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Natural Science Forum / Physics / Relativity / February 2006



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Einstein's Hypnotists Make Fun of the Zombie World

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Pentcho Valev - 24 Feb 2006 16:45 GMT
Problem 25 on p. 51 in

http://www.courses.fas.harvard.edu/~phys16/Textbook/ch10.pdf :

"Two spaceships float in space and are at rest relative to each other.
They are connected by a string....At a given instant, the spaceships
simultaneously start accelerating....with the same
acceleration.....Will the string eventually break?"

The solution is on p. 69 and the zombie world reads:

"To an observer in the original rest frame, the spaceships stay the
same distance, d, apart....After a long enough time,......the string
will be stretched by a large factor. Therefore, it will break."

Suddenly it occurs to the zombie world that the stretching string, like
any other stretching string, gradually gets thinner, and Einstein's
theory predicts that the same thinning will be observed by any
observer, even the observer in the original rest frame. Then the zombie
world, full of malicious joy, imagines the following scene. For the
observer in the original rest frame the length of the string remains
constant but the thickness gradually disappears. The observer is
terrified, gets a massive heart attack and dies.

Pentcho Valev
tdp1001@gmail.com - 25 Feb 2006 04:22 GMT
> Problem 25 on p. 51 in
>
[quoted text clipped - 19 lines]
> constant but the thickness gradually disappears. The observer is
> terrified, gets a massive heart attack and dies.

Zombies are EXTREMELY hard to kill,
but I think Pentcho Valev
might be able to kill a few.

As sentient beings know
Zombies can't think,
and all they do is follow geodesic paths.

It looks like Pentcho Valev is
who can think and affect his environment,
is forging a geodesic path
for Zombies that leads them into a black hole.

--
Tom Potter
http://no-turtles.com
http://photos.yahoo.com/tdp1001
http://spaces.msn.com/tdp1001
http://tom-potter.blogspot.com
The Ghost In The Machine - 25 Feb 2006 07:00 GMT
In sci.physics.relativity, tdp1001@gmail.com
<tdp1001@gmail.com>
wrote
on 24 Feb 2006 20:22:14 -0800
<1140841334.905882.161100@u72g2000cwu.googlegroups.com>:

>> Problem 25 on p. 51 in
>>
[quoted text clipped - 10 lines]
>> same distance, d, apart....After a long enough time,......the string
>> will be stretched by a large factor. Therefore, it will break."

The logic is suspect.  First, "simultaneity" cannot be proven;
it depends on the observer.  Second, the tension in the string is
a factor in their acceleration; if one replaces the string with
a *spring* one will see that the spacecraft will accelerate towards
each other, absent expenditure of fuel.

>> Suddenly it occurs to the zombie world that the stretching string, like
>> any other stretching string, gradually gets thinner, and Einstein's
[quoted text clipped - 12 lines]
> Zombies can't think,
> and all they do is follow geodesic paths.

Hooloovoos notwithstanding, that's all light can do.

> It looks like Pentcho Valev is
> who can think and affect his environment,
> is forging a geodesic path
> for Zombies that leads them into a black hole.

If one kills SR one needs to replace it.  Any suggestions between
the two of you?

There are some interesting candidates already.

[1] c'=c+v [Greenfield].  Classic theory.

[2] BaTh, which appears to be a modified c'=c+v with gaseous
attenuation, promoted by H. Wilson.

[3] An anti-theory from Hexenmeister which looks like [1] but is not.

[4] A probabilistic particle jump theory from Louis Savain which
postulates that a cubic lattice holds all particles, and that
the particles therein jump from point to point at lightspeed.

[5] Kenseto's IRT, which is an extension of SR while
simultaneously (?) postulating absolute time.

[6] The Law of Lever, by dedanoe.

One also has to at least try to account for the following.

[1] (Compton scattering.)  A photon hurtles towards an
electron, and dislodges it towards a series of detectors.
The theory should correctly predict the results -- in
particular a probability curve for the angle of deflection
(the general idea would be much like Rutherford's famous
experiments) and the energies.

[2] (LHC) A proton is -- somehow -- given 7 TeV of energy,
and constrained to a 27 km ring via magnetic fields.
How fast will it go around?  How much energy will it lose
while going around?  If it hits an antiproton going in
the opposite direction, what results?

[3] A spaceborne pi meson hits something in the upper
atmosphere (25km-100km) up, shattering it.  One of the
products is known to be a muon, which ends up going through
a sea-level detector.  What is the energy of that muon,
and how long will it to take to decay?

[4] (Twin Paradox) An earthbound muon is constrained to
a storage ring, moving fast.  Another muon is constrained
to a storage ring, moving slowly.  What happens?

[5] (Michelson-Morley/Miller) A laser hits a half-silvered
mirror; each resultant beam hits another mirror.  The
resultant beams ultimately combine in an interferometer.
The entire apparatus, laser, mirrors, and all, is placed
on a smoothly, very slowly rotating turntable.  Assuming
measurements are conducted with the turntable motionless,
how many fringes will shift in the interferometer, as a
function of laser wavelength and path length?

[6] (Pound-Rebka) A beam of light falls down a tower.  Estimate the
wavelength at the bottom of the tower, as a function
of tower height, gravitational field, lightspeed, and
original wavelength.

[7] (Hafele-Keating) Two pairs of clocks are synchronized.
One pair is then split by having one fly eastbound around
the world; the other pair is split by having one fly westbound.
How much will the clocks vary upon their return, assuing
flight schedules are known using standard commercial aviation/shipment?

[8] (Cassini mission time query) What time is it, and how
does it vary as the spacecraft moves in its orbit, and the
Earth moves in *its* orbit?

[9] Explain the observations surrounding a supernova; these
include a neutrino burst and glowing brightly for some
weeks, then fading from sight and eventual observation
of a nebula, some of them rather pretty.

[10] (Pioneer anomaly).  The Pioneer spacecraft is showing
a slight anomaly in its flightpath.  Explain that anomaly.

[11] Explain the AQL1493 lightcurve.  (SR cannot do this, at
least directly; I suspect the cause lies elsewhere.  Note that
a theoretical binary will show a U-shaped light/time curve given
the right parameters of orbit and distance from Earth.)

[12] Explain various dual neutron star orbiting binary observations,
some of them extremely interesting.

[13] Does Cygnus X-1 have a black hole?

[.sigsnip]

Signature

#191, ewill3@earthlink.net
It's still legal to go .sigless.

Pentcho Valev - 25 Feb 2006 07:24 GMT
> In sci.physics.relativity, tdp1001@gmail.com
> <tdp1001@gmail.com>
[quoted text clipped - 48 lines]
>
> If one kills SR one needs to replace it.

This is misleading. You have a false principle - of constancy of the
speed of light - the speed of light does not depend on the speed of
source or observer. Since it is false, it should be replaced with the
true principle of variability of speed of light - the speed of light
does depend on the speed of source or observer. Then, of course, the
corollaries of the false principle will have to be replaced with the
corollaries of the true principle. And that is all you should do.

Pentcho Valev
JanPB - 25 Feb 2006 07:52 GMT
> This is misleading. You have a false principle - of constancy of the
> speed of light -

Why is it false?

--
Jan Bielawski
Hexenmeister - 25 Feb 2006 12:50 GMT
>> This is misleading. You have a false principle - of constancy of the
>> speed of light -
>
> Why is it false?

Empirical data and the PoR.
  "But the ray moves relatively to the initial point of k,
when measured in the stationary system, with the velocity c-v..." --  
Einstein.
Androcles.
Lloyd Parker - 25 Feb 2006 12:59 GMT
>>> This is misleading. You have a false principle - of constancy of the
>>> speed of light -
>>
>> Why is it false?
>
>Empirical data

ALL data shows the speed of light in a vacuum is constant.

>and the PoR.

Another falsehood.

>   "But the ray moves relatively to the initial point of k,
>when measured in the stationary system, with the velocity c-v..." --  
>Einstein.
>Androcles.
The Ghost In The Machine - 25 Feb 2006 20:00 GMT
In sci.physics.relativity, Lloyd Parker
<lparker@emory.edu>
wrote
on Sat, 25 Feb 06 12:59:43 GMT
<dtq5un$sdb$3@leto.cc.emory.edu>:

>>>> This is misleading. You have a false principle - of constancy of the
>>>> speed of light -
[quoted text clipped - 4 lines]
>
> ALL data shows the speed of light in a vacuum is constant.

I'm not 100% sure of that -- 99%, maybe.  All peer-reviewed
data might show that, for instance, but there was some
information about a year or so back that suggested
quantum tunnelling in an odd experiment goes faster
than light, through a gap in a metal (?) cube.  Also,
"tired-light" theories -- in which a light quantum takes
time to travel, as measured in its own reference frame --
have been discredited.  (Or one can do a theoretical
computation using the Lorentz, carefully eliding a
division by zero at the apporpriate spot.)

And of course Hexenmeister is apparently of the opinion
that various effects -- AQL1493 and Cassini, plus some
theoretical computations regarding Sagnac's effect --
show c'=c+v and/or absolute time, but the last I looked
none of them has been accepted by the laypress, nor has
the laypress expostulated a breakthrough in science by
scientists using them.  (There have been some reports of
interesting neutron star-pairs, though; such are accepted,
as far as I read the articles, as very definitive evidence
for General Relativity.)

[rest snipped]

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N:dlzc D:aol T:com (dlzc) - 25 Feb 2006 20:05 GMT
Dear The Ghost In The Machine:

> In sci.physics.relativity, Lloyd Parker
> <lparker@emory.edu>
...
>> ALL data shows the speed of light in a vacuum
>> is constant.
[quoted text clipped - 6 lines]
> goes faster than light, through a gap in a
> metal (?) cube.

What is it about a metal cube, gap or not, that you think is a
vacuum?  If you research total internal reflection, you'll find
that "something about" light *must* travel FTL through the less
dense medium, to know whether or not it is to be totally
internally reflected.

Quantum behaviors confound any classical theory.

David A. Smith
The Ghost In The Machine - 25 Feb 2006 23:00 GMT
In sci.physics.relativity, N:dlzc D:aol T:com (dlzc)
<N>
wrote
on Sat, 25 Feb 2006 13:05:35 -0700
<WL2Mf.711$fL3.683@fed1read01>:
> Dear The Ghost In The Machine:
>
[quoted text clipped - 17 lines]
> dense medium, to know whether or not it is to be totally
> internally reflected.

I'll admit to some confusion on the matter.  Presumably, there's
enough discrepancies that, absent more data, one is bound to
suggest that the communication is either immeasurable given
the method described, or at lightspeed within measurement error.

> Quantum behaviors confound any classical theory.

Aye.  I for one find quantum entanglement particularly interesting.

> David A. Smith

Signature

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It's still legal to go .sigless.

N:dlzc D:aol T:com (dlzc) - 26 Feb 2006 02:31 GMT
Dear The Ghost In The Machine:

> In sci.physics.relativity, N:dlzc D:aol T:com (dlzc)
> <N>
...
>>> I'm not 100% sure of that -- 99%, maybe.  All
>>> peer-reviewed data might show that, for
[quoted text clipped - 18 lines]
> immeasurable given the method described,
> or at lightspeed within measurement error.

c constrains the bulk... not the quanta.

>> Quantum behaviors confound any
>> classical theory.
>
> Aye.  I for one find quantum entanglement
> particularly interesting.

Yep.  But you don't have to look any further than
self-interference (aka. diffraction) for some real mysteries...

David A. Smith
Hexenmeister - 25 Feb 2006 23:09 GMT
> Dear The Ghost In The Machine:
>
[quoted text clipped - 20 lines]
>
> David A. Smith

Dear The David A. Smith,
You are a moron, but you are used to it by now.
Androcles.
Hexenmeister - 25 Feb 2006 23:09 GMT
> In sci.physics.relativity, Lloyd Parker
> <lparker@emory.edu>
[quoted text clipped - 12 lines]
>
> I'm not 100% sure of that -- 99%, maybe.

Data is open to interpretation.
Still, what would you know, you couldn't set your watch by Cassini
time now and be 14 seconds right in May.
 http://www.androcles01.pwp.blueyonder.co.uk/Synchronize/Synchronize.htm
[rest snipped]
Androcles.
Hexenmeister - 25 Feb 2006 23:09 GMT
>>>> This is misleading. You have a false principle - of constancy of the
>>>> speed of light -
[quoted text clipped - 4 lines]
>
> ALL data shows the speed of light in a vacuum is constant.

Don't be silly.

High school algebra:

x² + y² + z² =  c²t²               Einstein
xi² + eta² + zeta² = c²tau²        Einstein

tau = (t-vx/c²)/sqrt(1-v²/c²)      Einstein
tau = (t-uy/c²)/sqrt(1-u²/c²)      Androcles
tau = (t-wz/c²)/sqrt(1-w²/c²)      Androcles
xi  = (x-vt)/sqrt(1-v²/c²)         Einstein
eta = (y-ut)/sqrt(1-u²/c²)         Androcles
zeta= (z-wt)/sqrt(1-w²/c²)         Androcles

Right or wrong, dumbfuck?
If one is right they all are, if one is wrong they all are,
pathetic shithead.
For v = 0.866c, u = 0.866c, w = 0.866c the resultant velocity is
sqrt( 3/4 + 3/4 +3/4) = 1.5c
Right or wrong, shitforbrains?

Einstein said
eta = y,
zeta = z
because he did not know how to move sideways or up,
anencephalous cretin.

[quote]
we establish by definition that the "time" required by a crab to travel
from A to B equals the "time" it requires to travel from B to A.
[end quote]
Ref: http://www.fourmilab.ch/etexts/einstein/specrel/www/

Einstein can prove nothing can go faster than a crab.

Oops!... Did I say 'a crab'? Sorry...'light'.

"In agreement with experience we further assume the quantity
2AB/(t'A-tA) = c,
to be a universal constant--the velocity of light in empty space." --  
Einstein.

In agreement with experience and without any assumption,
BA = -AB,
2AB = AC,

[AB +BA]/(t'A-tA) = 0
Hence c = 0 in Einstein's math.

Observation:
http://www.britastro.org/vss/gifc/00918-ck.gif
Explanation:
http://www.ebicom.net/~rsf1/sekerin.htm (fig 3)

(Or stars explode twice in three months, which is stupid).

In agreement with experience and without any assumption,
you remain an  arrogant, illiterate, innumerate, illogical,
incompetent c.nt without a scrap of logic in you, you whining little toad.
You don't have an inkling about mathematics or physics
and live in the vain hope some moron will think you are clever,
Mr SmartArse who pretends he understands physics and
doesn't have a clue how to synchronize his watch to Cassini
time.
Modern physics:
http://www.androcles01.pwp.blueyonder.co.uk/Synchronize/Synchronize.htm

f.ck off, useless tord!

tau = (t-vx/c²)/sqrt(1-v²/c²)
tau = (t-uy/c²)/sqrt(1-u²/c²)
tau = (t-wz/c²)/sqrt(1-w²/c²)
xi  = (x-vt)/sqrt(1-v²/c²)
eta = (y-ut)/sqrt(1-u²/c²)
zeta= (z-wt)/sqrt(1-w²/c²)
If one is right they all are, if one is wrong they all are.
Carry three watches or do not move sideways or ride an elevator.

Personally I prefer three witches:
Double double, toil and trouble,
Fire burn and Einstein bubble.  --- Pop!
Hexenmeister.

>>and the PoR.
>
> Another falsehood.

A shithead like you wouldn't know what the PoR is.

>>   "But the ray moves relatively to the initial point of k,
>>when measured in the stationary system, with the velocity c-v..." --
>>Einstein.
>>Androcles.
JanPB - 25 Feb 2006 23:17 GMT
> >>>> This is misleading. You have a false principle - of constancy of the
> >>>> speed of light -
[quoted text clipped - 15 lines]
> tau = (t-uy/c²)/sqrt(1-u²/c²)      Androcles
> tau = (t-wz/c²)/sqrt(1-w²/c²)      Androcles

Wrong.

> xi  = (x-vt)/sqrt(1-v²/c²)         Einstein
> eta = (y-ut)/sqrt(1-u²/c²)         Androcles
> zeta= (z-wt)/sqrt(1-w²/c²)         Androcles
>
> Right or wrong, dumbfuck?

Wrong.

> If one is right they all are, if one is wrong they all are,

You keep repeating this mantra - it won't make it true. Try 2+2=5 for a
change.

--
Jan Bielawski
Hexenmeister - 26 Feb 2006 05:30 GMT
Hexenmeister wrote:
> > In article <hoYLf.68956$YJ4.9470@fe2.news.blueyonder.co.uk>,
> >   "Hexenmeister" <vanquish@broom.Mickey> wrote:
[quoted text clipped - 20 lines]
> tau = (t-uy/c²)/sqrt(1-u²/c²)      Androcles
> tau = (t-wz/c²)/sqrt(1-w²/c²)      Androcles

Wrong.

> xi  = (x-vt)/sqrt(1-v²/c²)         Einstein
> eta = (y-ut)/sqrt(1-u²/c²)         Androcles
> zeta= (z-wt)/sqrt(1-w²/c²)         Androcles
>
> Right or wrong, dumbfuck?

Wrong.
Ok, so Einstein was wrong. <shrug>

> If one is right they all are, if one is wrong they all are,

You keep repeating this mantra - it won't make it true. Try 2+2=5 for a
change.

You arseholes have been repeating the twin paradox mantra
for years and that won't make it go away either.
At least my mantra is comparitively new.  Try 2-3 = 4 for a change.
Androcles.
JanPB - 26 Feb 2006 06:39 GMT
> Hexenmeister wrote:
> > > In article <hoYLf.68956$YJ4.9470@fe2.news.blueyonder.co.uk>,
[quoted text clipped - 32 lines]
> > Wrong.
> Ok, so Einstein was wrong. <shrug>

Not Einstein - you. Einstein never said that:
xi  = (x-vt)/sqrt(1-v²/c²)
eta = (y-ut)/sqrt(1-u²/c²)
zeta= (z-wt)/sqrt(1-w²/c²)

This set of three equations is your fabrication.

> > > If one is right they all are, if one is wrong they all are,
>
[quoted text clipped - 3 lines]
> You arseholes have been repeating the twin paradox mantra
> for years and that won't make it go away either.

It's not true that "if one is right they all are, if one is wrong they
all are". This statement is nonsense.

--
Jan Bielawski
Hexenmeister - 26 Feb 2006 13:31 GMT
Hexenmeister wrote:
> > > In article <hoYLf.68956$YJ4.9470@fe2.news.blueyonder.co.uk>,
> > >>
[quoted text clipped - 22 lines]
>
> Wrong.

Prove it.

> > > xi  = (x-vt)/sqrt(1-v²/c²)         Einstein
> > > eta = (y-ut)/sqrt(1-u²/c²)         Androcles
[quoted text clipped - 4 lines]
> > Wrong.
> Ok, so Einstein was wrong. <shrug>

Not Einstein - you. Einstein never said that:
xi  = (x-vt)/sqrt(1-v²/c²)
eta = (y-ut)/sqrt(1-u²/c²)
zeta= (z-wt)/sqrt(1-w²/c²)

Bilewacky:
This set of three equations is your fabrication.
Androcles:
No no.
 xi  = (x-vt)/sqrt(1-v²/c²)
is definitely Einstein's fabrication. I read him say it myself.
I said if one is wrong they all are.

Einstein said
"An analogous consideration--applied to the axes of Y and Z--it being borne
in mind that light is always propagated with the velocity sqrt(c² - v²)
gives us @tau/@y = 0, @tau/@z = 0. "

tau = (t-vx/c²)/sqrt(1-v²/c²)  is Einstein's fabrication.

Majority verdict, the Y and Z axes win by 2: 1

> > > If one is right they all are, if one is wrong they all are,
>
[quoted text clipped - 3 lines]
> You arseholes have been repeating the twin paradox mantra
> for years and that won't make it go away either.

It's not true that "if one is right they all are, if one is wrong they
all are". This statement is nonsense.

Its not true that tau = (t-vx/c²)/sqrt(1-v²/c²). This statement is nonsense
and so are you.
Androcles.
Lloyd Parker - 27 Feb 2006 08:32 GMT
>>>>> This is misleading. You have a false principle - of constancy of the
>>>>> speed of light -
[quoted text clipped - 6 lines]
>
>Don't be silly.

Get an education.

>High school algebra:
>
[quoted text clipped - 9 lines]
>
>Right or wrong, dumbfuck?

What of the above is empircal data?

>If one is right they all are, if one is wrong they all are,
>pathetic shithead.
>For v = 0.866c, u = 0.866c, w = 0.866c the resultant velocity is
>sqrt( 3/4 + 3/4 +3/4) = 1.5c
>Right or wrong, shitforbrains?

Slept through science class?

>Einstein said
>eta = y,
[quoted text clipped - 68 lines]
>>>Einstein.
>>>Androcles.

So when are you publishing all this?  Can your Nobel be far behind?

ROTFL
Hexenmeister - 27 Feb 2006 18:21 GMT
>>>>>> This is misleading. You have a false principle - of constancy of the
>>>>>> speed of light -
[quoted text clipped - 8 lines]
>
> Get an education.
I already have one, thanks.

>>High school algebra:
>>
[quoted text clipped - 11 lines]
>
> What of the above is empircal data?

The same empirical data Einstein wrote in "On the Electrodynamics
of Moving Bodies", shithead.  Of course you would not have read that
since you don't have an education, and even if you did you'd not be able
to understand it.

>>If one is right they all are, if one is wrong they all are,
>>pathetic shithead.
[quoted text clipped - 3 lines]
>
> Slept through science class?

Do you have any mathematics to discuss, arsehole?
If not f.ck off, there's a good c.nt.

>>Einstein said
>>eta = y,
[quoted text clipped - 72 lines]
>
> ROTFL
It's on my web page, not that an uneducated moron like you be able to
understand it since you don't know how to move sideways or up.
ROFLMAO!
 http://www.androcles01.pwp.blueyonder.co.uk/
Androcles.
Lloyd Parker - 27 Feb 2006 13:26 GMT
>>>>>>> This is misleading. You have a false principle - of constancy of the
>>>>>>> speed of light -
[quoted text clipped - 123 lines]
>  http://www.androcles01.pwp.blueyonder.co.uk/
>Androcles.

I understand Einstein.  And you're no Einstein.
Hexenmeister - 27 Feb 2006 20:23 GMT
>>>>>>>> This is misleading. You have a false principle - of constancy of
>>>>>>>> the
[quoted text clipped - 127 lines]
>>
> I understand Einstein.  And you're no Einstein.

No you don't, and I wouldn't want to be.
Now f.ck off, there's a good c.nt.
Androcles.
Dirk Van de moortel - 25 Feb 2006 13:10 GMT
> >> This is misleading. You have a false principle - of constancy of the
> >> speed of light -
[quoted text clipped - 5 lines]
> when measured in the stationary system, with the velocity c-v..." --
> Einstein.

As measured in K, relatively to the origin of K: c
As measured in k, relatively to the origin of k: c
As measured in K, relatively to the origin of k: c-v
As measured in k, relatively to the origin of K: c+v

Which part do you pretend not to understand?

Dirk Vdm
The Ghost In The Machine - 25 Feb 2006 17:00 GMT
In sci.physics.relativity, Dirk Van de moortel
<dirkvandemoortel@ThankS-NO-SperM.hotmail.com>
wrote
on Sat, 25 Feb 2006 13:10:37 GMT
<hHYLf.278854$an.7985181@phobos.telenet-ops.be>:

>> >> This is misleading. You have a false principle - of constancy of the
>> >> speed of light -
[quoted text clipped - 14 lines]
>
> Dirk Vdm

That is not empirical data; that is part of Einstein's theory
attempting to explain, among other things, the MMX failure to
detect absolute aether motion.

Not that it matters; Androcles is on record as stating that SR
predicts c = 0... :-)

Signature

#191, ewill3@earthlink.net
It's still legal to go .sigless.

Dirk Van de moortel - 25 Feb 2006 17:17 GMT
> In sci.physics.relativity, Dirk Van de moortel
> <dirkvandemoortel@ThankS-NO-SperM.hotmail.com>
[quoted text clipped - 24 lines]
> attempting to explain, among other things, the MMX failure to
> detect absolute aether motion.

Yes, and I wonder how he explains what he allegedly
fails to understand about which part of it.

Dirk Vdm

> Not that it matters; Androcles is on record as stating that SR
> predicts c = 0... :-)
JanPB - 25 Feb 2006 23:10 GMT
> >> This is misleading. You have a false principle - of constancy of the
> >> speed of light -
[quoted text clipped - 5 lines]
> when measured in the stationary system, with the velocity c-v..." --
> Einstein.

That's the difference between velocity coordinates of *two* objects
seen in a *single* frame of reference. Velocity is a vector, you know.
Vectors in general can be added and subtracted, you see.

What confuses you is the relationship between velocity coordinates of a
*single object* seen from *two different* frames of reference (the
"Einstein velocity addition" thing).

Two object, one frame.
One object, two frames.
Different things.

--
Jan Bielawski
Hexenmeister - 26 Feb 2006 05:30 GMT
>> >> This is misleading. You have a false principle - of constancy of the
>> >> speed of light -
[quoted text clipped - 9 lines]
> seen in a *single* frame of reference. Velocity is a vector, you know.
> Vectors in general can be added and subtracted, you see.
I do see.
"In agreement with experience we further assume the quantity
2AB/(t'A-tA) = c,
to be a universal constant--the velocity of light in empty space." --  
Einstein.

In agreement with experience and without any assumption,
BA = -AB,
2AB = AC,

[AB +BA]/(t'A-tA) = 0
Hence c = 0 in Einstein's math.
Vectors like -c and +c can be added and the sum is zero, you see.
Glad we agree at last.

> What confuses you

I'm not confused, I can see right through Einstein's crap.
I agree with you, vectors in general can be added and subtracted, you see.

is the relationship between velocity coordinates of a
> *single object* seen from *two different* frames of reference (the
> "Einstein velocity addition" thing).
>
> Two object, one frame.

What two object are you babbling about?
Androcles.

> One object, two frames.

> Different things.

> --
> Jan Bielawski
JanPB - 26 Feb 2006 06:48 GMT
> > What confuses you
>
> I'm not confused, I can see right through Einstein's crap.

Nonsense. You cannot do simplest physics problems. How you can even
THINK seriously (and post!!) about criticising Einstein is a mystery
I'll leave psychiatrists on this NG to resolve.

--
Jan Bielawski
Hexenmeister - 26 Feb 2006 13:32 GMT
>> > What confuses you
>>
>> I'm not confused, I can see right through Einstein's crap.
>
> Nonsense.

I know you are.

You are still an arrogant, illiterate, innumerate, illogical,
c.nt without a scrap of logic in you, you whining little toad.
You don't have an inkling about mathematics or physics
and live in the vain hope some moron will think you are clever,
Mr SmartArse who pretends he understands relativity and
doesn't have a clue how to synchronize his watch to Cassini
time.
Modern physics:
http://www.androcles01.pwp.blueyonder.co.uk/Synchronize/Synchronize.htm

Hey dumbfuck! Do you know how to move sideways or up?
http://www.androcles01.pwp.blueyonder.co.uk/how_to3.jpg

High school algebra:

x² + y² + z² =  c²t²               Einstein
xi² + eta² + zeta² = c²tau²        Einstein

tau = (t-vx/c²)/sqrt(1-v²/c²)      Einstein
tau = (t-uy/c²)/sqrt(1-u²/c²)      Androcles
tau = (t-wz/c²)/sqrt(1-w²/c²)      Androcles
xi  = (x-vt)/sqrt(1-v²/c²)         Einstein
eta = (y-ut)/sqrt(1-u²/c²)         Androcles
zeta= (z-wt)/sqrt(1-w²/c²)         Androcles

Right or wrong, dumbfuck?
If one is right they all are, if one is wrong they all are,
pathetic shithead.
For v = 0.866c, u = 0.866c, w = 0.866c the resultant velocity is
sqrt( 3/4 + 3/4 +3/4) = 1.5c
Right or wrong, shitforbrains?

Einstein said
eta = y,
zeta = z
because he did not know how to move sideways or up,
anencephalous cretin.

[quote]
we establish by definition that the "time" required by a crab to travel
from A to B equals the "time" it requires to travel from B to A.
[end quote]
Ref: http://www.fourmilab.ch/etexts/einstein/specrel/www/

Einstein can prove nothing can go faster than a crab.

Oops!... Did I say 'a crab'? Sorry...'light'.

"In agreement with experience we further assume the quantity
2AB/(t'A-tA) = c,
to be a universal constant--the velocity of light in empty space." --  
Einstein.

In agreement with experience and without any assumption,
BA = -AB,
2AB = AC,

[AB +BA]/(t'A-tA) = 0
Hence c = 0 in Einstein's math.

Observation:
http://www.britastro.org/vss/gifc/00918-ck.gif
Explanation:
http://www.ebicom.net/~rsf1/sekerin.htm (fig 3)

(Or stars explode twice in three months, which is stupid).

In agreement with experience and without any assumption,
you remain an arrogant, illiterate, innumerate, illogical,
incompetent c.nt without a scrap of logic in you,
you whining little toad.
You don't have an inkling about mathematics or physics
and live in the vain hope some moron will think you are clever,
Mr SmartArse who pretends he understands physics and
doesn't have a clue how to synchronize his watch to Cassini
time.
Modern physics:
http://www.androcles01.pwp.blueyonder.co.uk/Synchronize/Synchronize.htm

f.ck off, useless tord!

tau = (t-vx/c²)/sqrt(1-v²/c²)
tau = (t-uy/c²)/sqrt(1-u²/c²)
tau = (t-wz/c²)/sqrt(1-w²/c²)
xi  = (x-vt)/sqrt(1-v²/c²)
eta = (y-ut)/sqrt(1-u²/c²)
zeta= (z-wt)/sqrt(1-w²/c²)
If one is right they all are, if one is wrong they all are.
Carry three watches or do not move sideways or ride an elevator.

Personally I prefer three witches:
Double double, toil and trouble,
Fire burn and Einstein bubble.  --- Pop!
Hexenmeister.
Spaceman - 25 Feb 2006 15:19 GMT
>> This is misleading. You have a false principle - of constancy of the
>> speed of light -
>
> Why is it false?

Because, If you have to use self limiting math (transforms)
to prove such, you are in fact proving it was not actually constant.
You had to use the self limiting math itself to make it "supposedly"
constant.

Place any speed in place of the c in a tranform and the new
supposed constant speed will be that speed now.
Try it, use a speed of 100,000 meters per second as c
and just so you don't use speed of light by accident
replace c with k everyhwere is shows up and make
k = 100,000 meters per second.
If you do such. The new constant is the speed of k
and that will now be 100,000 meters per second
and all observers will measure k as the new constant
speed.
Self limiting math is more of a mathematical trick then
a proof that something is constant to all observers.
:)

--
James M Driscoll Jr
Spaceman
Lloyd Parker - 25 Feb 2006 13:01 GMT
>>> This is misleading. You have a false principle - of constancy of the
>>> speed of light -
[quoted text clipped - 5 lines]
>You had to use the self limiting math itself to make it "supposedly"
>constant.

Again, you throw out gibberish as supposed proof.

>Place any speed in place of the c in a tranform and the new
>supposed constant speed will be that speed now.

So?  Replace the charge on an electron with a different value and the
equations for that work out differently too.

>Try it, use a speed of 100,000 meters per second as c
>and just so you don't use speed of light by accident
[quoted text clipped - 7 lines]
>a proof that something is constant to all observers.
>:)
Spaceman - 25 Feb 2006 19:14 GMT
>>>> This is misleading. You have a false principle - of constancy of the
>>>> speed of light -
[quoted text clipped - 7 lines]
>
> Again, you throw out gibberish as supposed proof.

The "gibberish" I just threw out is only "gibberish"
to the brainwashed.
It is a simple fact to a brain that can actually think

>>Place any speed in place of the c in a tranform and the new
>>supposed constant speed will be that speed now.
>
> So?  Replace the charge on an electron with a different value and the
> equations for that work out differently too.

You truly do not grasp what I said at all huh?
The transform is helping in creating a constant that is not actually
a constant.

>>Try it, use a speed of 100,000 meters per second as c
>>and just so you don't use speed of light by accident
[quoted text clipped - 7 lines]
>>a proof that something is constant to all observers.
>>:)
JanPB - 26 Feb 2006 07:09 GMT
> >> This is misleading. You have a false principle - of constancy of the
> >> speed of light -
[quoted text clipped - 18 lines]
> Self limiting math is more of a mathematical trick then
> a proof that something is constant to all observers.

You've fallen into the standard trap: the illusion that the constancy
of the speed of light in SR is just the result of clock setting. You
are not the first one.

--
Jan Bielawski
The Ghost In The Machine - 25 Feb 2006 17:00 GMT
In sci.physics.relativity, Pentcho Valev
<pvalev@yahoo.com>
wrote
on 24 Feb 2006 23:24:07 -0800
<1140852247.612067.171970@i40g2000cwc.googlegroups.com>:

>> In sci.physics.relativity, tdp1001@gmail.com
>> <tdp1001@gmail.com>
[quoted text clipped - 52 lines]
> speed of light - the speed of light does not depend on the speed of
> source or observer.

I *did* say you had to replace it.  This is one of the principles
of SR; it may need to be replaced as well.

> Since it is false, it should be replaced with the
> true principle of variability of speed of light - the speed of light
> does depend on the speed of source or observer. Then, of course, the
> corollaries of the false principle will have to be replaced with the
> corollaries of the true principle. And that is all you should do.

This is fine.  Did you want c'=c+v or did you want some other formula?

I should point out that an attempted measurement of k in
the formula c'=c+kv suggests that k < 10^-9 or thereabouts;
unfortunately, I'm not at all sure how to find this
particular experiment in the literature.

But never mind that; mathematically express the "true principle" as
you call it and we'll see what we can do.

> Pentcho Valev

Signature

#191, ewill3@earthlink.net
It's still legal to go .sigless.

sal - 28 Feb 2006 16:13 GMT
> In sci.physics.relativity, tdp1001@gmail.com <tdp1001@gmail.com>
>  wrote
[quoted text clipped - 17 lines]
>
> The logic is suspect.

(I'm about to plonk all threads started by Valev for good (adding a rule
to do it automatically) and thought I'd take a quick peek first to see if
there's anything worth replying to here, and I saw this.)

The logic is fine.  It's "Bell's Paradox", IIRC, and it can be viewed
several ways.  To start with, as the ships speed up, the system of two
ships and a string must _contract_ as viewed by a "stationary" observer.
By the assumptions in the statement of the problem, the two ships are held
a _fixed_ _distance_ apart in the "stationary" frame; something has to
give, and the string breaks.

Alternatively, translate into a Lorentz frame which is momentarily
co-moving with the first spaceship.  Initially this frame looks just like
the "stationary" frame.  Later, you find that in the local Lorentz frame
of the leading ship, the trailing ship is _farther_ _away_.  So, in the
frame of either ship (or the string, for that matter) the string must be
stretching.  Eventually it breaks.

Another way to view it is to look at it from the POV of someone riding in
the first ship.  There's a uniform space-filling g-field (sort of) and the
second ship is sunk deeper in the universal gravity well.  Therefore the
clock on the trailing ship is seen to be going slower than the clock on
the leading ship.  (If you view it from the trailing ship you get the same
result -- time's going faster for the leading ship.)  But the trailing
vessel measures the _same_ _acceleration_ as the leading ship.  How can
that be?  It turns out that, as viewed by riders on the leading ship
(using telescopes, or whatever) the _trailing_ vessel is measured to be
accelerating less rapidly than the leading vessel.  Conversely, riders on
the trailing vessel see the leading vessel accelerating _more_ rapidly.
Again, the difference in clock rates forces this conclusion, and the
conclusion leads inevitably to the same result, which is that the string
must eventually break.

Finally, any observer in uniform acceleration must find there is a
"Rindler horizon" someplace "behind" him/her.  Time for objects "behind"
the accelerating observer seems to go slower, and the farther back another
observer is, the slower time seems to go for them.   At some distance,
time stops entirely; beyond that point time seems to go backwards.  You
can't ever see time going backwards, though, and in fact the "Rindler
horizon" is at the point where time seems to stop.  If the acceleration
goes on long enough and the string stretches far enough, the Rindler
horizon will eventually be close enough to the first ship that it will cut
the string.  And then the string _must_ break, no matter what it's made of.

(And now, as soon as this shows up I'll be plonking this thread and all
others started by Valev.  So on the off chance that you want me to see a
response to this you should email me or start a new (non-Valev) thread on
it ... or depend on the fact that I sometimes use Google and might see it
there.)

>  First, "simultaneity" cannot be proven; it depends
> on the observer.  Second, the tension in the string is a factor in their
> acceleration; if one replaces the string with a *spring* one will see that
> the spacecraft will accelerate towards each other, absent expenditure of
> fuel.

Signature

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I can be also contacted through http://www.physicsinsights.org

sal - 28 Feb 2006 16:19 GMT
[Still having posting trouble, so reposting via Google...]

> In sci.physics.relativity, tdp1001@gmail.com <tdp1001@gmail.com>
>  wrote
[quoted text clipped - 17 lines]
>
> The logic is suspect.

(I'm about to plonk all threads started by Valev for good (adding a
rule
to do it automatically) and thought I'd take a quick peek first to see
if
there's anything worth replying to here, and I saw this.)

The logic is fine.  It's "Bell's Paradox", IIRC, and it can be viewed
several ways.  To start with, as the ships speed up, the system of two
ships and a string must _contract_ as viewed by a "stationary"
observer.
By the assumptions in the statement of the problem, the two ships are
held
a _fixed_ _distance_ apart in the "stationary" frame; something has to
give, and the string breaks.

Alternatively, translate into a Lorentz frame which is momentarily
co-moving with the first spaceship.  Initially this frame looks just
like
the "stationary" frame.  Later, you find that in the local Lorentz
frame
of the leading ship, the trailing ship is _farther_ _away_.  So, in the
frame of either ship (or the string, for that matter) the string must
be
stretching.  Eventually it breaks.

Another way to view it is to look at it from the POV of someone riding
in
the first ship.  There's a uniform space-filling g-field (sort of) and
the
second ship is sunk deeper in the universal gravity well.  Therefore
the
clock on the trailing ship is seen to be going slower than the clock on
the leading ship.  (If you view it from the trailing ship you get the
same
result -- time's going faster for the leading ship.)  But the trailing
vessel measures the _same_ _acceleration_ as the leading ship.  How can
that be?  It turns out that, as viewed by riders on the leading ship
(using telescopes, or whatever) the _trailing_ vessel is measured to be
accelerating less rapidly than the leading vessel.  Conversely, riders
on
the trailing vessel see the leading vessel accelerating _more_ rapidly.
Again, the difference in clock rates forces this conclusion, and the
conclusion leads inevitably to the same result, which is that the
string
must eventually break.

Finally, any observer in uniform acceleration must find there is a
"Rindler horizon" someplace "behind" him/her.  Time for objects
"behind"
the accelerating observer seems to go slower, and the farther back
another
observer is, the slower time seems to go for them.   At some distance,
time stops entirely; beyond that point time seems to go backwards.  You
can't ever see time going backwards, though, and in fact the "Rindler
horizon" is at the point where time seems to stop.  If the acceleration
goes on long enough and the string stretches far enough, the Rindler
horizon will eventually be close enough to the first ship that it will
cut
the string.  And then the string _must_ break, no matter what it's made
of.

(And now, as soon as this shows up I'll be plonking this thread and all
others started by Valev.  So on the off chance that you want me to see
a
response to this you should email me or start a new (non-Valev) thread
on
it ... or depend on the fact that I sometimes use Google and might see
it
there.)

>  First, "simultaneity" cannot be proven; it depends
> on the observer.  Second, the tension in the string is a factor in their
> acceleration; if one replaces the string with a *spring* one will see
> that the spacecraft will accelerate towards each other, absent
> expenditure of fuel.

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