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RP - 26 Sep 2005 05:38 GMT During the course of the recent LET debates, I considered several possible alternatives to measuring length via mechanical means, hoping to by pass the simultaneity issue. While I failed to manage this, one promising prospect arose, though being inconsistent with the many other mechanical methods, I doubt that the problem is as clear as it seems. It is:
Suppose that an overhead tram carriage is moving parallel to a perfectly flat surface below. From the ends of the carriage are suspended identical spherical weights, by massless strings. Their constant heights above the flat surface are equal. There are an infinite number of clocks situated along the carriage and along the flat surface, all of which are e-synced to the other clocks in their respective frames. The threads are cut simultaneously wrt the carriage frame, and the spheres fall, striking the flat surface simultaneously. Wrt the Earth frame the lagging sphere strikes the surface before the leading sphere strikes. The reason for this in terms of LET, assuming the Earth as the ether frame for the purpose of argument, is that the release wasn't actually simultaneous; the carriage clocks aren't synchronized in the Earth frame.
That's simple enough. The SR version varies only in the fact that either frame may regard itself to be the ether frame. Thus whether the spheres strike simultaneously or not is a matter of opinion.
But suppose the spheres are joined by a massless rod, and that the two strings extend from the spheres to a common junction just before attaching to the carriage at a single point, thus forming a triangular support. When the single suspending string is cut, the spheres will again strike simultaneously wrt the carriage frame, and again the lagging sphere will strike before the leading sphere wrt Earth frame.
While the results as perceived from the carriage frame are understandable in the contexts of both LET and SR, the results as perceived from the Earth frame are rather perplexing. What is it that continues to suspend the leading sphere even after lagging sphere has begun its fall? I see no clear resolution to the paradox within either the LET or SR contexts. Could they both be wrong in principle?
Richard Perry
RP - 26 Sep 2005 06:39 GMT > During the course of the recent LET debates, I considered several > possible alternatives to measuring length via mechanical means, hoping [quoted text clipped - 36 lines] > > Richard Perry I've thought this thing out and the only possible solution is that the theories are in fact wrong.
A direct contradiction can easily be derived by performing the two versions of the experiment simultaneously wrt the carriage. To wit: The first set of spheres are arrange adjacent to the second set so that there are two spheres at each end, and these pairs are aligned along the y axis. All three strings are cut simultaneously wrt the carriage frame. Wrt Earth frame the lagging independently hanging sphere will strike first, the two coupled spheres second, and the leading independently hanging sphere last. This is because this is sequence in which the strings are cut in the Earth frame. However, wrt the carriage frame all four spheres must strike simultaneously. But since the two lagging spheres strike the same x position, side by side along y, they must also strike simultaneously wrt the Earth frame because there is no clock offset along y. This is in clear contradiction with the Lorentz transform. Special Relativity is thus necessarily wrong. In LET, however, the Lorentz transform only provides apparent measures, and thus it has a ticket out of this dilemma. If we assume that the Earth really is at rest in the ether frame, then we can derive a consistent outcome. If the carriage clocks are really offset wrt each other, then the four spheres will not all strike simultaneously, and won't even be perceived to strike simultaneously. Instead, the carriage observer, who expected them to strike simultaneously concludes from the fact that they didn't, that his clocks are not synchronized, i.e. that he is not at rest wrt the ether. He can in fact determine his speed wrt the ether with this experiment. The special relativistic carriage observer must draw the same conclusion, namely that there is an ether, and that he is moving wrt it. LET is the correct version of the theory, and the gravitational field breaks the symmetry that hides the ether frame. OTOH, it would seem that the gravitational field is the ether, thus we can expect ether drag due to superposition of various gravitational sources. This is not inconsistent with General relativistic frame dragging effects, nor with Einstein's determination that the matter in the universe is the medium, in opposition to the previous speculation of the ether being a separate entity, fixed in all its parts, and different from ponderable masses. Keep in mind that this is all speculation at this point, though the argument seems relatively valid to me.
Richard Perry
wespe@operamail.com - 26 Sep 2005 11:27 GMT (I think), After the string at the junction is cut, the two mechanical signals will not travel at the same speeds on the two strings, as seen on Earth. When the first signal reaches the lagging sphere, the sphere will start falling. Now another mechanical signal starts traveling on the rod connecting the spheres. But before this signal reaches the leading sphere, the leading sphere will have started falling. Or, at best, the two signals will reach the leading sphere at the same time. The rod will have to stretch a bit as seen as on Earth, but that's OK because there are no rigid rods in relativity. Note that even though the events are non-simultaneous as seen on Earth, there can be no casual connection between the two events, because that would require a faster than light signal.
RP - 26 Sep 2005 13:35 GMT > (I think), > After the string at the junction is cut, the two mechanical signals [quoted text clipped - 9 lines] > casual connection between the two events, because that would require a > faster than light signal. In this example the accelerating force is already there. The counter force, provided by the string, would have to remain even after the source of the tension is removed. Thus the inertial mass of the string would have to be infinite for a brief period. Given the EP, this would seem to be a bit contradictory, since during the period that the sphere is suspended after the cut, the Earth would suffer infinite acceleration toward the severed string.
Suppose the spheres are suspended by in equilibrium positions electromagnetic fields whose source is some portion of the carriage. In this case we can certainly see the restraining force continuing even after the source of the field has shut down, since the field is a local phenomenon, a property of space, it must radiate past the sphere before ceasing to act on it. How, OTOH, does this principle apply to the strings?
Richard Perry
Sue... - 26 Sep 2005 13:39 GMT > > (I think), > > After the string at the junction is cut, the two mechanical signals [quoted text clipped - 24 lines] > phenomenon, a property of space, it must radiate past the sphere before > ceasing to act on it. How, OTOH, does this principle apply to the strings? http://hyperphysics.phy-astr.gsu.edu/hbase/electric/elefor.html
Sue...
> Richard Perry wespe@operamail.com - 26 Sep 2005 14:21 GMT I'm sorry I don't exactly follow you. In order for the cut to have any effect on the spheres, mechanical waves has to travel from the cut point to the spheres. During this period the spheres will look like supported by floating strings, but that's not an issue exclusive to this gedanken, same applies to a single sphere hanged on a ceiling.
Sue... - 26 Sep 2005 11:48 GMT > During the course of the recent LET debates, I considered several > possible alternatives to measuring length via mechanical means, hoping [quoted text clipped - 35 lines] > > Richard Perry Synchonize the clocks with a bag of marbles and equal lengths of garden hose. Unless marble thieves carry knives to cut the hoses, then the bogus theories will be shown for what they are.
http://tf.nist.gov/timefreq/time/commonviewgps.htm
Sue...
http://tf.nist.gov/timefreq/time/commonviewgps.htm
Tom Roberts - 26 Sep 2005 16:07 GMT > But suppose the spheres are joined by a massless rod, and that the two > strings extend from the spheres to a common junction just before [quoted text clipped - 6 lines] > understandable in the contexts of both LET and SR, the results as > perceived from the Earth frame are rather perplexing. Not really. You must consider the speed of sound in the rod connecting the two spheres. It is clearly isotropic in the rest frame of the rod, which is the rest frame of the carriage to which it was attached. That means that in the carriage frame the two spheres start to fall simultaneously. So this is no change from your previous gedanken.
> What is it that continues to suspend the leading sphere even after > lagging sphere has begun its fall? The ANisotropy of the speed of sound in the moving rod, as seen in the Earth frame, combined with the fact that the leading sphere is moving away from the sound wave and the lagging sphere is moving toward it.
>I see no clear resolution to the > paradox within either the LET or SR contexts. You forgot to consider the sound waves in the rod, and how they propagate in the earth frame toward the moving spheres.
> Could they both be wrong > in principle? I suppose it is possible, but your gedanken has no ability to show it. These are physical theories which have been proven to be self-consistent[#], so no "in principle" argument can invalidate them. But they are physical theories, and experiment could certainly invalidate them (but to date no experiment has done so, within their domain of validity).
[#] Well, as self-consistent as is Euclidean geometry, and as self-consistent as is real analysis.
> I've thought this thing out and the only possible solution is that > the theories are in fact wrong. Nonsense. You just did not include all relevant facts in your analysis.
I have yet to see a valid argument from exhaustive enumeration around here. Invariably the people who attempt such arguments are woefully unprepared to make a truly exhaustive enumeration. This is merely one more instance of that. <shrug>
So whenever you see the phrase "the only possible solution...", it is almost certainly wrong.
Tom Roberts tjroberts@lucent.com
RP - 26 Sep 2005 19:00 GMT >> But suppose the spheres are joined by a massless rod, and that the two >> strings extend from the spheres to a common junction just before [quoted text clipped - 51 lines] > So whenever you see the phrase "the only possible solution...", it is > almost certainly wrong. Thanks Tom. I see that you have no further insight than afforded by the transform on a macroscopic scale. I'm looking for details. How does the severed string manage to suspend the sphere for any interval at all? This seems like a bootstrapping effect. The string holds itself up with enough extra force to hold the sphere as well. Where is the reaction force?
Richard Perry
Richard Perry
russell@mdli.com - 26 Sep 2005 19:06 GMT [snip]
> Thanks Tom. I see that you have no further insight than afforded by the > transform on a macroscopic scale. I'm looking for details. How does the > severed string manage to suspend the sphere for any interval at all? This is simple. The severed end is accelerated by the tension remaining in the string (between it and the sphere) and for a certain time the tension remains, as this end is whipped forward and downward. And since the tension does remain in the string, the sphere is supported. For a only millisecond or so, but that's sufficient.
> This seems like a bootstrapping effect. The string holds itself up with > enough extra force to hold the sphere as well. Where is the reaction force? The inertia of the string itself. The acceleration that it undergoes is huge.
wespe@operamail.com - 26 Sep 2005 21:16 GMT ...
> Thanks Tom. I see that you have no further insight than afforded by the > transform on a macroscopic scale. I'm looking for details. How does the > severed string manage to suspend the sphere for any interval at all? > This seems like a bootstrapping effect. The string holds itself up with > enough extra force to hold the sphere as well. Where is the reaction force? Let me try again. You need a simple setup to see this, just suspend a weight on a string tied to the ceiling. Before cutting anything, try to pull the weight down a bit. A mechanical wave travels on the string upwards (at the speed of sound in the string, depending on elasticity of the string), the wave gets reflected at top, and returns back to the weight. This is when the reaction force occurs. I imagine that even during equilibrium state, this delayed reaction is occuring. Now when you cut the string, this looseness starts traveling on the string downwards, meets the wave coming from down, and is reflected at some mid-point, but this time the reflection is at an open end, so that there is no reaction force, and weight starts falling.
Tom Roberts - 26 Sep 2005 23:20 GMT > How does the > severed string manage to suspend the sphere for any interval at all? You confuse yourself with your words, by using an active verb ("suspend") for what is actually a passive situation (does not fall).
Just think about it: suspend a rock from a support by a string. When you cut the string at the top, the rock cannot possibly start falling until the tension force of the string is removed, and that cannot happen until the longitudinal sound wave (generated by the cutting) reaches the weight.
The same thing happens in your gedanken, but more subtly.
> This seems like a bootstrapping effect. The string holds itself up with > enough extra force to hold the sphere as well. No. After the top of the string is cut but the sound wave has not yet reached the rock, there is still an upward tension force on the rock that equals its weight, so the rock does not move. Ultimately this is determined by the inertia OF THE STRING.
Yes, you specified a "massless rod". How reasonable do you think that is? One unphysical assumption can destroy a gedanken....
Tom Roberts tjroberts@lucent.com
Paul Cardinale - 26 Sep 2005 16:15 GMT Your error is in assuming that both signals (i.e. the release) that travel from the support to the weights will be observed to travel at the same speed in both frames. From the carriage frame, they will travel at the same speed; from the Earth frame, they will travel at different speeds.
Paul Cardinale
Tom Roberts - 26 Sep 2005 16:38 GMT > Your error is in assuming that both signals (i.e. the release) that > travel from the support to the weights will be observed to travel at > the same speed in both frames. From the carriage frame, they will > travel at the same speed; from the Earth frame, they will travel at > different speeds. That goes the wrong way, and would lead one to conclude that in the earth frame the front weight would start falling before the lagging weight.
You must also remember that in the Earth frame the front weight is moving away from the signal, and the lagging weight is moving toward the signal. This is a larger difference than the anisotropy in the signal speeds in the Earth frame.
In the Earth frame, the lagging (rear) weight starts falling before the front (leading) weight. This, of course, is simply "length contraction" viewed from the carriage frame (because that's the frame in which the two events are simultaneous).
Tom Roberts tjroberts@lucent.com
Paul Cardinale - 26 Sep 2005 20:19 GMT Sorry, I misused "speed". The quantity that I meant to refer to was not the speed of the signal with respect to the Earth frame, but the speed of signal in the support as observed from the Earth frame; i.e. 'ds' being on the support and 'dt' being in the Earth frame (is there even a name for such a quantity). I can see that would have been much better to refer to times instead of "speeds".
Paul Cardinale
Kees Roos - 26 Sep 2005 18:52 GMT > During the course of the recent LET debates, I considered several > possible alternatives to measuring length via mechanical means, hoping [quoted text clipped - 32 lines] > What is it that continues to suspend the leading sphere even after > lagging sphere has begun its fall? The results may be a bit counterintuitive. We can elaborate on your question: (there is no need to incorporate mechanical considerations) -What causes the lagging sphere to start falling before the suspending wire has been cut? - What precludes the leading sphere from starting to fall after the suspending wire has been cut?
The answer is: the rotated spacetime frame of reference of the embankment, relative to the tram frame.
> I see no clear resolution to the > paradox within either the LET or SR contexts. Could they both be wrong > in principle? There is no paradox. A paradox emerges when within a theory different solutions to a problem can be derived with different results. Both LET and SR give consistent solutions to this problem.
As I said, the result may be a bit counterintuitive, but there is no paradox.
> Richard Perry >  Signature Regards, Kees Roos
Bilge - 27 Sep 2005 02:35 GMT RP:
>During the course of the recent LET debates, I considered several >possible alternatives to measuring length via mechanical means, hoping [quoted text clipped - 6 lines] >identical spherical weights, by massless strings. Their constant heights >above the flat surface are equal. There are an infinite number of clocks [...]
>What is it that continues to suspend the leading sphere even after >lagging sphere has begun its fall? I see no clear resolution to the >paradox within either the LET or SR contexts. Could they both be wrong >in principle? In principle, it's possible to create as complex and contrived an example as one needs to give the outcome an appearance of being absurd. The moment you start invoking massless strings, perfectly rigid rods, infinite clocks, etc., you are violating the very physics the example was contrived to investigate. The rigid rod, in particular does it here, since what you're doing is trying to turn a spacelike interval into a timelike interval, so you can check something that relativity says you cant check.
The botton line is, the premises of special relativity are reasonable. The only real premise boils down to assuming that physics shouldn't change if you move across the street and that it's reasonable to expect the laws of physics to be the same tomorrow as they were today and yesterday, etc. The speed of light postulate only leads people to think that light has something to do with relativity, rather than the other way around. If the premises are reasonable, then all you can do is use the theory to predict the outcome of real experiments to test the theory. It's not surprising that a thought experiment will sound bizarre, since anything that is unfamiliar will sound bizarre. Hell, I think the idea of playing golf sounds bizarre and I even know people who play golf, so I fully expect relativity to make some predictions that appear less sensible than golf.
RP - 27 Sep 2005 17:52 GMT > RP: > > [quoted text clipped - 37 lines] > so I fully expect relativity to make some predictions that appear > less sensible than golf. That's a different perspective for sure, and I follow what you're saying. My only difficulty is trying to get correct advice on the subject. And though the subject heading specified "advice requested" Tom took that to mean "advice being offered". I even stopped to qualify my arguments with "this is just speculation", and yet he felt he had to flame me for presenting incorrect information as though I was proffering it as the bottom line of reality. So in return let me flame Tom back, and maybe you can tell me whether my arguments below are correct or incorrect.
I understand reaction forces and quite frankly, Tom is talking bullshit. The upward force on the sphere may instantaneously counter the force of gravity, but will have a progressive reduction in magnitude over time, beginning at the moment the string is cut. Here's a simple proof: Suppose that the downward force on the sphere is provided by its mechanical attachment to some rigid assembly (U shaped) that wraps around with two arms, the other arm being the one that the string is attached to. Now locate this system in free space. If both ends are simultaneously severed then both the sphere and the far end of the string will begin to accelerate simultaneously under the tension in the string. That is, wrt the frame of the center of gravity of the system. The sphere will not accelerate for any non-zero interval at a rate determined by the initial tension, because after the first infinitesimal instant the force will have been reduced. IOW, the entire string is going to contract simultaneously. If it helps the argument, then simply place an identical sphere at the other end of the string. We can imagine that these are bound to the bracket via electromagnets that are simultaneously switched off. There is now no severing of strings, OTOH both spheres will simultaneously accelerate (Assuming Newton) toward each other. We can't even talk about a sound wave propagating down the string causing the acceleration of these two masses, because the entire string, and the masses, are contracting simultaneously. Now if we release only one of the spheres in this system, then we must have exactly the same results when perceived from the accelerating frame of the center of gravity of the system. If the center of gravity of the system remained fixed in position wrt lab frame, as suggested by Tom, then we would have a violation of conservation laws on our hands. The released sphere would have accelerated while the other remained at rest. Thus there must be an acceleration of the bound sphere, along with the bracket to which it is bound that is simultaneous to the acceleration of the released sphere. IOW, the string in the original gedanken will not suspend the f.cking sphere at perfect rest at a height of h until such time as a sound wave can reach it. That's f.cking bullshit. It will partially counter the gravitational pull with a time-varying force, but won't null it completely, except, as I stated, for one infinitesimal instant at the start. Again, this is in a Newtonian context; Special Relativity is added below.
However, in this latter experiment with two spheres at the end of the same stretched string, when we take into account information delay (the speed of causality), per special relativity, then the center of the string cannot know that the electromagnets were switched off until a time r/c later, and thus there is a wave, an *causality wave* propagating at c, but not a sound wave. The proof is that this delay is independent of either the material or the tension that the material is under, and this is because the delay must precisely equal that of the offset between the end and middle clocks on the carriage wrt Earth frame.
It is light speed delays, independently of longitudinal mechanical compression waves that foils the gedanken. It would help greatly if the experts would get their f.cking facts straight.
The problem with the gedanken is independent of sound waves. We could easily adjust the elasticity of the strings to provide the desired simultaneous fall of the spheres wrt K'. The problem then reduces to the difference in the "apparent" speed of the sound waves horizontally and vertically along the string, the temporal offset over distance along the string being exactly exactly r/c. IOW, we could have used a laser at the midpoint of the carriage to sever a vertical string at the rear of the carriage, in which case we would have had to fire it earlier wrt K' (r'/c) in order to provide for both rear spheres falling simultaneously. However (r/c) the delay wrt K, is a different value, and corresponds to the disagreement in time intervals between the two frames. The gedanken fails, but the failure had not a god damn thing to do with sound waves, their presence is only incidental to the argument.
Now, although I've come to value your opinions above pretty much everyone elses around here, I wonder if you still believe, after all this debate about LET, that the Lorentz transform cannot be derived from Galilean relativity. This seems to be, in contrast to your sentiment, exactly what Lorentz did, so I wonder how you justify your opinion that it cannot be done? If you, like some of the other experts, are also leading me astray with false claims, then I don't have a chance in hell of getting the facts about relativity straight unless I simply derive them on my own from the transform, which seems to be what I'm consistently having to do anyway :)
Richard Perry
wespe@operamail.com - 27 Sep 2005 19:39 GMT Richard, Maybe you don't value my opinion much, but I have an observation you might want to consider: In the previous thread, the replies were all pointing out the same thing, the equality of LET and SR, but these answers weren't satisfying you and the discussion kept getting longer. I believe you now accept that LET and SR predict the same results. Now, knowing this, how would you reply differently than others did, to your own question in the previous thread? My point being, is it possible that you are rejecting the answers in this thread, for the same reason you did in the previous thread? That is, due to some misconception on your side. I would try to find out what that is, but you keep adding new elements which I have difficulty following.
RP - 27 Sep 2005 23:38 GMT > Richard, > Maybe you don't value my opinion much, but I have an observation you [quoted text clipped - 8 lines] > your side. I would try to find out what that is, but you keep adding > new elements which I have difficulty following. Primarily I was inclined to believe that there should be some observational difference between the two approaches based upon the fact that superluminal speed cannot possibly result in a causality violation within the LET version, but can within the SR version. I have yet to see this "apparent" contradiction sorted out. The only thing close to a solution that I've heard is that "Well nothing can go faster than light, so its a moot point". I don't see anything intrinsic to the transform that precludes it, however. Imaginary numbers appear when v>c. So what? We could form an equivalent to the transform for sound waves in a gas cloud. We would use sound clocks instead of light clocks, rulers would shorten via pressure differentials. Every observer could be made to measure the same speed of any sound wave through this gas cloud. Speeds greater than the speed of sound would produce imaginary numbers in our equations. This wouldn't however be taken notice of by the rays of sun passing through the cloud at c.
There are just a few issues that haven't been settled in my mind. If my original questions and descriptions weren't pedantic enough, then I can live with that. What I can't live with are inconsistent descriptions of the theory. Not only is it difficult sometimes to distinguish the experts from the cranks, but sometimes its difficult to distinguish the cranks from the experts. You'll have to read between the lines on that one :)
Richard Perry
wespe@operamail.com - 28 Sep 2005 12:58 GMT You have a point there, but who knows what those imaginary numbers can physically mean. Maybe laws of physics will reverse and it will be like time running backwards even in LET(assuming all processes are reversible). On the other hand, with SR/GR, there may be a slight possibility of backwards time travel with wormholes (or whatever) as speculated.
Tom Roberts - 28 Sep 2005 14:45 GMT > The upward force on the sphere may instantaneously counter the force of > gravity, but will have a progressive reduction in magnitude over time, > beginning at the moment the string is cut. No. The sphere cannot move until the tension on the string attached to the sphere is reduced or removed. That does not happen until the longitudinal sound wave from the other end of the string (where it was cut) reaches the end connected to the sphere. This is simple, basic, classical mechanics. That is what we MEAN by "longitudinal sound wave".
At base this is due to the inertia of the string, all along its length.
> Here's a simple proof: > Suppose that the downward force on the sphere is provided by its [quoted text clipped - 7 lines] > determined by the initial tension, because after the first infinitesimal > instant the force will have been reduced. Your physical situation is not at all clear.
But imagine a violin bow with a tightly-stretched string, in free space, at rest in an inertial frame. Start with everything in equilibrium:
|.................................| string | | |=================================| bow End A End B
Now sever the string from the bow at End A (cut it cleanly, without imparting any momentum to string or bow). Immediately a sound wave propagates down the string toward end B, and a sound wave also propagates down the bow toward end B. The wave in the string is moving mass toward end B (and the entire string gets progressively shorter as its tension is relieved), and the wave in the bow is moving mass toward end A (and the entire bow gets progressively longer as its compression is relieved). The center of mass of the entire system remains fixed throughout. End B does not move relative to the initial inertial frame until one of the sound waves reaches it -- that is inherently required by continuity and the fact that it was initially at rest and in equilibrium.
Once the sound waves reach end B, they reflect and ringing occurs....
Nothing in that description changes if you attach a sphere to End B. If you omit the bow, and create the tension in the string by attaching End A to a support and have a "gravitational force" A->B on the sphere (and string), the description of the string is unchanged (except for the minor change due to the "gravitational force" on the string).
> IOW, the entire string is > going to contract simultaneously. Nonsense. Strings simply DO NOT BEHAVE THAT WAY. They propagate longitudinal sound waves. IOW: strings are not clairvoyant, and one end does NOT know what the other end is doing until the sound wave from the other end arrives. <shrug>
This is all simple, basic, classical mechanics. No SR or GR appears in this entire message.
> [...] Tom Roberts tjroberts@lucent.com
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