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Natural Science Forum / Physics / Relativity / August 2005



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francisco - 27 Aug 2005 21:52 GMT
can you imagine a system of base units* in which time was not included?

*the system of base units is the following:

quantity                                       name                symbol
time                                             second             s
length                                           meter               m
mass                                            kilogram            kg
amount of substance                     mole                  mol
thermodynamic temperature          kelvin                K
electric current                              ampere              A
luminous intensity                          candela              cd
Bilge - 28 Aug 2005 02:23 GMT
francisco:
>can you imagine a system of base units* in which time was not included?
 Sure, geometerized unites:

length             meters
time               meters
velocity           dimensionless
acceleration       1/meters
force              dimensionless
mass               meters
electric charge    meters
angular momentum   meters^2
pressure           1/meters^2
energy             meters



>*the system of base units is the following:
>
[quoted text clipped - 6 lines]
>electric current                              ampere              A
>luminous intensity                          candela              cd
francisco - 28 Aug 2005 04:15 GMT
i was thinking of something along the same line:

i was thinking of defining the second as a specified length (299,792,458m)
of the path travelled by light in vacuum.

so that 1s = 299,792,458m

the meter of course would then be difined (as it is currently defined) as
the length of the path traveled by light in vacuum in 1 / 299,792,458 of a
second.

currently the second is defined as the duration of 9,192,631,770 vibrations
of a (specified) radiation emitted by a (specified) isotope of the cesium
atom.

vibration or a periodic oscillation of the radiation emitted by the isotope
is a periodic movement to and fro between two points. let the length of a
single movement to and fro between two points of the radiation emitted by
the isotope = L.

does this mean that 9,192,631,770L = length = 1s?

how fast is one oscillation?
what is the length of L?
if the speed of one oscillation = c, does that mean that 9,192,631,770L =
299,792,458m?

> francisco:
> >can you imagine a system of base units* in which time was not included?
[quoted text clipped - 22 lines]
> >electric current                              ampere              A
> >luminous intensity                          candela              cd
Bilge - 29 Aug 2005 14:25 GMT
francisco:
>i was thinking of something along the same line:
>
[quoted text clipped - 6 lines]
>the length of the path traveled by light in vacuum in 1 / 299,792,458 of a
>second.

 Right. But since the second itself was originally defined in
terms of distance anyway, it shouldnt seem strange. Before the
second was defined in terms of an atomic transition, it was
defined as 1/31,556,925.9747 of the year 1900, which is just
the distance the earth traversed as it went around the sun that
year.

>currently the second is defined as the duration of 9,192,631,770 vibrations
>of a (specified) radiation emitted by a (specified) isotope of the cesium
>atom.

>vibration or a periodic oscillation of the radiation emitted by the isotope
>is a periodic movement to and fro between two points. let the length of a
>single movement to and fro between two points of the radiation emitted by
>the isotope = L.
>
>does this mean that 9,192,631,770L = length = 1s?

 No. The `L' you want is the wavelength. There is nothing oscillating
back and forth in the way you are picturing the to-and-fro motion.

>how fast is one oscillation?

 I'm not sure what you mean, but c = \lambda\nu, where \lambda is the
wavelength. The way the correct frequency is found so that the definition
isnt circular, is by tuning the system to peak the resonance. The
resonance depends only on the atomic structure, so the peak will always
occir at the same frequency. Since the definition of a second is completely
arbitrary, the number of cycles, 9,192,631,770, was chosen to coincide as
closely as possible with the older definition.

>what is the length of L?

 It's the wavelength of the microwave signal from the cesium.

>if the speed of one oscillation = c, does that mean that 9,192,631,770L =
>299,792,458m?

 If the speed of light is `c', then that relation is correct.

   c = \lambda\nu
 
The speed of an oscillation doen't really make sense. I get a wavelength
of 3.26 cm, which is in the microwave regime. It would also be related
to the approximate dimensions of the resonant cavity.
 
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