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Natural Science Forum / Physics / Relativity / June 2007



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electric and magnetic field drops and rise

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gin - 19 Jun 2007 20:06 GMT
how long it takes for an electric field E to drop
from 100V to 5V (fall time, tf)

how long it takes for tha same field to drop
from 100V to 0V

how long it takes for a magnetic field to
drop from 6 Gauss to 0.7 Gauss

how long it takes for tha same magnetic field
to drop from 6 Gauss to 0.2 Gauss

how long it takes for an electric field to rise
from 5V to 100V (rise time, tr)
PD - 20 Jun 2007 01:15 GMT
> how long it takes for an electric field E to drop
> from 100V to 5V (fall time, tf)
[quoted text clipped - 10 lines]
> how long it takes for an electric field to rise
> from 5V to 100V (rise time, tr)

Depends on the circuit.
Look up RC and RL circuits in your nearest introductory physics book.

PD
lead free - 20 Jun 2007 17:40 GMT
> > how long it takes for an electric field E to drop
> > from 100V to 5V (fall time, tf)
[quoted text clipped - 15 lines]
>
> PD

which question you are about ta not answer professor?

i never knew that an electric field drop or rise have anything
ta do with RLC circuits

may _you_ should do tha introductory to that and  anything else,
otherwise you force me to send an undergraduate to teach you
some physics

you may eat a sandwich while you listening
Randy Poe - 20 Jun 2007 17:50 GMT
> > > how long it takes for an electric field E to drop
> > > from 100V to 5V (fall time, tf)
[quoted text clipped - 20 lines]
> i never knew that an electric field drop or rise have anything
> ta do with RLC circuits

That's why you need to read your book on such things
as "resonance frequency" or "oscillators" or "tuning".

If you are transmitting a radio signal and your circuit
is designed for 100 Hz, then the fields drop from maximum
to zero in 1/4 cycle, or 2.5 msec.

If you are transmitting at 1 MHz, the time is 250 nsec.

If you are asking questions about transient effects,
why that depends on the impedance in your circuit,
which depends on (surprise!) R, L and C.

Read your book.

          - Randy
lead free - 20 Jun 2007 17:58 GMT
> > > > how long it takes for an electric field E to drop
> > > > from 100V to 5V (fall time, tf)
[quoted text clipped - 23 lines]
> That's why you need to read your book on such things
> as "resonance frequency" or "oscillators" or "tuning".

what tha fok has oscillators and crap has ta do with that questions

yoo fool

> If you are transmitting a radio signal and your circuit
> is designed for 100 Hz, then the fields drop from maximum
> to zero in 1/4 cycle, or 2.5 msec.

what circuit you fool, who is talking about circuits?

its about tha foken field you moron, nobody mentioned electrons

i got you too, now anybody will know that you are moron indeed

> If you are transmitting at 1 MHz, the time is 250 nsec.

transmitting megaherdzi is EM fool, not electric field, learn physics

> If you are asking questions about transient effects,
> why that depends on the impedance in your circuit,
> which depends on (surprise!) R, L and C.

no fool, no transients, but drops and rise in E-fileds, period

ask your sister doing your RLCs, or PD

are you two living together?

> Read your book

what book? popular mechanics?.

>            - Randy
Randy Poe - 20 Jun 2007 18:10 GMT
> > If you are transmitting at 1 MHz, the time is 250 nsec.
>
> transmitting megaherdzi is EM fool, not electric field, learn physics

Do you have any idea what "EM" stands for?

Are you trying to declare that there is no electric
field or magnetic field an an EM wave?

> > If you are asking questions about transient effects,
> > why that depends on the impedance in your circuit,
> > which depends on (surprise!) R, L and C.
>
> no fool, no transients, but drops and rise in E-fileds, period

What E-field? Under what conditions? What is producing
it and what is causing it to change? The answer could
be 10 minutes or 1 picosecond.

           - Randy
lead free - 20 Jun 2007 18:18 GMT
> > > If you are transmitting at 1 MHz, the time is 250 nsec.
>
> > transmitting megaherdzi is EM fool, not electric field, learn physics
>
> Do you have any idea what "EM" stands for?

no, you tell me

> Are you trying to declare that there is no electric
> field or magnetic field an an EM wave?

you are tha only foken one talking about EM here, you cant be
that foken stoopid

> > > If you are asking questions about transient effects,
> > > why that depends on the impedance in your circuit,
[quoted text clipped - 3 lines]
>
> What E-field? Under what conditions? What is producing

what what E-field, a 100V E-field

> it and what is causing it to change? The answer could
> be 10 minutes or 1 picosecond.

yaa, finaly you read the question, you are funny

tell me more about the 10 minutes  and the 1 pS

>             - Randy
Randy Poe - 20 Jun 2007 18:30 GMT
> > > > If you are transmitting at 1 MHz, the time is 250 nsec.
>
[quoted text clipped - 26 lines]
>
> tell me more about the 10 minutes  and the 1 pS

I already gave you examples of 2.5 msec and 250 nsec.

10 minutes: Charge a capacitor. Disconnect the wires.
Let it discharge slowly on a humid day.

1 psec: Discharge the same capacitor with a piece of
low-resistance wire.

Now if you want some help with your homework question,
copy the rest of the question and tell us what is
producing these E and B fields and what is causing
them to change.

         - Randy
lead free - 20 Jun 2007 18:47 GMT
> > > > > If you are transmitting at 1 MHz, the time is 250 nsec.
>
[quoted text clipped - 31 lines]
> 10 minutes: Charge a capacitor. Disconnect the wires.
> Let it discharge slowly on a humid day.

you are perplexing me

has nothing to do with capacitor discharging

your capacitor is full with charged electrons flowin out
in humid air

it is about fiels not electrons

> 1 psec: Discharge the same capacitor with a piece of
> low-resistance wire.
[quoted text clipped - 3 lines]
> producing these E and B fields and what is causing
> them to change.

are you sure you know what fields and a potentials stands for
in math and physics?

>           - Randy
Randy Poe - 20 Jun 2007 18:58 GMT
> > > > it and what is causing it to change? The answer could
> > > > be 10 minutes or 1 picosecond.
[quoted text clipped - 9 lines]
>
> you are perplexing me

You asked for an example where the answer could be
10 minutes or 1 psec. That's an example where the
answer could be 10 minutes or 1 psec.

The answer could also be anything in between,
such as the previous examples I gave with
2.5 msec and 250 nsec.

> has nothing to do with capacitor discharging

Well, you haven't said what it DOES have to do
with. Until you've asked the actual question, there
isn't an answer.

> your capacitor is full with charged electrons flowin out
> in humid air

Yes. So the discharge time could be very long. You
could take 10 minutes for the E-field to decay
from 100 V to 5 V.

> it is about fiels not electrons

Fields are caused by something. You haven't said
what. Fields are changed by something. You haven't
said by what. That something could cause the change
to be fast, or slow, or not at all.

> > 1 psec: Discharge the same capacitor with a piece of
> > low-resistance wire.
[quoted text clipped - 6 lines]
> are you sure you know what fields and a potentials stands for
> in math and physics?

Yes.

Now, reread your homework and provide the rest of
the question, or give up.

              - Randy
lead free - 20 Jun 2007 19:23 GMT
> > > > > it and what is causing it to change? The answer could
> > > > > be 10 minutes or 1 picosecond.
[quoted text clipped - 13 lines]
> 10 minutes or 1 psec. That's an example where the
> answer could be 10 minutes or 1 psec.

no you said the drop in a E-field can take 10min or 1ps

and i said that this is funny but tell me more

> The answer could also be anything in between,
> such as the previous examples I gave with
> 2.5 msec and 250 nsec.

these are electron discharges,

has nothing to do with E-fields fall times

> > has nothing to do with capacitor discharging
>
> Well, you haven't said what it DOES have to do
> with. Until you've asked the actual question, there
> isn't an answer.

!?

> > your capacitor is full with charged electrons flowin out
> > in humid air
>
> Yes. So the discharge time could be very long. You
> could take 10 minutes for the E-field to decay
> from 100 V to 5 V

who asked you about electrons?
.

> > it is about fiels not electrons
>
> Fields are caused by something. You haven't said
> what. Fields are changed by something. You haven't
> said by what. That something could cause the change
> to be fast, or slow, or not at all.

why is important who or what causes the E-field, it does
not matter, reread the question

> > > 1 psec: Discharge the same capacitor with a piece of
> > > low-resistance wire.
[quoted text clipped - 13 lines]
>
>                - Randy

i understand you now, you think that E-fields are filled up
with electrons

everybody please fok meeee

what about a M-field, what is it filled up with?
Randy Poe - 20 Jun 2007 19:32 GMT
> no you said the drop in a E-field can take 10min or 1ps
>
[quoted text clipped - 5 lines]
>
> these are electron discharges,

A charged capacitor has an E-field between the
plates.

> has nothing to do with E-fields fall times

The charge of a capacitor has nothing to do with
the E-field? Are you sure?

When the charge falls to half, the E-field falls to
half. When the charge falls to zero, the E-field
falls to zero. The E-field between the plates is
directly proportional to the charge.

> > Yes. So the discharge time could be very long. You
> > could take 10 minutes for the E-field to decay
> > from 100 V to 5 V
>
> who asked you about electrons?

You asked me about E-fields. I gave an example
of a decaying E-field. In fact, I gave you four
examples where E-fields are decaying.

          - Randy
lead free - 20 Jun 2007 20:01 GMT
> > no you said the drop in a E-field can take 10min or 1ps
>
[quoted text clipped - 13 lines]
> The charge of a capacitor has nothing to do with
> the E-field? Are you sure?

not in context of tha OP question

tha RLC crap you brought it in

> When the charge falls to half, the E-field falls to
> half. When the charge falls to zero, the E-field
> falls to zero. The E-field between the plates is
> directly proportional to the charge

nothin to do with OP question

.

> > > Yes. So the discharge time could be very long. You
> > > could take 10 minutes for the E-field to decay
[quoted text clipped - 3 lines]
>
> You asked me about E-fields. I gave an example

no, is not about any examples, cant you read?
forget capacitors and crap

it is about E-fields fall and rise times
it is about M-fields fall and rise times

reread tha foken questions

> of a decaying E-field. In fact, I gave you four
> examples where E-fields are decaying

crap and non-sense

why are you sniping the rest and not answer the beautiful  questions?

do you mean that E-fields are filled up with electrons?

why on the moon are you talking about electrons so much?

>            - Randy
Randy Poe - 20 Jun 2007 20:22 GMT
> > > no you said the drop in a E-field can take 10min or 1ps
>
[quoted text clipped - 15 lines]
>
> not in context of tha OP question

Your original question had no context. It asked a
generic question about E-fields. The answer can
be anything at all, depending on the nature of what
is causing the E-field to decrease.

> tha RLC crap you brought it in

... is one example of a changing E-field.

> > When the charge falls to half, the E-field falls to
> > half. When the charge falls to zero, the E-field
> > falls to zero. The E-field between the plates is
> > directly proportional to the charge
>
> nothin to do with OP question

Sure it does. Your question was about an E-field
changing from 100 V to 5 V or 0 V. My answer
involves an E-field that changes from 100 V to
0V. The time to reach 0 V can be 10 minutes. It's
an E-field. It's decreasing. It reaches 0.
The time can also be 1 psec. Or 250 msec. Or
50 years.

The answer to your original question is: "10 minutes.
Or 1 psec. Or 250 msec. Or 50 years. Depends."

OK?

> > > > Yes. So the discharge time could be very long. You
> > > > could take 10 minutes for the E-field to decay
[quoted text clipped - 5 lines]
>
> no, is not about any examples, cant you read?

It's about SOMETHING. You just haven't specified what.

> forget capacitors and crap
>
> it is about E-fields fall and rise times
> it is about M-fields fall and rise times

Which could be 10 min. Or 1 psec. Or 250 msec.
Or 50 years. Depending.

> reread tha foken questions
>
[quoted text clipped - 6 lines]
>
> do you mean that E-fields are filled up with electrons?

Nope. I mean that E-fields could take 10 min to
decay or rise. Or 1 psec. Or 250 msec. Or
50 years. Depending.

> why on the moon are you talking about electrons so much?

Doesn't matter. Let's just talk about E-fields.

Q: how long it takes for an electric field E to drop
from 100V to 5V (fall time, tf)
A: Could be 10 minutes. Or 1 psec. Or 250 msec. Or
50 years. Depending.

Q: how long it takes for tha same field to drop
from 100V to 0V
A: Could be 10 minutes. Or 1 psec. Or 250 msec. Or
50 years. Depending.

Q: how long it takes for a magnetic field to
drop from 6 Gauss to 0.7 Gauss
A: Could be 10 minutes. Or 1 psec. Or 250 msec. Or
50 years. Depending.

Q: how long it takes for tha same magnetic field
to drop from 6 Gauss to 0.2 Gauss
A: Could be 10 minutes. Or 1 psec. Or 250 msec. Or
50 years. Depending.

Q: how long it takes for an electric field to rise
from 5V to 100V (rise time, tr)
A: Could be 10 minutes. Or 1 psec. Or 250 msec. Or
50 years. Depending.

Is that better?

By the way, E-fields aren't measured in "volts" but
I haven't even bothered with that aspect of your
question.

           - Randy
lead free - 20 Jun 2007 20:44 GMT
> > > > no you said the drop in a E-field can take 10min or 1ps
>
[quoted text clipped - 114 lines]
> I haven't even bothered with that aspect of your
> question.

volt per meter, or centimeter or millimeter etc,  so what,

it is a scaling factor, are you familiar with scalings, means nothen

in a relativity group you are talkin about electrons in capacitors
when the question was about E-field strength rate of change, one
would presume minimums and maximums, in vacuum or whatever

now tell me that i am stoopid

if i now change the questions from E-fields and M-fields to
G-fields, you and PD will ask me on what planet, atmospheric
pressure, density and such

then tell me that EM equal an E-field and a M-field twisted together

what a waist of sperm

>             - Randy
Randy Poe - 20 Jun 2007 21:00 GMT
> > Q: how long it takes for an electric field to rise
> > from 5V to 100V (rise time, tr)
[quoted text clipped - 10 lines]
>
> it is a scaling factor, are you familiar with scalings, means nothen

Means a lot. A 10000 Volt power line 100 m away from you
is safe (E field = 10000 V/100 m = 100 V/m). The same
line one mm away from you, you die. (E field = 10000 V/0.001 m
= 10 million V/m, big spark, fire, death). Same voltage.

> in a relativity group you are talkin about electrons in capacitors

You asked an incomplete question about changing E-fields
and B-fields, and you asked it in this group.

> when the question was about E-field strength rate of change, one
> would presume minimums and maximums, in vacuum or whatever
>
> now tell me that i am stoopid

Nah, I'll let others decide that.

> if i now change the questions from E-fields and M-fields to
> G-fields, you and PD will ask me on what planet, atmospheric
> pressure, density and such

No, an analogous gravitational question might
be something like this:

"I have a tank with 100 gallons of water
in it. How much time will it take to get to
5 gallons? How about 0 gallons?"

> then tell me that EM equal an E-field and a M-field twisted together

Not "twisted together", but each oscillating in its
own plane:

http://www.monos.leidenuniv.nl/smo/index.html?basics/light_anim.htm

             - Randy
lead free - 20 Jun 2007 21:07 GMT
> > > Q: how long it takes for an electric field to rise
> > > from 5V to 100V (rise time, tr)
[quoted text clipped - 15 lines]
> line one mm away from you, you die. (E field = 10000 V/0.001 m
> = 10 million V/m, big spark, fire, death). Same voltage.

no sh.t, you are blaverin about safety now, you are a kid

> > in a relativity group you are talkin about electrons in capacitors
>
> You asked an incomplete question about changing E-fields
> and B-fields, and you asked it in this group.

incomplete?

like yours charge proportional with voltage?
half charge half voltage?

please show me that capacitor having tha same capacitance
at both 100V and 5V

dQ/dt = C(E)dE/dt

> > when the question was about E-field strength rate of change, one
> > would presume minimums and maximums, in vacuum or whatever
[quoted text clipped - 22 lines]
>
>               - Randy
Randy Poe - 20 Jun 2007 21:16 GMT
> > > it is a scaling factor, are you familiar with scalings, means nothen
>
[quoted text clipped - 4 lines]
>
> no sh.t, you are blaverin about safety now, you are a kid

No, I'm "blaverin" about the denominator of V/m.

I'm telling you 10000 V/100 m is different from
10000 V/0.001 m, even though they're both 10000 V.
The denominator is not just "a scaling factor
means nothen", it's the difference between living
and dying.

Do you think the difference between living and dying
is "nothen"?

> > > in a relativity group you are talkin about electrons in capacitors
>
> > You asked an incomplete question about changing E-fields
> > and B-fields, and you asked it in this group.
>
> incomplete?

Well, as complete as my question:

> > "I have a tank with 100 gallons of water
> > in it. How much time will it take to get to
> > 5 gallons? How about 0 gallons?"

Is my question complete? What's the answer?

> like yours charge proportional with voltage?

In a capacitor, yes. Q = CV.

> half charge half voltage?
>
> please show me that capacitor having tha same capacitance
> at both 100V and 5V
>
> dQ/dt = C(E)dE/dt

That is not a capacitor equation. This is:

Q = CV.

And yes, the capacitor has the same capacitance
at 100 V and 5 V. If I buy a 50 uF capacitor at
Radio Shack, I expect it to have C = 50 uF at
100 V and at 5 V.

        - Randy
lead free - 20 Jun 2007 21:28 GMT
> > > > it is a scaling factor, are you familiar with scalings, means nothen
>
[quoted text clipped - 52 lines]
>
>          - Randy

the capacity for a capacitor you buy wherever is
a function of both

voltage,
frequency,
temperature
and many other things,

you professor, maybe your phd
lead free - 20 Jun 2007 21:56 GMT
> > > > it is a scaling factor, are you familiar with scalings, means nothen
>
[quoted text clipped - 52 lines]
>
>          - Randy

take a look professor, page 4
http://docs-europe.electrocomponents.com/webdocs/0117/0900766b80117c46.pdf
Randy Poe - 20 Jun 2007 22:14 GMT
> > And yes, the capacitor has the same capacitance
> > at 100 V and 5 V. If I buy a 50 uF capacitor at
> > Radio Shack, I expect it to have C = 50 uF at
> > 100 V and at 5 V.
>
> take a look professor, page 4http://docs-europe.electrocomponents.com/webdocs/0117/0900766b80117c4...

Oh dear, are we dropping the brain-dead act momentarily
to score points?

OK, I learned something. Though a 30% capacitance
variation from 0 to rated voltage sounds awfully large.

Now can you answer my tank-draining question?

> > > > "I have a tank with 100 gallons of water
> > > > in it. How much time will it take to get to
> > > > 5 gallons? How about 0 gallons?"

         - Randy
lead free - 20 Jun 2007 22:25 GMT
> > > And yes, the capacitor has the same capacitance
> > > at 100 V and 5 V. If I buy a 50 uF capacitor at
[quoted text clipped - 5 lines]
> Oh dear, are we dropping the brain-dead act momentarily
> to score points?

i dont know what i do, but sorry for that

> OK, I learned something. Though a 30% capacitance
> variation from 0 to rated voltage sounds awfully large.
[quoted text clipped - 6 lines]
>
>           - Randy

area of the outflow, position, length of the sink ?

i did this type of question with some variations many times before

the idea is that to remember that the pressure at the bottom of
the tank decrease with time

the length of the sink is very important
lead free - 20 Jun 2007 21:13 GMT
> > > Q: how long it takes for an electric field to rise
> > > from 5V to 100V (rise time, tr)
[quoted text clipped - 43 lines]
> Not "twisted together", but each oscillating in its
> own plane:

nice,

are you sure that what you have in an EM is an
E-field and a M-field?

are they in phase or in anti-phase?

EM without oscillations is still EM?

> http://www.monos.leidenuniv.nl/smo/index.html?basics/light_anim.htm
>
>               - Randy
 
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