like our blood)
much stronger than a magnetic field.
   Thus, a high power radio wave would fry the people it passes
through. The electric field would generate an electric current in the
blood, heating the blood, and making it boil.
    However, suppose the energy was carried in a strong magnetic
field without an associated electric field. Consider the giant coil
example that I proposed. This would have a strong magnetic field, no
significant electric field. The people would not fry.
>  Rather
> nasty lawsuits could result.
     If this giant coil is ever built, stay away from any iron nails
left in the city. The magnetic field may interact with ferromagnetic
materials, heating them or even pulling them out of the walls.

> In his 'declining' years, Tesla proposed such an energy transmission
> scheme.  I am not sure if he was insane at that time, or had never
> learned the basics of electromagnetic wave radiation.
      I suspect the latter. Tesla was not a theorist. He was a hands-
on experimentalist. To analyze his experiments, he often used theories
that were valid only under limiting conditions, that coincided with
his experiments.
     I think many of his experiments and devices required "near field
conditions." For example, his Tesla coil isn't really a radio wave
transmitter. It actually transmits electricity over a short distance.
Ever notice, when playing with a Tesla coil, how the ionized gases
follow your finger? That is a capacitive effect. This is a near field
effect, not a far field effect.
   On the other hand, maybe that was sufficient. One doesn't need to
always use the most general theory to get something done. Maybe in his
later years he learned more about radio waves. Or maybe in his later
years he came up with a novel method that used near field conditions
to transmit electric power. Maybe it would work. I don't think we have
the right to call him insane, right or wrong.
  Tesla didn't like Einstein's theory of relativity. He thought it
wasn't really science. That shows how poor a theorist he was. However,
Tesla was a was a real good experimentalist. He may have been better
than Edison. I think that Einstein and Tesla would have been a real
winning combination, if they decided to communicate with each other.
    I don't think Tesla was insane. He had real problems getting
along with people, but he did not hallucinate or delude himself like
certain people on this forum.
Matthew Johnson - 29 Jul 2008 00:59 GMT
[snip]

>I didn't look up any article on the wireless transmission of
>energy. I was making an educated guess based on copiouse's incomplete
[quoted text clipped - 5 lines]
>electromagnetic energy isn't properly described by electromagnetic
>waves.

Speaking of semantics, this looks like a semantic error here. Or it could be a
different kind of error. I'll let you decide;)

I think what you meant to say is something like, "transmission of
electromagnetic energy is usually described in terms of the far-field
approximation to the solution of Maxwell's equations for a radiating dipole
(radiated waves): but since they are far-field, they are not good approximations
for near field condtions".

This would be true. But we are still forced to concede that it is properly
described by "electromagnetic waves", since electromagnetic waves _are_ the
photons, which _are_ the exchange particles that generate the force.

That is, once you take the viewpoint of QED, which is necessary to fully and
accurately describe any interaction of matter and free E-M waves, you find
yourself forced to use electromagnetic waves for everything -- usually in ugly
multi-dimensional integrals of Fourier analysis;)

See, for example, http://en.wikipedia.org/wiki/Photon which says:

Begin quote-----------------------
in theoretical physics, a photon can be considered as a mediator for ANY type of
electromagnetic interactions, including magnetic fields and electrostatic
repulsion between like charges.
End quote---(emphasis mine)-------

> For example: If an observer is you are very close to a radio
>antennae, within less than half a wavelength of the radio wave sent
>out by the antennae, the flow of energy can not be described by the
>wave equation.

The wave equation is used for describing the propagation of E-M waves. But you
seem to have in mind a very special case of it, the homogeneous wave equation
with simple boundary conditions. True, that cannot be used here.

Ultimately, the right thing to use would be not the wave equation, but Maxwell's
equations: then when these in turn imply you can approximate well with the
homogenous wave equation (with simple boundary conditions), you do so.

>Therefore, true radio waves only form at a distance
>from that antennae.

That is, freely propagating radiated waves form only at a distance.

> Therefore, the transmission of energy close to the
>antennae shouldn't be referred to as "radio wave transmission." I
>think that is this semantic point that confuses him.
>      He seems to think that all electromagnetic energy is carried by
>"electromagnetic waves." I want primarily to dispel this misconception
>before discussion starts as to how serious the proposal is.

Perhaps the right way to do this would be to use the term "freely propagating
radiated electromagnetic waves". Yet even this term does not clearly distinguish
between the real physical wave you clearly have in mind from the infinitely many
waves summed up by Fourier analysis to represent any field distribution as
described in:

http://en.wikipedia.org/wiki/Electromagnetic_wave_equation

See especially the subsection titled "Spectral decomposition".

Any solution to Maxwell's equations can be written as an infinite sum or
integral of electromagnetic waves. And Maxwell's equations describe all E-M
phenomena -- even if they sometimes need help via "second quantization".

[snip]
Darwin123 - 29 Jul 2008 21:51 GMT
On Jul 28, 7:59 pm, Matthew Johnson <matthew_mem...@newsguy.org>
wrote:
> In article <d6d5cee7-e1b8-4428-850b-fe3da10d0...@m73g2000hsh.googlegroups.com>,
> Darwin123 says...

> This would be true. But we are still forced to concede that it is properly
> described by "electromagnetic waves", since electromagnetic waves _are_ the
> photons, which _are_ the exchange particles that generate the force.
   Okay, you just made a leap. I was talking in terms of strictly
classical electrodynamics. When you bring in photons, you have to
bring in quantum mechanics. In fact, you have to bring in a little
quantum electrodynamics (QED) theory. Although the same system can be
described in QED theory, it is unnecessary to answer his question.
Power transmission can be described using plain old Maxwell's
equations, with no quantized anything. If you want to go there,
however, you have to look at the concepts of QED closely.

> That is, once you take the viewpoint of QED, which is necessary to fully and
> accurately describe any interaction of matter and free E-M waves, you find
> yourself forced to use electromagnetic waves for everything -- usually in ugly
> multi-dimensional integrals of Fourier analysis;)
      Semi-wrong. The Fourier analysis by itself doesn't necessarily
refer to traveling waves. The confusion is that traveling waves in
classical electromagnetic theory carry half their energy in their
electric fields, and half their energy in magnetic fields. Power
transmission can't always be described in terms of such waves.
   For example, classical electrodynamics accurately describes static
electric fields and static magnetic fields. Static electric fields and
static magnetic fields are not traveling waves. Yet, Maxwell's
equations describes how charges interact with them. If you broaden the
definition of wave, you can include electric and magnetic fields.
   However, I don't think it was this type of wave that Copiouse was
talking about. He was talking about traveling waves. You can't
describe always describe the transmission of power in terms of
traveling waves.
    QED has virtual particles as well as real particles. The real
particles correspond to electromagnetic waves. The real particles
refer to electromagnetic fields under far field conditions. In other
words, real particles correspond to traveling waves. The virtual
particles refer to electromagnetic fields under near field conditions.
The virtual particles correspond closer to most types of power
transmission.
   Therefore, radio waves would correspond to real particles.
Magnetic-field induced-power would correspond to virtual particles, as
would electrical-field induced power. Real particles don't disappear,
they keep going and going. So transmission by radio waves corresponds
to shooting real photons in all directions, most of the power being
lost. In my giant coil example, the virtual photons would be staying
in the area of the coil disappearing before they left the coil.
  Therefore, in the large coil proposal that I talked about the power
can be said to be transmitted by virtual photons. The magnetic field
can be pictured as being caused by a particular type of virtual
photon.
  This is an overly convoluted way to look at it, I admit. However,
you were the one who brought in QED. QED includes virtual photons for
exactly the type of systems we are talking about. However, I prefer to
stay with classical electrodynamics, when I can. In any case,
traveling waves are not the answer to every electrodynamics problem
whether in classical electrodynamics or QED.
   So I still think the issue Copi is talking about is a near field
way to transmit power over large distances. I think a coil inside a
coil approach could do it. Maybe this is what the MIT guys were
talking about.

> See, for example,http://en.wikipedia.org/wiki/Photonwhich says:
>
[quoted text clipped - 44 lines]
>
> [snip]
Matthew Johnson - 30 Jul 2008 01:02 GMT
>On Jul 28, 7:59 pm, Matthew Johnson <matthew_mem...@newsguy.org>
>wrote:
[quoted text clipped - 5 lines]
>> photons, which _are_ the exchange particles that generate the force.
>    Okay, you just made a leap.

Yup.

>I was talking in terms of strictly
>classical electrodynamics.

Which may have been the right thing to do. Then again, it is still remotely
possible that the OP may have heard something about how the electromagnetic
field can be represented as a sea of harmonic oscillators, and have been
confused by that.

>When you bring in photons, you have to
>bring in quantum mechanics. In fact, you have to bring in a little
>quantum electrodynamics (QED) theory. Although the same system can be
>described in QED theory, it is unnecessary to answer his question.
>Power transmission can be described using plain old Maxwell's
>equations, with no quantized anything.

Ah, but this 'description' usually relies on glossing over the interaction of
the E-M field with matter, relying on phenomological results that are all too
often not clearly stated.

Remember that radiating dipole I mentioned? You can find such a derivation of
radiated/traveling waves in oodles of elementary physics books, or in electrical
engineering texts (even at more advanced levels), yet how many of them mention
that these dipoles have no physical existence? They are 19th century models with
no physical reality. Yet we still use them in 20th century texts!

The physical reality is QED.

>If you want to go there,
>however, you have to look at the concepts of QED closely.
[quoted text clipped - 5 lines]
>       Semi-wrong. The Fourier analysis by itself doesn't necessarily
>refer to traveling waves.

I didn't say that it did! I said rather that any electromagnetic field (whether
stationary or varying, and over any arbitrary volume) can be represented as an
infinite sum or Fourier integral (depending on the case) involving infinite
waves -- waves that mathematically look a lot like your "traveling waves".

However, I did not state it clearly, and you are probably right that we do not
need to go there to address the OPs question.

>The confusion is that traveling waves in
>classical electromagnetic theory carry half their energy in their
>electric fields,

When traveling in what medium?? What are you assuming for permittivity and
permeability?

> and half their energy in magnetic fields. Power
>transmission can't always be described in terms of such waves.

True. Then will it help to delineate the cases in which power transmission _can_
be described in terms of such waves?

>For example, classical electrodynamics accurately describes static
>electric fields and static magnetic fields.

And "quasi-static" too, i.e., when the circuit components are small compared to
the highest relevant wavelength, e.g., shortwave frequencies in a shortwave
radio transceiver. But not in a VHF transceiver or modern computer, where we
have to start using fancier techniques, even microwave techniques, such as
S-matrices.

[snip]
Darwin123 - 30 Jul 2008 17:29 GMT
On Jul 29, 8:02 pm, Matthew Johnson <matthew_mem...@newsguy.org>
wrote:
> In article <95c14cc4-6808-4057-b6b5-d3eb927dc...@t54g2000hsg.googlegroups.com>,
> Darwin123 says...
[quoted text clipped - 15 lines]
>
> Which may have been the right thing to do. Then again, it is still >remotely possible that the OP may have heard something about how >the electromagnetic field can be represented as a sea of harmonic oscillators, and have been confused by that.
    I didn't get that. However, you may be right. I was answering the
question according to my interpretation of his question. I hope he
makes a comment on our discussion, and tells us if there is anything
in the thread that has enlightened him. His question has stimulated an
interesting thread.

> >When you bring in photons, you have to
> >bring in quantum mechanics. In fact, you have to bring in a little
[quoted text clipped - 39 lines]
> When traveling in what medium?? What are you assuming for permittivity and
> permeability?
    I am assuming that both permittivity and permeability are
entirely real quantities, with no imaginary components. The most
important examples are the vacuum and the lower atmosphere of earth.
Almost material with zero conductivity, which is neither ferromagnetic
or ferrimagnetic, would support electromagnetic waves that have the
following properties:
1) Half the energy is in the magnetic field and half in the electric
field.
2) The electric field, the magnetic field, and the wave vector are all
orthogonal to each other. This type of polarization is called
transverse. The are planar polarization modes and circular
polarization modes, both of which are types of transverse
polarization.
     Of course, there are many materials that don't obey those
conditions. There is a big topic of metal optics. Light waves can pass
through thin layers of metal, and on the surface of metals. While they
are in the metal, the electric field is suppressed more than the
magnetic field. There is a longitudinal polarization mode in a metal.

> > and half their energy in magnetic fields. Power
> >transmission can't always be described in terms of such waves.
>
> True. Then will it help to delineate the cases in which power transmission _can_
> be described in terms of such waves?
    Not for the original question.
    Maybe I am misrepresenting him, but I think I see where he is
confused. Maybe I merely remember my own confusion when taking these
courses, and have projected on him.
     Copi knows that radio waves carry power. He mentioned them.
Therefore, he doesn't need more examples of how electromagnetic
radiation carries power. He refers to electromagnetic waves having
BOTH electric fields and magnetic fields. He is 100% right. In fact,
traveling waves in air and vacuum carry half their energy in their
magnetic fields and half in electric fields.
    His question can be rephrased: How on earth can anyone transmit
power through the air by means of purely magnetic coupling? What
happened to the electric field? I was trying to offer a conjecture on
how it can be done.

> >For example, classical electrodynamics accurately describes static
> >electric fields and static magnetic fields.
[quoted text clipped - 4 lines]
> have to start using fancier techniques, even microwave techniques, such as
> S-matrices.
  Yes, exactly. The near field condition includes electric and
magnetic fields that are oscillating very slowly. However, I think the
multipole expansion is the easiest way to introduce classical
electromagnetic theory. That is how it is done in "Classical
Electrodynamics" by J. D. Jackson. The generalization is a little
heavy for beginners. It is easier to refer to static electric and
static magnetic fields, which many people have direct experience of.
Darwin123 - 30 Jul 2008 20:43 GMT
> >On Jul 28, 7:59 pm, Matthew Johnson <matthew_mem...@newsguy.org>
> >wrote:
> >>In article <d6d5cee7-e1b8-4428-850b-fe3da10d0...@m73g2000hsh.googlegroups.com>,

> Remember that radiating dipole I mentioned? You can find such a derivation of
> radiated/traveling waves in oodles of elementary physics books, or in electrical
> engineering texts (even at more advanced levels), yet how many of them mention
> that these dipoles have no physical existence?
   Yes, these dipoles have physical existence. To study them in
detail, one has to look on a smaller distance scale where one has to
use quantum physics. However, on size scales larger than the molecule
these dipoles are real.
   Remember, the nineteenth century physicists didn't have a
description of molecules on a subatomic level. They didn't even know
what force keeps the dipole from imploding. They knew they didn't know
what held electrical particles together. However, they did know that
on a gross scale of space and time the molecules acted like dipoles,
quadropoles, etc. So that analysis is still useful today.
  I used to work in the field of picosecond spectroscopy. I have
measured the lifetime of an induced dipole. Most of the dipole
components are well modeled by the molecule physically turning. The
molecular dipoles of the molecules really line up. Classical equations
are sufficient to model how they snap back to their original
equilibrium. There is a very short femtosecond component which is
caused by the electrons being moved. Accurate modeling of the
femtosecond component requires quantum mechanics. However,
phenomenological models based on classical physics have been developed
that help model the data.
   The dipoles in classical electrodynamics, such as described by
Jackson, are real. Saying their unreal sounds like something Spaceman
would make up.

>They are 19th century models with
> no physical reality.
   Depends on what you call "physical reality." They used parameters
that at the time were phenomenological. The phenomenological
parameters have a pretty clear classical interpretation. However, we
can now sometimes make an a priori calculation of these parameters
using quantum mechanics. Maybe what you mean is that the a priori
model is more "physically real" than the phenomenological parameters.
Maybe.
     I am a hierarchal reductionist. I prefer to say that the
phenomenological description is physically real on a molecular scale
of time and space. The quantum mechanical model is physically real on
a subatomic scale. The different models are "physically real" on
different levels of reality.
>Yet we still use them in 20th century texts!
   Yes, I find 20th century texts useful. Actually, I occasionally
find 19th century texts useful. Rarely, but it is true. The earlier
scientist understood some things less than we do. However, they had to
think through some details that are taken for granted today. Look how
you and Copi had so much trouble figuring out what "magnetic resonance
coupling" means. I'll bet Maxwell would have figured it out 1-2-3!
Darwin123 - 27 Jul 2008 17:08 GMT
On Jul 26, 11:08 pm, copiouse...@gmail.com wrote:
> On Jul 26, 4:07 pm, kronec...@yahoo.co.uk wrote:
>
> > On Jul 27, 6:03 am, copiouse...@gmail.com wrote:

> In other words, how is one way better than the other for transferring
> energy through space?
   Over large distances, they are the same. An electromagnetic wave
can travel huge distances from an electric charge or magnet. However,
the electromagnetic wave has both electric and magnetic fields
associated with it, as measured in all inertial frames. There is no
way to separately analyze the electric and magnetic field.
  Look up "near field approximation" and "far field approximation."
These are two limiting cases of Maxwell's equations. Electromagnetic
waves per se can only be described in the far field approximation. In
the near field approximation, one has to analyze electric and magnetic
fields separately. Electric and magnetic fields don't couple with each
other at short distances from the electric charges and currents that
cause them.
  However, over short distances there is a difference between
electric and magnetic fields. If one is looking at an electric charge
in the inertial frame of that electric charge, one finds an electric
field associated with that magnetic charge. However, if one is looking
at an electric charge in an inertial frame where the electric charge
is moving very fast, the electric charge starts to behave like an
electric current. So there is a large magnetic field associated with
the electric charge.
  So I think that magnetic coupled resonance is associated with small
distances. If you have two sets of moving charges very close to each
other, the sets couple. Of course both the electric and magnetic
fields contribute to the coupling. The question is which field causes
the most coupling. If the charges are rotating, the coupling is
probably more magnetic than electric.
  In a transformer, for instance, two coils of wire are practically
on top of each other. The laws of optics are not strictly applicable
to describing the operation of a transformer because of the proximity
of the coils. Each coil contains both positive and negative charges,
but the charges in each coil are moving in circles. So the magnetic
field couples the two coils. I am sure that microscopically the
electric field contributes. However, in the inertial frame of the
transformer there are equal amounts of positive an negative electric
charges. So the effect of the electric field is negligible.
   If the two sets of charges are far away from each other, it makes
no sense to ask which field is causing the coupling. What causes the
coupling is the electromagnetic waves, which contain both electric and
magnetic fields. Although one can use Maxwell's equations directly, it
is easier to use the laws of optics which are mostly based on the far
field approximation.
   I think this issue of "far field" and "near field" has confused
many a novice scientist. Optics are a limiting case of Maxwell's
equations in the far field approximation. The simplest expressions for
the laws of induction are limiting cases of Maxwell's equations in the
near field approximation. The problem is that most introductory
problems are best solved in either one limiting case of the other. The
continuity of the physics is sometimes missed in these introductory
problems.
hhc314@yahoo.com - 27 Jul 2008 04:34 GMT
On Jul 26, 2:03 pm, copiouse...@gmail.com wrote:
> I was reading about magnetically coupled resonance recently, and a
> question came to me. How is MCR any different than a radio transmitter
> and receiver?

Please clarify exactly what you mean by MCR.  Google only recogonize
the term as a rock group.

Are you perhaps asking about MRI  (Magnetic Resonance Imaging) or
Nuclear Magnetic Resonance (NMR)?

Harry C,
Edward Green - 30 Jul 2008 04:00 GMT
On Jul 26, 2:03 pm, copiouse...@gmail.com wrote:
> I was reading about magnetically coupled resonance recently, and a
> question came to me. How is MCR any different than a radio transmitter
> and receiver?

You've received a number of relevant responses, but none of them seem
actually to be familiar with the work at MIT!  I'm vaguely familiar
with it, but before I post some links, here are some gleanings,
thoughts and personal misconceptions of mine. ;-)

(1) "near field" is certainly a phrase of power here, as several have
noted
(2) several have also noted the possible relation of the magnetic
transformer, which is certainly a near field device, but I think that
is not the complete story
(3) the technology involved is (I think advertised by the inventors) a
close relative of that used in "RFID".  These are the ID cards (or
labels) which, by means of an internal antenna and a chip, manage to
transmit back a response to "readers".  They are definitely a near
field technology.

An interesting thing about RFID devices is that they are powered by
the incident field: their electronics wakes up long enough to send the
response signal -- or at least modify the reflected signal, whichever
description is more appropriate.  And, I think they involve some role
for resonance -- not just any incident frequency properly excites
them.  I think the MIT work essentially uses larger versions of these,
and a near field, largely magnetic, which couples with appropriate
devices over the space of a room, say.

This technology is going to be very popular with the scared of EM
radiation crowd.  Only MIT geeks are going to want to work in an
environment saturated with enough potential EM power to heat toasters,
whatever the engineers assurance that it can't couple to our bodies.
Right!

Anyway, here are the promised links, to refine and illuminate:

http://web.mit.edu/newsoffice/2007/wireless-0607.html

http://www.sciencemag.org/cgi/content/full/317/5834/83

That will do for now.  I may even read them myself. :-)
Matthew Johnson - 30 Jul 2008 04:25 GMT
[snip]

>This technology is going to be very popular with the scared of EM
>radiation crowd.

Until they figure out that it is just as risky!

After all: if they could so easily ignore all the evidence that E-M radiation
(of the relevant frequencies) does not affect our bodies, they could just as
easily ignore the more slender evidence that such magnetic fields do not affect
our bodies.

Also, the latter effect has been much less studied: only in MRI machines do
humans regularly get exposed to such high magnetic fields. But that, of course,
is only for a short time. Yet if this method of powering devices becomes
widespread, high exposure will become much more common and lengthy.
Edward Green - 30 Jul 2008 17:41 GMT
On Jul 29, 11:25 pm, Matthew Johnson <matthew_mem...@newsguy.org>
wrote:
> In article <982fa9f8-cfe9-4543-90b8-008c63dcb...@w7g2000hsa.googlegroups.com>,
> Edward Green says...
[quoted text clipped - 5 lines]
>
> Until they figure out that it is just as risky!

Ahem.  That was a highly ironical statement.

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