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Natural Science Forum / Physics / Relativity / June 2007How does the photon's Electric Field generate electricity?
I presume that when a proton or electron absorb photons they get more excited (does this mean they oscillate more?) and they move away from each other by a distance(or r^2 distance?) equal to the excitation (this way a dead battery gets charged from solar transistors)? How does a negative charge dissacociate from positive charge (when recharging a battery) when the electron being excited (solar transistor) is perhaps 10 feet away along the copper wire? So you have an excitation in the middle of a long wire that tells the entire series of charges to reverse direction from the positive terminal....how does this occur? On Jun 27, 1:56 pm, "g...@hotmail.com" <g...@hotmail.com> wrote: > I presume that when a proton or electron absorb photons they get more > excited (does this mean they oscillate more?) and they move away from [quoted text clipped - 8 lines] > entire series of charges to reverse direction from the positive > terminal....how does this occur? Electrical current will only be produced if the energy of the photon (hf) exceeds the material's work function. http://en.wikipedia.org/wiki/Photoelectric_effect > On Jun 27, 1:56 pm, "g...@hotmail.com" <g...@hotmail.com> wrote: > [quoted text clipped - 15 lines] > > http://en.wikipedia.org/wiki/Photoelectric_effect I just read:"if the energy exceeds the gag band...so that it can jump from the covalent band to the conduction band where the drift electrons displace" Dear guskz: On Jun 27, 10:56 am, "g...@hotmail.com" <g...@hotmail.com> wrote: > I presume that when a proton or electron absorb > photons they get more excited (does this mean > they oscillate more?) and they move away from > each other by a distance(or r^2 distance?) equal > to the excitation (this way a dead battery gets > charged from solar transistors)? Atoms / molecules absorb photons, particles (such as free electrons and free protons) scatter them. Which did you mean? Igor talked about the photoelectric effect, where electrons are bound to molecular structure. > How does a negative charge dissacociate from > positive charge (when recharging a battery) > when the electron being excited (solar > transistor) is perhaps 10 feet away along the > copper wire? The "dissociation" occurs by altering the ionization state of ions inside the battery. > So you have an excitation in the middle of > a long wire that tells the entire series of > charges to reverse direction from the positive > terminal....how does this occur? Electric potential. David A. Smith > Dear guskz: > [quoted text clipped - 27 lines] > > Electric potential. I think no electric potential from an excited electron in a plain copper wire would be created since: I read solar cells use p/n transistors/diodes therefore I presume an exicted charge needs to be "close" to the potential (potential difference)? Meaning if the wire was only electron ions(electron valences) in a plain copper wire then an excited electron, I "presume" would simply re-emit the photon or escape the copper(photoelectric effect)? P/N transistor I think is like a battery where a "sufficiently" exicted electron will generate sufficient energy to jump through the barrier(semi-insulator)that seperates the "more" positvie terminal from the negative terminal (or is it vice-versa)? > David A. Smith |
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