Home | Contact Us | FAQ | Search & Site Map | Link to Us
Sign In | Join | Other 45 Sites in Network
Home
Discussion Groups
Biology
BiologyBotanyMicrobiologyEntomologyEvolutionPaleontology
Chemistry
General ChemistryAnalytical ChemistryElectrochemistryOrganic Synthesis
Earth Science
GeologyMineralogyOceanographyMeteorologyEarthquakes
Physics
General PhysicsResearchRelativityParticle PhysicsElectromagnetismFusionOpticsAcousticsNew Theories

Natural Science Forum / Physics / General Physics / November 2008



Tip: Looking for answers? Try searching our database.

Gravity and mass-energy equivalence

Thread view: 
Enable EMail Alerts  Start New Thread
Thread rating: 
mike3 - 21 Nov 2008 21:10 GMT
Hi.

According to Einstein's theories of relativity, mass and energy are
equivalent. So when you add energy, you also add mass, and vice versa.
This would imply that a spring compressed is slightly heavier than one
not compressed, for example (although too small to measure).

I'd also assume this would apply to gravity. As two objects approach
under gravity, their potential energy decreases -- but would not that
also correspond to a decrease in mass? For example, isn't the Earth
slightly lighter than it would be if it was a strew of asteroids? So
as objects fall together under gravity, mass is converted to energy,
right? Therefore as a planet accretes, it heats up due to some of the
mass being turned into energy.

Now, what about with a Black Hole? Suppose we drop something into a
Black Hole. It loses gravitational potential energy as it falls down
the hole. But given the hole is (at least according to relativity --
whether or not a "true singularity" _really_ exists is likely
something that will only be known once we have a quantum theory of
gravity), an infinitely deep gravity well, should not a point be
reached where _all_ the mass turns to energy? If so, then what happens
to the object? Does it just poof, quit existing? Become a weird
massless blob? If that's so, then wouldn't the grav. force then drop
to zero? Does this mean the inside of a BH is nothing but pure energy?
Sam Wormley - 21 Nov 2008 21:25 GMT
> Hi.
>
[quoted text clipped - 21 lines]
> massless blob? If that's so, then wouldn't the grav. force then drop
> to zero? Does this mean the inside of a BH is nothing but pure energy?

  The mass-energy of what falls into the black hole is added to the
  mass-energy of the black hole. What happens on the inside of the
  event horizon is not observable to someone on the outside.

  One expects the tidal forces increase without limit as "whatever"
  falls toward a singularity into the future.
john211108 - 21 Nov 2008 22:16 GMT
> > Hi.
>
[quoted text clipped - 28 lines]
>    One expects the tidal forces increase without limit as "whatever"
>    falls toward a singularity into the future.

Alice in Wonderland
Sam Wormley - 21 Nov 2008 23:59 GMT
>>> Hi.
>>> According to Einstein's theories of relativity, mass and energy are
[quoted text clipped - 26 lines]
>
> Alice in Wonderland

  Except once you go down the rabbit hole of a black hole, you ain't
  coming back. Welcome to the reality of the universe, John. It was
  never the way you wanted it to be.
G=EMC^2 Glazier - 22 Nov 2008 17:50 GMT
Sam My equation says it all TreBert
carlip-nospam@physics.ucdavis.edu - 22 Nov 2008 01:30 GMT
> Hi.

> According to Einstein's theories of relativity, mass and energy are
> equivalent. So when you add energy, you also add mass, and vice versa.
> This would imply that a spring compressed is slightly heavier than one
> not compressed, for example (although too small to measure).

Right.  While that particular case is too small to measure (yet), we
can actually measure that, for example, the kinetic energy of the
electrons in an atom contributes to the mass.

> I'd also assume this would apply to gravity. As two objects approach
> under gravity, their potential energy decreases -- but would not that
> also correspond to a decrease in mass? For example, isn't the Earth
> slightly lighter than it would be if it was a strew of asteroids?

Right.  This is also measurable, by comparing the orbits of the Earth
and the Moon.  As a proportion of total mass, the gravitational binding
energy of the Earth is slightly different from that of the Moon.  If the
gravitational mass didn't decrease as you describe, the Earth and Moon
would fall toward the Sun with slightly different accelerations (the
"Nordtvedt effect"), which would be observable with Lunar laser ranging.  
You might want to get a copy of Cliff Will's nontechnical paperback
book _Was Einstein Right?_, which has a nice chapter on this.

> So
> as objects fall together under gravity, mass is converted to energy,
> right? Therefore as a planet accretes, it heats up due to some of the
> mass being turned into energy.

This is something a bit different.  As objects fall together, total energy
remains constant -- (positive) kinetic energy increases, while (negative)
potential energy becomes more negative.  If you're looking at the mass,
or energy, of a system of two objects falling towards each other, it will
remain very nearly constant ("very nearly" because a tiny bit of energy
will be radiated away in electromagnetic and gravitational energy).

When the two objects collide, the kinetic energy will be converted into
other forms of energy, mostly heat.  As this energy is radiated off into
space, the remaining mass and energy will decrease, and you will end
up with slightly less mass.  But it's not as simple as "mass converted
to energy."

> Now, what about with a Black Hole? Suppose we drop something into a
> Black Hole. It loses gravitational potential energy as it falls down
[quoted text clipped - 3 lines]
> gravity), an infinitely deep gravity well, should not a point be
> reached where _all_ the mass turns to energy?  

As an object falls toward a black hole, some of its mass is converted to
energy.  The maximum efficiency is about 29% -- pretty high, but not 100%.
Note that the picture of a black hoke as an "infinitely deep gravitational
well" is misleading -- what's relevant is only the gravitational field
outside the horizon, since nothing inside the horizon can get out.

Steve Carlip
mike3 - 22 Nov 2008 05:24 GMT
On Nov 21, 6:30 pm, carlip-nos...@physics.ucdavis.edu wrote:
> > Hi.
> > According to Einstein's theories of relativity, mass and energy are
[quoted text clipped - 53 lines]
>
> Steve Carlip

Thanks for the explanation.
Uncle Al - 22 Nov 2008 01:36 GMT
> Hi.
>
> According to Einstein's theories of relativity, mass and energy are
> equivalent. So when you add energy, you also add mass, and vice versa.
> This would imply that a spring compressed is slightly heavier than one
> not compressed, for example (although too small to measure).

Education is hopeless.

> I'd also assume this would apply to gravity. As two objects approach
> under gravity, their potential energy decreases -- but would not that
> also correspond to a decrease in mass?

Kinetic energy.  If you want a decrease in mass you need gravitational
binding energy.  Yer friendly neighborhood neutron star is missing
about 15% of its unbound total baryon mass.

Potential energy is a particularly slippery concept re potential vs.
what?

> For example, isn't the Earth
> slightly lighter than it would be if it was a strew of asteroids? So
[quoted text clipped - 12 lines]
> massless blob? If that's so, then wouldn't the grav. force then drop
> to zero? Does this mean the inside of a BH is nothing but pure energy?

Gravitation is an efficient engine to convert rest mass to energy -
better than 30% during event horizon infall.  Now tell us how long it
takes an external bowling ball to pass through the event horizon - and
how much energy ends up kinetic rather than radiated.

Put the bowing ball at the end of a carbon nanotube cable and lower it
in.  If it passes through the event horizon, can you pull it back
out?  Feel free to use a galactic core black hole so event horizon
local curvature asymototes toward zero.

Signature

Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/lajos.htm#a2

Y.Porat - 22 Nov 2008 12:49 GMT
> > Hi.
>
[quoted text clipped - 46 lines]
> Uncle Alhttp://www.mazepath.com/uncleal/
>  (Toxic URL! Unsafe for children and most mammals)http://www.mazepath.com/uncleal/lajos.htm#a2

--------------------
idiot farter

gravitation has nothing to do with
parrots
nor with 'curvature of space'
2
while you  talk         about
'potential energy of gravity'
you have to take in account ALL ! the
involved components in it
and that is surely far beyond you poor
parroting ability!!
Y.P
--------------------------------

--------------------------
BURT - 22 Nov 2008 21:04 GMT
> > > Hi.
>
[quoted text clipped - 66 lines]
>
> - Show quoted text -

Round geometry

space motion decelerates outward motion of mass then accelerates mass
toward its center. if mass resists space motion creates weight. Space
motion affects time then time affects light.

Mitch Raemsch
 
Sign In
Join
My Latest Posts
My Monitored Threads
My Blog
My Photo Gallery
My Profile
My Homepage

Start New Thread
Enable EMail Alerts
Rate this Thread



©2009 Advenet LLC   Privacy Policy - Terms of Use
This website includes both content owned or controlled by Advenet as well as content owned or controlled by third parties.