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Natural Science Forum / Physics / Relativity / July 2005relativity concerns
are there special relativiy concerns when dealing with dls? or c is taken as infinitly? Dear Jerry T: > are there special relativiy concerns when dealing > with dls? "dls" means what? > or c is taken as infinitly? Only when the velocities considered are much less than c. This allows Newton to provide accurate predictions. David A. Smith > Dear Jerry T: > > > are there special relativiy concerns when dealing > > with dls? > > "dls" means what? pcs why answering when you dont know > > or c is taken as infinitly? > > Only when the velocities considered are much less than c. This > allows Newton to provide accurate predictions. > > David A. Smith particle particle collision concerns, what about photon particle? Dear @echo off: >> Dear Jerry T: >> [quoted text clipped - 4 lines] > > pcs Still no idea what you mean. I assume you don't intend to communicate... Goodbye. <plonk> David A. Smith > Dear Jerry T: > > > are there special relativiy concerns when dealing > > with dls? > > "dls" means what? all right, you are nice photon - particle collision when in brownian motion > > or c is taken as infinitly? > > Only when the velocities considered are much less than c. This > allows Newton to provide accurate predictions. > > David A. Smith Dear Jerry T: >> Dear Jerry T: >> [quoted text clipped - 6 lines] > > photon - particle collision when in brownian motion Then the answer is "yes", barely. The photoelectric effect shows marked effect when the photoemitting surface is heated. Additionally, characteristic emissions spectra of "stuff" is broadened by increasing temperature. But the gamma of velocities associated with even 25000000 K is not too terribly much larger than 1. And "photon - particle collision" does require a charged particle as the particle, and "collision" isn't a very useful term here. David A. Smith > Dear Jerry T: > [quoted text clipped - 13 lines] > Additionally, characteristic emissions spectra of "stuff" is > broadened by increasing temperature. light comes usually from a laser, T is constant > But the gamma of velocities associated with even 25000000 K is > not too terribly much larger than 1. > > And "photon - particle collision" does require a charged particle > as the particle, and "collision" isn't a very useful term here. where is your "yes" and why is photon - particle not a collision, smashed photons are scattered all over plalces > David A. Smith please do more answer ta me Dear Jerry T: >> Dear Jerry T: >> [quoted text clipped - 16 lines] > > light comes usually from a laser, T is constant Photon energy absorbed by a conduction-band electron provide the photoelectric effect. Temperature affects "cutoff voltage" when a quenching bias is applied. Just as light emitted by real matter is broadened by temperature, so to is absorption of photons by orbital electrons, when the atom/molecule is moving. >> But the gamma of velocities associated with even >> 25000000 K is not too terribly much larger than 1. [quoted text clipped - 4 lines] > > where is your "yes" Photoelectric effect. Emission (and hence absorption) spectral broadening. > and why is photon - particle not a collision, > smashed photons are scattered all over plalces The photon is completely absorbed, and some finite time later, a new photon may-or-may not be emitted. Examples would be orbital-transistion, thermal, or Compton scattered photons. > please do more answer ta me Hopefully I was more clear this time. David A. Smith > Dear Jerry T: > [quoted text clipped - 22 lines] > photoelectric effect. Temperature affects "cutoff voltage" when > a quenching bias is applied. ok maybe, but you run away farther from the issue are there any realtivity concerns? > Just as light emitted by real matter is broadened by temperature, > so to is absorption of photons by orbital electrons, when the > atom/molecule is moving. there are no absortions at all, only geometry what are the "orbital electrons"? > >> But the gamma of velocities associated with even > >> 25000000 K is not too terribly much larger than 1. [quoted text clipped - 6 lines] > > Photoelectric effect. what has the photoelectric effect to do with relativity? > Emission (and hence absorption) spectral broadening. no absortion, to be more simpler, only reflections,. take them 100% > > and why is photon - particle not a collision, > > smashed photons are scattered all over plalces > > The photon is completely absorbed, and some finite time later, a how long times it takes? a period, a phase shift or somthing? > new photon may-or-may not be emitted. lets say there is a good chance to be emited, take it 100% > Examples would be > orbital-transistion, you just said electrons has no distict orbits but they are a kind of projection of the nucleus, am i cool? > thermal, forget the thermals, we simplify to constant temperature as been said before > or Compton scattered photons. compton deals with x-rays, we use cheap red lasers > > please do more answer ta me > > Hopefully I was more clear this time. yes, a bit, thanks > David A. Smith please tell me where are the relativity concernes if any i think more on velocitys, angles, dilations/contractions, geometrys and stuff like that please do more answer ta me thank you very much Dear Jerry T: >> Dear Jerry T: >> [quoted text clipped - 26 lines] > > are there any realtivity concerns? Temperature has two effects in photoemission. 1) the atoms/molecules (and so the electrons in the matrix) have various velocities, 2) the work function of the surface is met (in part or in whole) by the energy represented by the stored heat. Relativity plays a very small part, but a part that can be measured/detected. >> Just as light emitted by real matter is broadened by >> temperature, so to is absorption of photons by orbital >> electrons, when the atom/molecule is moving. > > there are no absortions at all, only geometry Photons are absorbed by electrons of atoms. These produce what are called "absorption bands", and are characteristic of different materials. > what are the "orbital electrons"? In hydrogen, this is the electron that is "bound" to the nucleus by releasing a characteristic photon (ground state, 13 and change eV, if I recall correctly). And it can transistion to different orbtial states from the ground state, by absorption of lower energy photons. Or be blasted completely out of the nucleus' grasp by a photon energy higher than the electron's binding energy. >> >> But the gamma of velocities associated with even >> >> 25000000 K is not too terribly much larger than 1. [quoted text clipped - 8 lines] > > what has the photoelectric effect to do with relativity? It affects the cutoff of photo electrons, due in part to molecular motion. >> Emission (and hence absorption) spectral broadening. > > no absortion, to be more simpler, only reflections,. take > them 100% *Not* reflections. The polarization is (in general) entirely random. >> > and why is photon - particle not a collision, >> > smashed photons are scattered all over plalces [quoted text clipped - 3 lines] > > how long times it takes? a period, a phase shift or somthing? It depends on too much. It is akin to the same process that is an "atomic clock". >> new photon may-or-may not be emitted. > [quoted text clipped - 5 lines] > you just said electrons has no distict orbits but they > are a kind of projection of the nucleus, am i cool? I did NOT say that electrons have "no distinct orbits". They simply don't orbit according to the Bohr model, and the rest mass of the nucleus-plus-electron is less than the rest mass of the nucleus alone and the electron alone. >> thermal, > > forget the thermals, we simplify to constant temperature as > been said before Every body at other than 0 K is constantly emitting thermal photons. We "shout" our temperature at each other. Two bodies in thermal equilibrium simply send (on average) the same numbers and energies of photons. >> or Compton scattered photons. > > compton deals with x-rays, we use cheap red lasers "Cheap red lasers" fired head on into an electron beam of sufficient energy, makes TeV gamma photons used in photon-photon interactions. Actually, I think they use a slightly shorter wavelength than red for this, but it is the same idea. The scattered photon gets up to a gamma-factor^2 boost in its energy... depending on scattering angle. ... > please tell me where are the relativity concernes if any > > i think more on velocitys, angles, dilations/contractions, > geometrys and stuff like that > > please do more answer ta me thank you very much I guess "we" need to know a little more about your intended application. What are you trying to accomplish? David A. Smith |
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