Imagine a very long, low friction surface, in outer space, i.e.
gravityless.
You press a steel ball against this table, and start it rolling. You
then
release the ball and table.
Does the ball continue to roll along the surface?
--
Rich
> Imagine a very long, low friction surface, in outer space, i.e.
> gravityless.
[quoted text clipped - 3 lines]
>
> Does the ball continue to roll along the surface?
Low friction... means there is friction which implies that the
surface is not perfectly smooth... and no force to hold the ball
to the surface.
Conservation laws apply.
Y.Porat - 30 Aug 2008 08:35 GMT
> > Imagine a very long, low friction surface, in outer space, i.e.
> > gravityless.
[quoted text clipped - 9 lines]
>
> Conservation laws apply.
---------------------
since you pressed it to the surface
it will not stay attached to the surface
it will .... surprise ......
roll but .......
will move (rolling) but further and further away from the
surface !!!
think about an elastic rubber or tennis ball
you see
the other guys know abstract rules
but they dont notice the 'little details ' .....(as well)
sometimes the devil is in some little details .....
ATB
Y.Porat
-------------------------------------
> Imagine a very long, low friction surface, in outer space, i.e.
> gravityless.
[quoted text clipped - 3 lines]
>
> Does the ball continue to roll along the surface?
Momentum is conserved. Angular momentum is conserved.
What would kick in to change its rolling?
> --
> Rich
In sci.physics, RichD
<r_delaney2001@yahoo.com>
wrote
on Fri, 29 Aug 2008 21:16:05 -0700 (PDT)
<c681255b-a8a9-42a1-ae9e-247617ff4cf5@e53g2000hsa.googlegroups.com>:
> Imagine a very long, low friction surface, in outer space, i.e.
> gravityless.
[quoted text clipped - 6 lines]
> --
> Rich
Yes, the ball continues to "roll" along the surface. Since it is
low friction both angular and linear momentum are conserved.
In real life the ball will probably deviate from the table unless
additional forces (e.g., magnetic) are involved, as no one can
get the vectors exactly right, but it would continue to spin.

Signature
#191, ewill3@earthlink.net
Useless C++ Programming Idea #12995733:
bool f(bool g, bool h) { if(g) h = true; else h = false; return h;}
** Posted from http://www.teranews.com **
Benj - 30 Aug 2008 20:19 GMT
On Aug 30, 2:35 pm, The Ghost In The Machine
<ew...@sirius.tg00suus7038.net> wrote:
> Yes, the ball continues to "roll" along the surface. Since it is
> low friction both angular and linear momentum are conserved.
>
> In real life the ball will probably deviate from the table unless
> additional forces (e.g., magnetic) are involved, as no one can
> get the vectors exactly right, but it would continue to spin.
Correct. probably depends on how precise the ball and ramp are
constructed. You would have gravitation and Van der Waals forces
holding the ball to the track but as these are very weak, the track
would have to be absolutely flat and the ball absolutely round so as
not to bounce the ball off the track as it continued forward and
continued to turn.
Y.Porat - 31 Aug 2008 04:01 GMT
> On Aug 30, 2:35 pm, The Ghost In The Machine
>
[quoted text clipped - 12 lines]
> not to bounce the ball off the track as it continued forward and
> continued to turn.
----------------
it will certainly bounce of the track!
because it was ** pressed to it ** at the beginning to the track
dont you know that
even a steel ball has some elasticity ??
or you need first to be a structural engineer ?? (:-)
ATB
Y.Porat
--------------------------------
RichD - 31 Aug 2008 00:18 GMT
On Aug 30, The Ghost In The Machine <ew...@sirius.tg00suus7038.net>
wrote:
> > Imagine a very long, low friction surface, in outer space, i.e.
> > gravityless. You press a steel ball against this table, and start
[quoted text clipped - 8 lines]
> additional forces (e.g., magnetic) are involved, as no one can
> get the vectors exactly right, but it would continue to spin.
That's part of the motivation for the question...
on earth, there is gravity, constantly pressing
the ball and track together. When that force
disappears, does 'rolling' make sense? And
what if the surface is frictionless?
In the example, there would be gravitational
attraction between ball and table, and surface
imperfections opposing that, so it's tricky.
Also, one must press the objects together
initially, to start the roll; when they are
released, there is decompression as they
spring back to shape. So it seems they
would separate immediately.
--
Rich