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Natural Science Forum / Physics / Relativity / April 2005F=MA appears to be incorrect
Newton's states; Force = Mass x Acceleration (f=ma). However, this law does not explain why an object dropped from any height will be deformed (by force) when impacting the Earth. At the moment of impact, the acceleration of an object is immediately reduced to ZERO, thus at that precise moment, force = zero. However, an egg dropped from a height of 5 feet will break when it impacts the floor, eventhough there is no force at the exact moment of impact. Therefore, there must be another element (a force), which causes the egg to break. Mathematically speaking, F=MA is incorrect, unless the added element of time is factored into the equation. At the precise moment of impact, acceleration is reduced to ZERO, yet time continues. Therefore is time really a force, as opposed to mass or acceleration ? The ultimate question is this, is time really "the force" which is merely altered by mass and or acceleration ? Details can be found at www.threexd.com Mark Oliver > Newton's states; Force = Mass x Acceleration (f=ma). However, this law does > not explain why an object dropped from any height will be deformed (by [quoted text clipped - 14 lines] > > Mark Oliver How have you not confused velocity with acceleration? > Newton's states; Force = Mass x Acceleration (f=ma). Actually Newton states: Force = Time derivative of Momentum F = dp/dt = d(mv)/dt > However, this law does > not explain why an object dropped from any height will be deformed (by > force) when impacting the Earth. At the moment of impact, the acceleration > of an object is immediately reduced to ZERO, thus at that precise moment, > force = zero. No, the acceleration is not immediately reduced to zero. As seen by us, during freefall of the object, its acceleration is constant. Upon impact, there is a huge acceleration in the opposite direction (deceleration) that brings the object to rest in a very small time interval, but not, like you seem to like to think, in zero time. When the bottom part touches the ground, two things start happening: (1) the bottom part drills itself into the ground and starts decelerating. The harder the ground, the shorter the penetration depth and the greater the deceleration. (2) A shock wave (with typically the speed of sound) is sent from the bottom part of to the top part. The wave takes some time to propagate, and as long as the front of the shock wave has not reached the top, the latter will nicely continue its journey down while the bottom is strongly decelerating. This causes the deformation of the object. > However, an egg dropped from a height of 5 feet will break > when it impacts the floor, eventhough there is no force at the exact moment > of impact. Therefore, there must be another element (a force), which causes > the egg to break. The deformation causes the egg to break. Dirk Vdm > Newton's states; Force = Mass x Acceleration (f=ma). Euler stated that, not Newton. Newton stated what can be expressed today F=dp/dt as Dirk has specified. This relation can be used to derive SR, given a very reasonable assumption. > However, this law does > not explain why an object dropped from any height will be deformed (by [quoted text clipped - 14 lines] > > Mark Oliver |
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