Light speed in emission theory
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kanuk - 27 Apr 2007 22:29 GMT I am a stupid guy, who does not know the answer to this problem: A body (observer) moves in a stationary frame with speed v<c. It sends a light signal travelling with speed c+v (parallel with v). What will be the speed of the signal after reflection on a stationary mirror (which is perpendicular to v). Thanks to anybody who would answer.
karandash2000@yahoo.com - 27 Apr 2007 22:50 GMT > I am a stupid guy, Yes.
kanuk - 27 Apr 2007 23:01 GMT >> I am a stupid guy, > > Yes. (|)
Sue... - 27 Apr 2007 23:00 GMT > I am a stupid guy, who does not know the answer to this problem: A body > (observer) moves in a stationary frame with speed v<c. It sends a light > signal travelling with speed c+v (parallel with v). What will be the speed > of the signal after reflection on a stationary mirror (which is > perpendicular to v). > Thanks to anybody who would answer. For a macroatomic path, light moves at c wrt to the dielectric of free-space regardless of the motion of the emitter.
Propagation in a dielectric medium http://farside.ph.utexas.edu/teaching/em/lectures/node98.html http://en.wikipedia.org/wiki/Wave_impedance http://en.wikipedia.org/wiki/Free_space http://www-ssg.sr.unh.edu/ism/what.html
Sue...
kanuk - 27 Apr 2007 23:32 GMT >> I am a stupid guy, who does not know the answer to this problem: A body >> (observer) moves in a stationary frame with speed v<c. It sends a light [quoted text clipped - 15 lines] > > Sue... Well, some misunderstanding. I am well aware, that the majority of contemporary physicists accepts the theory of the constant light speed, which I would also prefer. I just would like to know "if".
Androcles - 28 Apr 2007 00:49 GMT >>> I am a stupid guy, who does not know the answer to this problem: A body >>> (observer) moves in a stationary frame with speed v<c. It sends a light [quoted text clipped - 19 lines] > contemporary physicists accepts the theory of the constant light speed, > which I would also prefer. I just would like to know "if". Nature doesn't care about your preferences, or Sue's for that matter.
Sue... - 28 Apr 2007 02:15 GMT > >> I am a stupid guy, who does not know the answer to this problem: A body > >> (observer) moves in a stationary frame with speed v<c. It sends a light [quoted text clipped - 19 lines] > contemporary physicists accepts the theory of the constant light speed, > which I would also prefer. I just would like to know "if". If it is a conductive mirror, it propagates at c. If it is a dielectric mirror is moves at less than c when the mirror thickness is a significant fraction of the path.
Sue...
Henri Wilson - 29 Apr 2007 00:43 GMT >> I am a stupid guy, who does not know the answer to this problem: A body >> (observer) moves in a stationary frame with speed v<c. It sends a light [quoted text clipped - 6 lines] >dielectric of free-space regardless of the motion of the >emitter. I take it you mean 'light speed moves at c wrt the emitter in accordance with the dielectric of free space as measured in the emitter's frame'.
Don't argue because nobody has ever measured the OW speed of EM in anything BUT the emitter's frame.
>Propagation in a dielectric medium >http://farside.ph.utexas.edu/teaching/em/lectures/node98.html >http://en.wikipedia.org/wiki/Wave_impedance >http://en.wikipedia.org/wiki/Free_space >http://www-ssg.sr.unh.edu/ism/what.html These tell us nothing...
>Sue... www.users.bigpond.com/hewn/index.htm
Einstein's Relativity - the greatest HOAX since jesus christ's virgin mother.
Androcles - 28 Apr 2007 00:49 GMT >I am a stupid guy, who does not know the answer to this problem: A body > (observer) moves in a stationary frame with speed v<c. Huh? A "stationary" frame has speed v? I can see you are confused, reduce the problem to real world terms. We don't need observers, bodies or frames. I'll translate into plain English for you and assume you mean 'c' is the speed of light, but I will use *some* technical terms. Here goes:
Translation: A motorcyclist careens along a road with velocity v which is also speed v but has direction as well. He is not going backwards, sideways or looping the loop. He is unidirectional, not omnidirectional. (I mention that because light from the sun is omnidirectional, meaning it goes in all directions.)
> It sends a light > signal travelling with speed c+v (parallel with v). Translation: He turns on his headlight, it's getting dark, the sun has gone down. The light leaves the lamp at velocity +c relative to the lamp, v+c relative to the road, and we are only concerned with its unidirectional velocity parallel with v.
> What will be the speed > of the signal after reflection on a stationary mirror (which is > perpendicular to v). Translation: The light hits a reflective traffic sign that shows arrows like this ">>>>" -- meaning "Slow up, bend ahead" (or "Slow down, bend ahead", depending the cliche you prefer). How fast does the light come back to the rider's eye so that he can read the sign that he picked out in his headlight beam and react to it?
Answer: It comes back at '-c' with respect to the motorcycle and 'v-c' with respect to the road. Check with Doppler radar for verification. http://www.androcles01.pwp.blueyonder.co.uk/AC/doppler.gif
> Thanks to anybody who would answer. Do not listen to idiots. Figure out for yourself who they are, shun them. Here are a few to start you off. Tom Roberts. (Humpty Roberts) Timo Neiminen. (The nonwizard of Oz) Paul Draper. (Phuckwit Duck) "Uncle" Al Schwartz. (Uncle Stooopid) Randy Poe. (Blind Poe) Ghost in the Machine. (General Idiot) Albert Einstein, relativist. John Baez, relativist. James Clerk Maxwell, aetherialist. A host of lesser phuckwits.
Those you should listen to (not so many of these) are: Nicholas Copernicus. Galileo Galilei. Sir Isaac Newton. Johannes Kepler. Christian Andreas Doppler. Albert Michelson. Georges Sagnac.
Perhaps Georges Sagnac does the best job in answering your question. His light goes around a circle, light guides can do that.
http://www.androcles01.pwp.blueyonder.co.uk/Sagnac/Sagnac.htm
kanuk - 28 Apr 2007 01:38 GMT >I am a stupid guy, who does not know the answer to this problem: A body > (observer) moves in a stationary frame with speed v<c. Huh? A "stationary" frame has speed v? I can see you are confused, reduce the problem to real world terms. We don't need observers, bodies or frames. I'll translate into plain English for you and assume you mean 'c' is the speed of light, but I will use *some* technical terms. Here goes:
Translation: A motorcyclist careens along a road with velocity v which is also speed v but has direction as well. He is not going backwards, sideways or looping the loop. He is unidirectional, not omnidirectional. (I mention that because light from the sun is omnidirectional, meaning it goes in all directions.)
> It sends a light > signal travelling with speed c+v (parallel with v). Translation: He turns on his headlight, it's getting dark, the sun has gone down. The light leaves the lamp at velocity +c relative to the lamp, v+c relative to the road, and we are only concerned with its unidirectional velocity parallel with v.
> What will be the speed > of the signal after reflection on a stationary mirror (which is > perpendicular to v). Translation: The light hits a reflective traffic sign that shows arrows like this ">>>>" -- meaning "Slow up, bend ahead" (or "Slow down, bend ahead", depending the cliche you prefer). How fast does the light come back to the rider's eye so that he can read the sign that he picked out in his headlight beam and react to it?
Answer: It comes back at '-c' with respect to the motorcycle and 'v-c' with respect to the road. Check with Doppler radar for verification. http://www.androcles01.pwp.blueyonder.co.uk/AC/doppler.gif
> Thanks to anybody who would answer. Do not listen to idiots. Figure out for yourself who they are, shun them. Here are a few to start you off. Tom Roberts. (Humpty Roberts) Timo Neiminen. (The nonwizard of Oz) Paul Draper. (Phuckwit Duck) "Uncle" Al Schwartz. (Uncle Stooopid) Randy Poe. (Blind Poe) Ghost in the Machine. (General Idiot) Albert Einstein, relativist. John Baez, relativist. James Clerk Maxwell, aetherialist. A host of lesser phuckwits.
Those you should listen to (not so many of these) are: Nicholas Copernicus. Galileo Galilei. Sir Isaac Newton. Johannes Kepler. Christian Andreas Doppler. Albert Michelson. Georges Sagnac.
Perhaps Georges Sagnac does the best job in answering your question. His light goes around a circle, light guides can do that.
http://www.androcles01.pwp.blueyonder.co.uk/Sagnac/Sagnac.htm
Thanks for enlightenment. However, I think that it would have been sufficient to write "In a stationary frame, a body > (observer) moves with speed v<c." I wrote "speed" intentionally, because that was the value, I was interested in, being aware, that after reflection the velocity is in reversed direction. So far your list of credible(?) and uncredible "sages" concerns, I might have some doubts, but that is not the question. In the end, I am not sure, that my question is equivalent with the Doppler radar situation. While relation between the source and the mirror is equivalent, I think it is not equivalent in relation to the medium, through which the light propagates. But I do not argue about this point. May be that I am wrong.
Androcles - 28 Apr 2007 18:46 GMT >>I am a stupid guy, who does not know the answer to this problem: A body >> (observer) moves in a stationary frame with speed v<c. [quoted text clipped - 80 lines] > which the light propagates. But I do not argue about this point. May be that > I am wrong. What makes you hallucinate energy needs a medium to propagate? http://www.androcles01.pwp.blueyonder.co.uk/AC/AC.htm
kanuk - 28 Apr 2007 19:40 GMT > "kanuk" <sperlingz@shaw.ca> wrote in message > news:AWtYh.135540$aG1.75362@pd7urf3no... [quoted text clipped - 87 lines] > that > I am wrong. What makes you hallucinate energy needs a medium to propagate? http://www.androcles01.pwp.blueyonder.co.uk/AC/AC.htm
Touche. I appologise.
Androcles - 28 Apr 2007 21:19 GMT >> "kanuk" <sperlingz@shaw.ca> wrote in message >> news:AWtYh.135540$aG1.75362@pd7urf3no... [quoted text clipped - 92 lines] > > Touche. I appologise. No need for apology, just as long as we clear up that rather large sticking point, it being the crux of the entire debate concerning light's velocity. We have aetherialists like Ken Seto and G.L. O'Barr, a wide spread of relativists who have only learned the "Lorentz Transformations" without understanding their derivation, and a very few others who say that light's velocity, like a bullet, is its emission velocity.
There are only three choices: 1) source dependence. 2) medium dependence. 3) observer dependence.
It only takes one counter-example to blow a hole in any theory, and Einstein provided his own. "But the ray moves relatively to the initial point of k, when measured in the stationary system, with the velocity c-v" ... Reference: http://www.fourmilab.ch/etexts/einstein/specrel/www/ section 3. That's it, observer dependence is killed by that single statement, relativity is dead in the water.
The aetherialists refuse to accept Sagnac or MMX, but that's sheer obstinacy and blind faith. Neither Seto nor O'Barr will produce any mathematical argument, they just wave their hands and say its the same math as relativity. You cannot reason with either of them.
So all that is left is emission theory (or source dependence). Where do we go from here? http://www.androcles01.pwp.blueyonder.co.uk/Algol/Algol.htm Astronomy may be the oldest science. It also has more dogma and blind faith than any other.
Ahmed Ouahi, Architect - 28 Apr 2007 00:49 GMT Obviously!?
However, it does not matter, whether you would like to be a stupid, but what you are asking, it would not let you, to be along any stupidy matter, as for the simple reason, that it would as it should turns to a definite a geometrically matter, as it would a puzzle you as a hell...
For the time being, as anything would be along a limited space, would never repeat itself as it would never cross itself neither, for instance, do put the v along zero, a distance along a left of the center, a both point would specify a single point, then the v would reach its maximum along any perpendicularity, as it would cross the zero, as the v, would pass again to the zero, as it would appear a negative motion.
Therefore, a simply, once a system returns to a state it has had been in it before, should follow the same path, whether to produce every behaviors, as the base would have to be along an infinitely long line along a finite area all along, and this what it would be, what is all about, a definitely as a matter a fact.
-- Ahmed Ouahi, Architect Best Regards!
> I am a stupid guy, who does not know the answer to this problem: A body > (observer) moves in a stationary frame with speed v<c. It sends a light > signal travelling with speed c+v (parallel with v). What will be the speed > of the signal after reflection on a stationary mirror (which is > perpendicular to v). > Thanks to anybody who would answer. bz - 28 Apr 2007 01:04 GMT > I am a stupid guy, who does not know the answer to this problem: A body > (observer) moves in a stationary frame with speed v<c. It sends a light > signal travelling with speed c+v (parallel with v). What will be the speed > of the signal after reflection on a stationary mirror (which is > perpendicular to v). > Thanks to anybody who would answer. IF the supposition 'it sends a light signal travelling with speed c+v' were possible [imagine a universe where this is possible] then there are several possible answers, depending on the laws of physics in that universe.
1) the reflected light moves at c-v (momentum conserved) 2) the reflected light moves at c (momentum would have to be transfered to the mirror 3) the reflected light moves at c-v/2 (half the momentum is conserved, half transfered to the mirror 4) you make your own rule.
 Signature bz
please pardon my infinite ignorance, the set-of-things-I-do-not-know is an infinite set.
bz+spr@ch100-5.chem.lsu.edu remove ch100-5 to avoid spam trap
kanuk - 28 Apr 2007 02:35 GMT >> I am a stupid guy, who does not know the answer to this problem: A body >> (observer) moves in a stationary frame with speed v<c. It sends a light [quoted text clipped - 17 lines] > transfered to the mirror > 4) you make your own rule. bz, it seems that the presented problem is more complicated than I have expected. Infinity plus something is still infinity.
bz - 28 Apr 2007 07:01 GMT >>> I am a stupid guy, who does not know the answer to this problem: A >>> body (observer) moves in a stationary frame with speed v<c. It sends a [quoted text clipped - 20 lines] > bz, it seems that the presented problem is more complicated than I have > expected. Infinity plus something is still infinity. knowledge is finite. Ignorance is infinite. Wisdom is knowing one's ignorance.
 Signature bz
please pardon my infinite ignorance, the set-of-things-I-do-not-know is an infinite set.
bz+spr@ch100-5.chem.lsu.edu remove ch100-5 to avoid spam trap
fritzius@bellsouth.net - 28 Apr 2007 14:25 GMT > I am a stupid guy, who does not know the answer to this problem: A body > (observer) moves in a stationary frame with speed v<c. It sends a light > signal travelling with speed c+v (parallel with v). What will be the speed > of the signal after reflection on a stationary mirror (which is > perpendicular to v). > Thanks to anybody who would answer. You need to be doing this experiment in a pretty good vacuum. That's assuming that Fox's dispersive extinction theorem* is a factor. The extinction distance should be greater than the distance between the moving source and the mirror, otherwise the light will have slowed to C before it reaches the mirror. (That's assuming the air between the source and mirror is essentially stationary with respect to the mirror.)
With the above added constraint in effect, the light should impact the mirror at C + V. The reflected (re-radiated) light should leave the mirror at the speed C (with respect to the mirror). According to Fox,ther re- radiated light travels C with respect to the most recent (re-radiating) source.
*J.G. Fox, Evidence Against Emission Theories, Am. J. Phys. 33, 1, (1965)
Bob Fritzius
Androcles - 28 Apr 2007 18:50 GMT >> I am a stupid guy, who does not know the answer to this problem: A body >> (observer) moves in a stationary frame with speed v<c. It sends a light [quoted text clipped - 4 lines] > > You need to be doing this experiment in a pretty good vacuum. Nah, Sagnac works just fine with or without vacuum. http://www.androcles01.pwp.blueyonder.co.uk/Sagnac/Sagnac.htm
RULES OF REASONING IN PHILOSOPHY.
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RULE I. We are to admit no more causes of natural things than such as are both true and sufficient to explain their appearances.
To this purpose the philosophers say that Nature does nothing in vain, and more is in vain when less will serve; for Nature is pleased with simplicity, and affects not the pomp of superfluous causes. --- Sir Isaac Newton.
kanuk - 28 Apr 2007 19:59 GMT <fritzius@bellsouth.net> wrote in message news:1177766758.689809.258820@o5g2000hsb.googlegroups.com...
> On Apr 27, 4:29 pm, "kanuk" <sperli...@shaw.ca> wrote: >> I am a stupid guy, who does not know the answer to this problem: A body [quoted text clipped - 6 lines] > > You need to be doing this experiment in a pretty good vacuum. Nah, Sagnac works just fine with or without vacuum. http://www.androcles01.pwp.blueyonder.co.uk/Sagnac/Sagnac.htm
RULES OF REASONING IN PHILOSOPHY.
--------------------------------------------------------------------------------
RULE I. We are to admit no more causes of natural things than such as are both true and sufficient to explain their appearances.
To this purpose the philosophers say that Nature does nothing in vain, and more is in vain when less will serve; for Nature is pleased with simplicity, and affects not the pomp of superfluous causes. --- Sir Isaac Newton.
With reference to this quote I am taking the liberty of advertising my creation "An Alternative Mathematical Frame for the Theory of Relativity", available at www.myrelance.com, link AMF, in pdf (no medium for energy propagation included). Users of Firefox would have to download it and open in pdf (Acrobat). IE works directly. TR is there treated in three dimensions, even GR works that way.
If on the basis of this communication some people would be tempted to state that I am an idiot, I wish to let them know that that has been said manytimes, so that they would be wasting their precious energy.
Androcles - 28 Apr 2007 22:03 GMT > <fritzius@bellsouth.net> wrote in message > news:1177766758.689809.258820@o5g2000hsb.googlegroups.com... [quoted text clipped - 34 lines] > that I am an idiot, I wish to let them know that that has been said > manytimes, so that they would be wasting their precious energy. "Any suggestions for improvements in this direction would be greatly appreciated. The writer hopes that no such a defect will be of a “fatal” nature."
I see no reason at this stage to call you an idiot, but I do take immediate issue with: "Because time depends on location"
I shall not comment with my own voice, but that of Newton's.
"Absolute, true, and mathematical time, of itself, and from its own nature flows equably without regard to anything external, and by another name is called duration: relative, apparent, and common time, is some sensible and external (whether accurate or unequable) measure of duration by the means of motion, which is commonly used instead of true time; such as an hour, a day, a month, a year."
"Absolute time, in astronomy, is distinguished from relative, by the equation or correlation of the vulgar time. For the natural days are truly unequal, though they are commonly considered as equal and used for a measure of time; astronomers correct this inequality for their more accurate deducing of the celestial motions. It may be, that there is no such thing as an equable motion, whereby time may be accurately measured. All motions may be accelerated and retarded, but the true, or equable, progress of absolute time is liable to no change. The duration or perseverance of the existence of things remains the same, whether the motions are swift or slow, or none at all: and therefore, it ought to be distinguished from what are only sensible measures thereof; and out of which we collect it, by means of the astronomical equation. The necessity of which equation, for determining the times of a phænomenon, is evinced as well from the experiments of the pendulum clock, as by eclipses of the satellites of Jupiter."
You have chosen to argue against the words of one of the greatest men of science that there ever was, perhaps *the* greatest.
This is not a comment, it is an invitation to you to substantiate your postulate.
Please produce the empirical evidence to support your assertion "time depends on location". In particular, show that the duration of the period of a Saturnian Moon is different when seen near Saturn than seen from Earth, my two chosen locations; for I claim that should I take a (perfect) caesium or similar atomic clock to Saturn (aboard the Cassini probe) it will remain synchronised with clocks on Earth and measure the period of Titan to be exactly the same (within the limits of experimental error and Doppler shift which I can obviate but running the experiment for as many orbits of the Earth about the Sun as necessary) and that Newton was correct, using the finest clocks we have available. "The second is the duration of 9 192 631 770 periods of the radiation corresponding to the transition between the two hyperfine levels of the ground state of the cesium 133 atom. "
http://physics.nist.gov/cuu/Units/second.html
kanuk - 28 Apr 2007 23:11 GMT > <fritzius@bellsouth.net> wrote in message > news:1177766758.689809.258820@o5g2000hsb.googlegroups.com... [quoted text clipped - 37 lines] > that I am an idiot, I wish to let them know that that has been said > manytimes, so that they would be wasting their precious energy. "Any suggestions for improvements in this direction would be greatly appreciated. The writer hopes that no such a defect will be of a “fatal” nature."
I see no reason at this stage to call you an idiot, but I do take immediate issue with: "Because time depends on location"
I shall not comment with my own voice, but that of Newton's.
"Absolute, true, and mathematical time, of itself, and from its own nature flows equably without regard to anything external, and by another name is called duration: relative, apparent, and common time, is some sensible and external (whether accurate or unequable) measure of duration by the means of motion, which is commonly used instead of true time; such as an hour, a day, a month, a year."
"Absolute time, in astronomy, is distinguished from relative, by the equation or correlation of the vulgar time. For the natural days are truly unequal, though they are commonly considered as equal and used for a measure of time; astronomers correct this inequality for their more accurate deducing of the celestial motions. It may be, that there is no such thing as an equable motion, whereby time may be accurately measured. All motions may be accelerated and retarded, but the true, or equable, progress of absolute time is liable to no change. The duration or perseverance of the existence of things remains the same, whether the motions are swift or slow, or none at all: and therefore, it ought to be distinguished from what are only sensible measures thereof; and out of which we collect it, by means of the astronomical equation. The necessity of which equation, for determining the times of a phænomenon, is evinced as well from the experiments of the pendulum clock, as by eclipses of the satellites of Jupiter."
You have chosen to argue against the words of one of the greatest men of science that there ever was, perhaps *the* greatest.
This is not a comment, it is an invitation to you to substantiate your postulate.
Please produce the empirical evidence to support your assertion "time depends on location". In particular, show that the duration of the period of a Saturnian Moon is different when seen near Saturn than seen from Earth, my two chosen locations; for I claim that should I take a (perfect) caesium or similar atomic clock to Saturn (aboard the Cassini probe) it will remain synchronised with clocks on Earth and measure the period of Titan to be exactly the same (within the limits of experimental error and Doppler shift which I can obviate but running the experiment for as many orbits of the Earth about the Sun as necessary) and that Newton was correct, using the finest clocks we have available. "The second is the duration of 9 192 631 770 periods of the radiation corresponding to the transition between the two hyperfine levels of the ground state of the cesium 133 atom. "
http://physics.nist.gov/cuu/Units/second.html
Androcles, that is a misunderstanding. Please, note, that my "postulate", ot whatever you would call it, is: Time increases at a constant rate, which is the same in all points which are stationary in relation to each other. It shows, however, a "phase difference" which depends on location, and eventually, on the presence of other fields (e.g. gravitational). In your terms, I am saying nothing else, than Newton has said, the period of a Saturnian moon is the same, when measured on Saturn, on Earth or on the surface of a black hole, the second would have still the same definition.. And if the TIME (not its rate of lapsing) were not dependent on location (a "shift of phase") then Roemer would not have been able to determine the velocity of light. That the light from Sun travels to Earth for 8 minutes is - I believe - fairly well known fact. Therefore, in my terms, there is a time difference of 8 minutes between the Sun time and Earth time (According to Einstein, there woul be no such difference).On the other hand, things would look a little bit differently, if we would observe Sun clock and Earth clock from Alpha Centauri (however, the period of a Sat. moon would be still the same) Satisfied? !
kanuk - 28 Apr 2007 23:31 GMT >> <fritzius@bellsouth.net> wrote in message >> news:1177766758.689809.258820@o5g2000hsb.googlegroups.com... [quoted text clipped - 118 lines] > Satisfied? > ! Perhaps, I should say " ...there is a CONSTANT time difference between the Earth time and the Sun time."
Androcles - 29 Apr 2007 01:01 GMT >>> <fritzius@bellsouth.net> wrote in message >>> news:1177766758.689809.258820@o5g2000hsb.googlegroups.com... [quoted text clipped - 121 lines] > Perhaps, I should say " ...there is a CONSTANT time difference between the > Earth time and the Sun time." NOW here is NOW everywhere.
Androcles - 29 Apr 2007 01:01 GMT >> <fritzius@bellsouth.net> wrote in message >> news:1177766758.689809.258820@o5g2000hsb.googlegroups.com... [quoted text clipped - 97 lines] > whatever you would call it, is: Time increases at a constant rate, which is > the same in all points which are stationary in relation to each other. Why the caveat?
> It > shows, however, a "phase difference" which depends on location, and > eventually, on the presence of other fields (e.g. gravitational). Phase difference? Uptime is 90 degrees out of phase with lefttime and 180 degrees out of phase with forward time?
tau_x = (t-vx/c²)/sqrt(1-v²/c²) tau_y = (t-uy/c²)/sqrt(1-u²/c²) tau_z = (t-wz/c²)/sqrt(1-w²/c²) xi = (x-vt)/sqrt(1-v²/c²) eta = (y-ut)/sqrt(1-u²/c²) zeta= (z-wt)/sqrt(1-w²/c²) If one is right they all are, if one is wrong they all are. Carry three watches or do not move sideways or ride an elevator.
Personally I prefer three witches: Double double, toil and trouble, Fire burn and Einstein bubble. --- Pop! ("Macbeth" by W. Shakespeare)
You are not making much sense here. Please produce the empirical evidence to support your assertion "time depends on location". Alternatively, withdraw the statement from your paper. Better yet, withdraw your paper.
> In your terms, I am saying nothing else, than Newton has said, the period of > a Saturnian moon is the same, when measured on Saturn, on Earth or on the > surface of a black hole, the second would have still the same definition.. Ok, an engineer would call that the same "gain".
> And if the TIME (not its rate of lapsing) were not dependent on location (a > "shift of phase") then Roemer would not have been able to determine the > velocity of light. Rate of lapsing? The word is "duration". Rate means "mass per unit time" (rate of weight gain) or length per unit time (speed) or kilowatts per unit time (electrical consumption, your meter reads it). There are no meters per meter, grams per gram or seconds per second, the word "rate" applies to a quantity that changes with DURATION. A second is a duration, a day is a duration. "Rate of lapsing" is meaningless. Roemer used duration of the orbit of the Jovian Moons. He didn't care that he wasn't on the Greenwich meridian, but 1/2 an hour or so ahead of GMT.
> That the light from Sun travels to Earth for 8 minutes > is - I believe - fairly well known fact. Duration.
> Therefore, in my terms, there is a > time difference of 8 minutes between the Sun time and Earth time We see the sun as it was 8 minutes ago, not as it is NOW. I could have a phone conversation with you via a transceiver on the Moon and hear what you said 2.3 seconds ago, but we could not synchronise watches that way, you'd be two seconds behind me and I'd be 2 seconds behind you and anyway you are 8 hours behind me. But we'd both see the event of a meteor striking the Moon simultaneously.
> (According > to Einstein, there woul be no such difference). Einstein was an idiot, Newton would chew him up and spit out the bones.
> On the other hand, things > would look a little bit differently, if we would observe Sun clock and Earth > clock from Alpha Centauri (however, the period of a Sat. moon would be still > the same) > Satisfied? No, I'm not. The time here (London) is 0:55 am, I'm about to wrap it up for the day. The time in Southern California is 4:44 pm. I can go to a webcam and see traffic "live" in daylight (slight delay) NOW. http://svhqmsmedia1.dot.ca.gov/d12cam1 I understand a signal delay, but NOW here is NOW there.
Please produce the empirical evidence to support your assertion "time depends on location", duration of signal information (delay) is irrelevant. NOW here is NOW everywhere throughout the Universe. The time is NOW.
kanuk - 29 Apr 2007 19:26 GMT > "kanuk" <sperlingz@shaw.ca> wrote in message > news:JQMYh.140240$6m4.119807@pd7urf1no... [quoted text clipped - 116 lines] > is > the same in all points which are stationary in relation to each other. Why the caveat?
> It > shows, however, a "phase difference" which depends on location, and > eventually, on the presence of other fields (e.g. gravitational). Phase difference? Uptime is 90 degrees out of phase with lefttime and 180 degrees out of phase with forward time?
tau_x = (t-vx/c²)/sqrt(1-v²/c²) tau_y = (t-uy/c²)/sqrt(1-u²/c²) tau_z = (t-wz/c²)/sqrt(1-w²/c²) xi = (x-vt)/sqrt(1-v²/c²) eta = (y-ut)/sqrt(1-u²/c²) zeta= (z-wt)/sqrt(1-w²/c²) If one is right they all are, if one is wrong they all are. Carry three watches or do not move sideways or ride an elevator.
Personally I prefer three witches: Double double, toil and trouble, Fire burn and Einstein bubble. --- Pop! ("Macbeth" by W. Shakespeare)
You are not making much sense here. Please produce the empirical evidence to support your assertion "time depends on location". Alternatively, withdraw the statement from your paper. Better yet, withdraw your paper.
> In your terms, I am saying nothing else, than Newton has said, the period > of > a Saturnian moon is the same, when measured on Saturn, on Earth or on the > surface of a black hole, the second would have still the same definition.. Ok, an engineer would call that the same "gain".
> And if the TIME (not its rate of lapsing) were not dependent on location > (a > "shift of phase") then Roemer would not have been able to determine the > velocity of light. Rate of lapsing? The word is "duration". Rate means "mass per unit time" (rate of weight gain) or length per unit time (speed) or kilowatts per unit time (electrical consumption, your meter reads it). There are no meters per meter, grams per gram or seconds per second, the word "rate" applies to a quantity that changes with DURATION. A second is a duration, a day is a duration. "Rate of lapsing" is meaningless. Roemer used duration of the orbit of the Jovian Moons. He didn't care that he wasn't on the Greenwich meridian, but 1/2 an hour or so ahead of GMT.
> That the light from Sun travels to Earth for 8 minutes > is - I believe - fairly well known fact. Duration.
> Therefore, in my terms, there is a > time difference of 8 minutes between the Sun time and Earth time We see the sun as it was 8 minutes ago, not as it is NOW. I could have a phone conversation with you via a transceiver on the Moon and hear what you said 2.3 seconds ago, but we could not synchronise watches that way, you'd be two seconds behind me and I'd be 2 seconds behind you and anyway you are 8 hours behind me. But we'd both see the event of a meteor striking the Moon simultaneously.
> (According > to Einstein, there woul be no such difference). Einstein was an idiot, Newton would chew him up and spit out the bones.
> On the other hand, things > would look a little bit differently, if we would observe Sun clock and [quoted text clipped - 3 lines] > the same) > Satisfied? No, I'm not. The time here (London) is 0:55 am, I'm about to wrap it up for the day. The time in Southern California is 4:44 pm. I can go to a webcam and see traffic "live" in daylight (slight delay) NOW. http://svhqmsmedia1.dot.ca.gov/d12cam1 I understand a signal delay, but NOW here is NOW there.
Please produce the empirical evidence to support your assertion "time depends on location", duration of signal information (delay) is irrelevant. NOW here is NOW everywhere throughout the Universe. The time is NOW.
I will attempt to answer some of your points, possibly not all of them. 1) Newton, your favorite sage. While I have no objection to consider him if not the greatest then at least one of the greatest physicists, the fact remains that his physics does not consider the finite velocity of light. Therefore, for high speeds, which have been observed in astronomy for some time, and at present are being observed in particle accelerators, his equations fail. 2) Einstein. You might have noted that I am no fanatic einsteinist. However, I am trying to give everybody his due. According to my opinion, Einstein's merit(?) is that he was the first to build up a physical system, from several postulates (axioms?), which takes into account the finite velocity of light. As in mathematics, axioms are unprovable. You may have some reservations(?) to his axioms, but so far as I know, no alternative theory exists, which would be similarly complete, or at least of similar extent. 3) NOW is NOW everywhere. NOW is no physical entity. A physical entity is 12:00:00 or so. That is time. Duration by itself is meaningless. It has to relate to something, e.g. duration of a trip, starting at T1 = 12:00:00 and ending at T2 = 12:15:00, i.e. a trip of duration of 15 min. 4) Empirical evidence that time depends on location. Such evidence does not exist, in the same way as for the opposite that time does not depend on location. That is a matter of definition, not of experimental proof. However, if my mathematics of Sec 2 is accepted, then c* = -grad(T) and consequently T IS a scalar field, vith value of T depending on location. This relationship is deduced directly from the definition of c = dr/dt and its validity I have consulted with a mathematics professor. 5) To put all of this into "practical" terms. I believe that you have accepted that light travels from Sun to Earth in 8 minutes. Lets asuume, that at 12:00:00 Earth time in Greenwich a solar eruption has been observed. Lets assume, that a clock exists on the Sun, going at the same rate (clock rate is a technical term, like it or not) as the Earth clock. Which time did the solar clock show at the instant of the eruption? Here I am ending for now. If you wish to continue our discussion, I will be glad to obtain your answer. If you are fed up with a crazy old guy - no hard feelings.
Androcles - 29 Apr 2007 21:00 GMT >> "kanuk" <sperlingz@shaw.ca> wrote in message >> news:JQMYh.140240$6m4.119807@pd7urf1no... [quoted text clipped - 218 lines] > not the greatest then at least one of the greatest physicists, the fact > remains that his physics does not consider the finite velocity of light. If it did not, Roemer would not have used it.
"the velocity of light in our theory plays the part, physically, of an infinitely great velocity." -- Einstein (who plays the part, physically, of an idiot savant).
Please produce the evidence to support your assertion that Newtonian physics does not support a finite speed of light.
> Therefore, for high speeds, which have been observed in astronomy for some > time, and at present are being observed in particle accelerators, his > equations fail. What is the closing velocity in this animation of a particle accelerator? http://hands-on-cern.physto.se/ani/acc_lhc_atlas/lhc_atlas.swf
Please produce the evidence to support your assertion that Newtonian equations fail.
> 2) Einstein. You might have noted that I am no fanatic einsteinist. However, > I am trying to give everybody his due. According to my opinion, I have to interrupt here and tell you that I'm not interested in anyone's opinion, or even interested in any person alive or dead, except insofar as they can prove their case. I demand proof. Nothing less will do. Your opinion will be glanced through for possible tid-bits but otherwise go unstudied.
Please produce the empirical evidence to support your assertion "time depends on location".
Please produce the evidence to support your assertion that Newtonian physics does not support a finite speed of light.
Please produce the evidence to support your assertion that Newtonian equations fail.
> Einstein's > merit(?) is that he was the first to build up a physical system, from > several postulates (axioms?), which takes into account the finite velocity > of light. As in mathematics, axioms are unprovable. You may have some > reservations(?) to his axioms, but so far as I know, no alternative theory > exists, which would be similarly complete, or at least of similar extent.
> 3) NOW is NOW everywhere. NOW is no physical entity. A physical entity is > 12:00:00 or so. That is time. > Duration by itself is meaningless. It has to relate to something, e.g. > duration of a trip, starting at T1 = 12:00:00 and ending at T2 = 12:15:00, > i.e. a trip of duration of 15 min. I've been sitting at my desk for more than 15 minutes, time has passed. You'll be telling me next that a bit, byte or word in computer memory is not a physical entity, it has no mass and is of undefined duration. If we are to continue this discussion then some definition of 'entity' is called for, or we'll not be communicating and continuation is pointless.
> 4) Empirical evidence that time depends on location. Such evidence does not > exist, in the same way as for the opposite that time does not depend on > location. That is a matter of definition, not of experimental proof. Ok. So your choices are a) withdraw the statement from your paper and all that directly follows from it and I'll read it until I find the next sticking point. or b) Mathematically define time as a function of location.
The problem I foresee with that (perhaps you can overcome it) is that your 12:00:00 is my 12:00:01 in my view and my 12:00:00 is 12:00:01 in your view, making time subjective. Yet this offset is maintained in perpetuity, your 13:00:00 is my 13:00:01 in my view and my 13:00:00 is 13:00:01 in your view. Our respective clocks have the same gain but we cannot agree on the offset. This is very different to Einstein's time, he has differing gains as a function of relative velocity but he did it by dividing by zero and not telling anyone. Subjectivity is not objectivity.
> However, if my mathematics of Sec 2 is accepted, then c* = -grad(T) and > consequently T IS a scalar field, vith value of T depending on location. > This relationship is deduced directly from the definition of c = dr/dt and > its validity I have consulted with a mathematics professor. I'm still stuck on your definitions of "time depends on location", "duration is meaningless" and "'Now' is no physical entity", I cannot proceed until I clearly understand your definitions.
Please produce the evidence to support your assertion that Newtonian physics does not support a finite speed of light.
Please produce the evidence to support your assertion that Newtonian equations fail.
> 5) To put all of this into "practical" terms. I believe that you have > accepted that light travels from Sun to Earth in 8 minutes. Yes, of course. I'll not nitpick to tthe nearest second, 8 mins is fine.
> Lets asuume, > that at 12:00:00 Earth time in Greenwich a solar eruption has been observed. Ok, so it took place at 11:52:00 and Cassini at Saturn will see it at around 1 o'clock. Cassini was taking a photograph of the Sun at that time, transmits the image and it will arrive at JPL at 2:10:00. What's the big deal?
> Lets assume, that a clock exists on the Sun, going at the same rate (clock > rate is a technical term, like it or not) as the Earth clock. Which time did > the solar clock show at the instant of the eruption? 11:52:00
> Here I am ending for now. If you wish to continue our discussion, I will be > glad to obtain your answer. If you are fed up with a crazy old guy - no hard > feelings. I'm quite used to crazy old guys. I'm crazy enough to argue with anyone until they bore me, then I plonk them. You'll know when I've had enough.
Please produce the evidence to support your assertion that Newtonian equations does not support a finite speed of light, c = dr/dt is a Newtonian equation, Newton developed the calculus independently of Leibnitz.
Please produce the evidence to support your assertion that Newtonian equations fail.
kanuk - 30 Apr 2007 02:32 GMT > "kanuk" <sperlingz@shaw.ca> wrote in message > news:CEPYh.142103$6m4.108123@pd7urf1no... [quoted text clipped - 234 lines] > not the greatest then at least one of the greatest physicists, the fact > remains that his physics does not consider the finite velocity of light. If it did not, Roemer would not have used it.
"the velocity of light in our theory plays the part, physically, of an infinitely great velocity." -- Einstein (who plays the part, physically, of an idiot savant).
Please produce the evidence to support your assertion that Newtonian physics does not support a finite speed of light.
> Therefore, for high speeds, which have been observed in astronomy for some > time, and at present are being observed in particle accelerators, his > equations fail. What is the closing velocity in this animation of a particle accelerator? http://hands-on-cern.physto.se/ani/acc_lhc_atlas/lhc_atlas.swf
Please produce the evidence to support your assertion that Newtonian equations fail.
> 2) Einstein. You might have noted that I am no fanatic einsteinist. > However, > I am trying to give everybody his due. According to my opinion, I have to interrupt here and tell you that I'm not interested in anyone's opinion, or even interested in any person alive or dead, except insofar as they can prove their case. I demand proof. Nothing less will do. Your opinion will be glanced through for possible tid-bits but otherwise go unstudied.
Please produce the empirical evidence to support your assertion "time depends on location".
Please produce the evidence to support your assertion that Newtonian physics does not support a finite speed of light.
Please produce the evidence to support your assertion that Newtonian equations fail.
> Einstein's > merit(?) is that he was the first to build up a physical system, from > several postulates (axioms?), which takes into account the finite velocity > of light. As in mathematics, axioms are unprovable. You may have some > reservations(?) to his axioms, but so far as I know, no alternative theory > exists, which would be similarly complete, or at least of similar extent.
> 3) NOW is NOW everywhere. NOW is no physical entity. A physical entity is > 12:00:00 or so. That is time. > Duration by itself is meaningless. It has to relate to something, e.g. > duration of a trip, starting at T1 = 12:00:00 and ending at T2 = 12:15:00, > i.e. a trip of duration of 15 min. I've been sitting at my desk for more than 15 minutes, time has passed. You'll be telling me next that a bit, byte or word in computer memory is not a physical entity, it has no mass and is of undefined duration. If we are to continue this discussion then some definition of 'entity' is called for, or we'll not be communicating and continuation is pointless.
> 4) Empirical evidence that time depends on location. Such evidence does > not > exist, in the same way as for the opposite that time does not depend on > location. That is a matter of definition, not of experimental proof. Ok. So your choices are a) withdraw the statement from your paper and all that directly follows from it and I'll read it until I find the next sticking point. or b) Mathematically define time as a function of location.
The problem I foresee with that (perhaps you can overcome it) is that your 12:00:00 is my 12:00:01 in my view and my 12:00:00 is 12:00:01 in your view, making time subjective. Yet this offset is maintained in perpetuity, your 13:00:00 is my 13:00:01 in my view and my 13:00:00 is 13:00:01 in your view. Our respective clocks have the same gain but we cannot agree on the offset. This is very different to Einstein's time, he has differing gains as a function of relative velocity but he did it by dividing by zero and not telling anyone. Subjectivity is not objectivity.
> However, if my mathematics of Sec 2 is accepted, then c* = -grad(T) and > consequently T IS a scalar field, vith value of T depending on location. > This relationship is deduced directly from the definition of c = dr/dt and > its validity I have consulted with a mathematics professor. I'm still stuck on your definitions of "time depends on location", "duration is meaningless" and "'Now' is no physical entity", I cannot proceed until I clearly understand your definitions.
Please produce the evidence to support your assertion that Newtonian physics does not support a finite speed of light.
Please produce the evidence to support your assertion that Newtonian equations fail.
> 5) To put all of this into "practical" terms. I believe that you have > accepted that light travels from Sun to Earth in 8 minutes. Yes, of course. I'll not nitpick to tthe nearest second, 8 mins is fine.
> Lets asuume, > that at 12:00:00 Earth time in Greenwich a solar eruption has been > observed. Ok, so it took place at 11:52:00 and Cassini at Saturn will see it at around 1 o'clock. Cassini was taking a photograph of the Sun at that time, transmits the image and it will arrive at JPL at 2:10:00. What's the big deal?
> Lets assume, that a clock exists on the Sun, going at the same rate (clock > rate is a technical term, like it or not) as the Earth clock. Which time > did > the solar clock show at the instant of the eruption? 11:52:00
> Here I am ending for now. If you wish to continue our discussion, I will > be > glad to obtain your answer. If you are fed up with a crazy old guy - no > hard > feelings. I'm quite used to crazy old guys. I'm crazy enough to argue with anyone until they bore me, then I plonk them. You'll know when I've had enough.
Please produce the evidence to support your assertion that Newtonian equations does not support a finite speed of light, c = dr/dt is a Newtonian equation, Newton developed the calculus independently of Leibnitz.
Please produce the evidence to support your assertion that Newtonian equations fail.
Again, I can answer only some points. 1) Newtonian equations fail. It has been established, that for high particle velocities the relationship F = m*a is not valid any more and has to be replaced by the Einstein equation F = m*a/SQRT(1-v^2/c^2). I have some doubts that this is final, but that is another question. 2) While I do not care if infinitesimal calculus has been developed by Newton or by Leibnitz, and I have no objection to c = dr/dt being Newtonian equation, Newton's mechanics does not consider the effect of velocity on some relationships, see 1). 3) According to my Oxford dictionary, "entity" means something real, opposite to quality or relationship. I do not know, what else do you want. You may argue that time is nothing real which you can grab in hand. But I hope that you will agree that it is something that can be measured. More exactly, duration can be measured (a point can't be measured, only distance between two points). 4) Your reference to the hadron collider. I do not understand what you have in mind. +v +(-v) = 0, for both Newton and Einstein. So what is the point? 5) You are demanding proofs, on several places. Are you not aware, that no hypothesis can be proven, it can be only disproven? So, turning the table, I am inviting you to disprove my assertion that time depends on location. To satisfy you at this point, I wish to refer to my Eqn 5.3 and 6.6, which are deduced for spherical fields, empty and non-empty, respectively. Of course, you may argue that that is no experimental result. Neither can you present an experiment "proving" your assertion that time does not depend on location. I think, that is all I wanted to say.
bz - 30 Apr 2007 12:56 GMT > Please produce the evidence to support your assertion that > Newtonian equations does not support a finite speed of light, c = dr/dt [quoted text clipped - 5 lines] > > Again, I can answer only some points. ....
Please learn how to properly quote previous postings.
ALL of the 'single level quoted' material above appears to be written by kanuk.
It only became clear to me, after reading the entire posting, that part of the 'unquoted' material consisted of words of someone else and part were your words.
I suspect that the material above SHOULD have look like this:
kanuk said:
> A said: >> Please produce the evidence to support your assertion that [quoted text clipped - 6 lines] >> > Again, I can answer only some points. Either that or you are arguing with yourself.
 Signature bz
please pardon my infinite ignorance, the set-of-things-I-do-not-know is an infinite set.
bz+spr@ch100-5.chem.lsu.edu remove ch100-5 to avoid spam trap
Androcles - 30 Apr 2007 17:29 GMT >> "kanuk" <sperlingz@shaw.ca> wrote in message >> news:CEPYh.142103$6m4.108123@pd7urf1no... [quoted text clipped - 370 lines] > replaced by the Einstein equation F = m*a/SQRT(1-v^2/c^2). I have some > doubts that this is final, but that is another question. Please produce the EMPIRICAL EVIDENCE to support your assertion that Newtonian equations fail.
Please do not produce handwaving bullshit, I am not interested in bullshit.
Please produce the evidence to support your assertion that Newtonian physics does not support a finite speed of light.
> 2) While I do not care if infinitesimal calculus has been developed by > Newton or by Leibnitz, and I have no objection to c = dr/dt being Newtonian > equation, Newton's mechanics does not consider the effect of velocity on > some relationships, see 1). "1)" is handwaving bullshit, therefore "2)" is bullshit.
> 3) According to my Oxford dictionary, "entity" means something real, > opposite to quality or relationship. I do not know, what else do you want. I cannot proceed until I clearly understand your definitions. We are at a sticking point, as I knew would happen. What I want has been clearly stated and unanswered.
Please produce the EMPIRICAL EVIDENCE to support your assertion that Newtonian equations fail.
Please produce the evidence to support your assertion that Newtonian physics does not support a finite speed of light.
> You may argue that time is nothing real which you can grab in hand. But I > hope that you will agree that it is something that can be measured. Measurement is no physical entity. Measurement is comparison of one entity with another. I compare marks on a ruler with the diagonal of my computer screen. My screen measures 17". Measurement is a number.
> More > exactly, duration can be measured (a point can't be measured, only distance > between two points). Measurement, like NOW, is no physical entity.
> 4) Your reference to the hadron collider. I do not understand what you have > in mind. +v +(-v) = 0, for both Newton and Einstein. So what is the point? Let's put it this way. I'm not trying to find out if you are crazy or not, but whether you have any intelligence.
I wrote: What is the closing velocity in this animation of a particle accelerator?
> 5) You are demanding proofs, on several places. Are you not aware, that no > hypothesis can be proven, it can be only disproven? "I frame no hypotheses" -- Sir Isaac Newton.
> So, turning the table, I > am inviting you to disprove my assertion that time depends on location. Ok, here goes, make a note of it.
When at the same location our watches read the same. When you move away from my location, your watch reads less than my watch. When I move away from your location, your watch STILL reads less than my watch. I account for this apparent discrepancy in watch readings by stating that the velocity of light is finite. If you deny it, that is against empirical evidence. When we again meet "later", time has passed, our watches once again agree. If you deny it, then that is against the supposition that you moved. Around me is a sphere of radius 1 light second, wherever I happen to be. You can be at any point on the surface of said sphere and your watch will read one second less than my watch. Let there be two locations on said sphere, North Pole and South Pole for want of a better name. Time does not determine which Pole you are at, your watch read by me is 1 second slow for either. I can extend the sphere to 1 light minute, 1 light hour, 1 light day, 1 light year, indefinitely. By doing so not only have I disproven your wild conjecture, but reaffirmed Newton's axiom, time is the same everywhere. Your hypothesis fails, time is independent of location. Quod Erat Demonstrandum. Incidentally, the sphere I use in practice is the GPS satellite constellation. Each satellite tells me ITS location, from that I can determine my location.
http://www.androcles01.pwp.blueyonder.co.uk/GPS/GPS.htm
Did I see somewhere you saying you were a retired physicist? I'm a retired engineer. Physicists write reams of discarded papers, engineers make things work and wear them out before discarding them, then we put them on display, with pride. http://www.aerospaceweb.org/aircraft/jetliner/concorde/concorde_18.jpg I helped build Concorde.
> To > satisfy you at this point, I wish to refer to my Eqn 5.3 and 6.6, which are [quoted text clipped - 3 lines] > location. > I think, that is all I wanted to say. Disposed of.
Please produce the evidence to support your assertion that Newtonian physics does not support a finite speed of light. Please produce the evidence to support your assertion that Newtonian equations fail.
bz - 29 Apr 2007 21:09 GMT > But we'd both > see the event of a meteor striking the Moon simultaneously. Not quite. Let us imagine that you and A are on opposite sides of the earth and the moon is just above your eastern horizon, just above his western horizon at the moment the strike takes place. Assume you both live at sea level and on the equator.
You are moving toward the moon at 1038 mph. A is moving away from the moon at 1038 mph.
You will see the flash of light before A does because the flash has less distance to travel to get to you because you are moving toward it.
In fact you will have moved about 1.067 km closer to the source of the flash by the time you see the flash.
Light takes 3.558 us to travel that distance so you will see the flash about 7.11 us before A sees it.
I ignored making any relativistic corrections because, even though Newton WAS wrong about time being absolute, the velocities involved are small enough that the corrections would be very small compared with those we have already made. I also ignored the moon's velocity in it's orbit even though it is much greater than the 1038 mph. I did this because the component in our direction is close to zero (actually the moon is slowly moving away from us).
Possible homework: if you want to, have someone ride on another meteor that passes directly between earth and moon, missing both at .9 c and have THEM observe the meteor impact. Despite the fact that they are much closer than either of you, they are moving much faster, so they will not see the flash until much later than either of you.
Assume the clocks, yours, TRAVELERS, and A's were all exactly coincident at the moment of impact (as seen by an observer equidistant from the three of you). What time do each of you read on your clock when you see the impact. What time do you compute that the other persons should read on their clocks.
 Signature bz
please pardon my infinite ignorance, the set-of-things-I-do-not-know is an infinite set.
bz+spr@ch100-5.chem.lsu.edu remove ch100-5 to avoid spam trap
Androcles - 29 Apr 2007 23:40 GMT >> But we'd both >> see the event of a meteor striking the Moon simultaneously.
> Not quite. Let us imagine that you and A are on opposite sides of the earth > and the moon is just above your eastern horizon, just above his western [quoted text clipped - 6 lines] > You will see the flash of light before A does because the flash has less > distance to travel to get to you because you are moving toward it. HAHAHAHA!
I've seen it all now, someone who confuses distance with velocity.
The light strikes both sides of the Earth simultaneously, regardless of whether it takes 1.2 seconds or six hours to get here. If six hours, then the Moon was overhead for one observer and in the Earth's shadow beneath the feet of the other when the impact occurred. In those six hours the Earth rotates 90 degrees and both observers see the event at the same instant.
The sun crosses the sky (the Earth rotates) 180 degrees in 12 hours. Even that is not right, the Earth rotates 366 and a quarter sidereal days relative to the stars, but close enough for a rough estimate. If you want to be really picky, see http://www.androcles01.pwp.blueyonder.co.uk/Analemmae/Analemmae.htm
That's 15 degrees per hour. That's 15 arc minutes per minute. It takes 8 minutes for light from the Sun to get here. The sun is already 8 * 15 = 120 minutes = 2 degrees above the horizon before you see sunrise, and 2 degrees below when you see sunset... but even that's not quite right, the light bends as it goes through atmosphere, we call that "refraction". Day (sunrise to sunset) is longer than night (sunset to sunrise), during equinox on the equator.
http://www.roe.ac.uk/info/srss.html Latitude and Earth's tilt do of course produce longer nights than days during winter. However, though it takes many years for light from stars to reach us, they still rise and set on the horizon. You see them all as they were, not as they are NOW.
When a bullet travels faster than sound, it hits you before you hear the gun that fired it. When you see one of these: http://www.fourmilab.ch/documents/ohmygodpart.html you haven't yet seen the event that caused it. Keep looking up.
kanuk - 30 Apr 2007 18:05 GMT >> But we'd both >> see the event of a meteor striking the Moon simultaneously. [quoted text clipped - 43 lines] > What time do you compute that the other persons should read on their > clocks. --------------------------------- Being stupid, I do not know how to affect the "quotation marks". My text begins with "Again, I can answer only some points."
bz - 30 Apr 2007 18:22 GMT > Being stupid, I do not know how to affect the "quotation marks". My text > begins with > "Again, I can answer only some points." If you use a decent news client, it puts in the quotes for you. If you do not have such a client, then you must put in the quote marks yourself. You would normally add a '>' in front of each line that you did NOT write this time. Lines that already have a '>' in front of them then have '>>', etc.
You appear to be using Microsoft Outlook express as a mail and news client. I would advise people NOT to use outlook express for either because of the frequent vulnerabilities being exploited by viruses and worms.
I use xnews, a free news reader. But there are hundreds of different news readers available.
 Signature bz
please pardon my infinite ignorance, the set-of-things-I-do-not-know is an infinite set.
bz+spr@ch100-5.chem.lsu.edu remove ch100-5 to avoid spam trap
PD - 30 Apr 2007 18:38 GMT > --------------------------------- > Being stupid, I do not know how to affect the "quotation marks". My text > begins with > "Again, I can answer only some points." You are using Microsoft Outlook Express as your newsreader. If you will look in your Options and Preferences, you will find some settings for reading Newsgroups. You will see there how to configure MOE to properly handle quotations in replies. When in doubt, RTFM.
PD
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