> > In James Hartle's book Gravity (An introduction...) he runs through the
> > maths of deriving time dilation from a pair of mirrors aligned parallel
[quoted text clipped - 17 lines]
> 2gL/c (i.e. a factor of g longer than the time taken in the reference
> frame of the mirrors).
xxein: I am just skipping through this but what about the parallel
perpendicular mirrors? It seems that you gave a good description for
the mirrors aligned along the axis of motion, but not to parallel
mirrors aligned perpendicular to the line of motion.
What is the primary cause of a physical (not just mathematical) length
contraction?
Same for time. What is time?
I am not being confrontational here. I think that you think along the
same lines that I do. But we have to have a solid physical reason for
these thoughts. (And then it's still called a theory that is false
because Einstein had to be completely right?)
> > In James Hartle's book Gravity (An introduction...) he runs through the
> > maths of deriving time dilation from a pair of mirrors aligned parallel
[quoted text clipped - 10 lines]
> Suppose the distance between the mirrors (in the reference frame of the
> mirrors) is L, the speed of the mirrors is v, and g = 1/sqrt(1-v^2/c^2).
This much I can understand.
> Then, due to length contraction, the distance between the moving
> mirrors is L/g
What is the frame of reference here? Are we assuming that the mirrors
are on a moving platform and it is moving wrt the surface of the Earth?
If so, then is the statement above essentially saying, "In the
reference frame of the surface of the Earth, the distance between the
moving mirrors is L/g?" If so, why is length contraction applied in
the frame of the surface of the Earth and not in the frame of the
mirrors?
>, and the speed of a horizontal light pulse relative to
> the mirrors is c-v in the direction the mirrors are moving, and c+v in
> the opposite direction.
How many frames are you using here? When you say the speed of a
horizontal light pulse, do you mean the same light pulse that is
travelling back and forth between the mirrors in the frame of the
mirrors? Are you saying that the speed of the light pulse in the frame
of the surface of the Earth is anything other than c? SR's second
postulate states the speed of light is always c in any reference frame.
What gives?
> Therefore the time for a light pulse to
> complete a round trip between the mirrors is L/(g(c-v)) + L/(g(c+v)) =
> 2gL/c (i.e. a factor of g longer than the time taken in the reference
> frame of the mirrors).
Can you just state what you're trying to show with the math? Are you
maybe saying that in the reference frame of the surface of the Earth,
the light pulse is travelling at an angle between the mirrors since the
mirrors are moving and because the speed of light is always c and the
distance the light pulse travels appears to be longer in the frame of
the surface of the Earth as it's travelling down the hypotenuse of a
right triangle, then the distance between the mirrors must be less in
that frame, otherwise the light pulse wouldn't hit the mirror in the
same place?
Vern
Jem - 24 Jun 2006 14:27 GMT
>>>In James Hartle's book Gravity (An introduction...) he runs through the
>>>maths of deriving time dilation from a pair of mirrors aligned parallel
[quoted text clipped - 17 lines]
>
> What is the frame of reference here?
One in which the speed of the mirrors is v.
Are we assuming that the mirrors
> are on a moving platform and it is moving wrt the surface of the Earth?
> If so, then is the statement above essentially saying, "In the
> reference frame of the surface of the Earth, the distance between the
> moving mirrors is L/g?" If so, why is length contraction applied in
> the frame of the surface of the Earth and not in the frame of the
> mirrors?
As measured in the reference frame of the mirrors, the distance between
the mirrors is L, and as measured in a reference frame in which the
mirrors are moving at speed v, the distance between the mirrors is L/g.
>>, and the speed of a horizontal light pulse relative to
>>the mirrors is c-v in the direction the mirrors are moving, and c+v in
[quoted text clipped - 4 lines]
> travelling back and forth between the mirrors in the frame of the
> mirrors?
The light pulse which travels between the mirrors - in every frame of
reference.
Are you saying that the speed of the light pulse in the frame
> of the surface of the Earth is anything other than c? SR's second
> postulate states the speed of light is always c in any reference frame.
> What gives?
The speed of light (locally, in vacuum) will be measured as c, and so
(in 1-D) if the speed of some other object is measured as v, the speed
of the light with respect to that object will be measured as either c-v
or c+v.
>> Therefore the time for a light pulse to
>>complete a round trip between the mirrors is L/(g(c-v)) + L/(g(c+v)) =
[quoted text clipped - 10 lines]
> that frame, otherwise the light pulse wouldn't hit the mirror in the
> same place?
Apparently you didn't understand the question that was asked. In order
to graphically demonstrate the time dilation effect, most introductory
textbooks on Relativity use a light clock which is moving
perpendicularly to the path of the light pulse which bounces back and
forth between the clock's two mirrors. The question that was asked and
answered concerns how to demonstrate the time dilation effect when the
clock is rotated 90 degrees so that both the light pulse and the mirrors
travel along the same line.
> Vern
vern@bealenet.com - 25 Jun 2006 12:49 GMT
> Apparently you didn't understand the question that was asked. In order
> to graphically demonstrate the time dilation effect, most introductory
[quoted text clipped - 4 lines]
> clock is rotated 90 degrees so that both the light pulse and the mirrors
> travel along the same line.
Sorry, but you are incorrect. The original poster stated that the
textbook he was using gave the example of the mirrors moving parallel
to the path of the light first and he understood that example. He was
asking for help with the second example in which the mirrors were
moving perpendicular to the path of the light. See posts #1 and #13.
Vern
Dirk Van de moortel - 25 Jun 2006 13:12 GMT
>> Apparently you didn't understand the question that was asked. In order
>> to graphically demonstrate the time dilation effect, most introductory
[quoted text clipped - 10 lines]
> asking for help with the second example in which the mirrors were
> moving perpendicular to the path of the light. See posts #1 and #13.
See Jem's answer.
Dirk Vdm
Sue... - 25 Jun 2006 13:53 GMT
> > Apparently you didn't understand the question that was asked. In order
> > to graphically demonstrate the time dilation effect, most introductory
[quoted text clipped - 12 lines]
>
> Vern
If an example uses a train to explain how a boat floats or
it uses a frog to explain how a bird flys...
... you find a better example.
Sue...
Jem - 25 Jun 2006 14:06 GMT
>>Apparently you didn't understand the question that was asked. In order
>>to graphically demonstrate the time dilation effect, most introductory
[quoted text clipped - 10 lines]
> asking for help with the second example in which the mirrors were
> moving perpendicular to the path of the light. See posts #1 and #13.
The original question was somewhat ambiguous, but if it had been about
motion perpendicular to the light path, there certainly wouldn't have
been any problem finding the answer on the "net". See post #1.
vern@bealenet.com - 26 Jun 2006 00:33 GMT
> >>Apparently you didn't understand the question that was asked. In order
> >>to graphically demonstrate the time dilation effect, most introductory
[quoted text clipped - 14 lines]
> motion perpendicular to the light path, there certainly wouldn't have
> been any problem finding the answer on the "net". See post #1.
After reading the original poster's two posts again, I think he said
parallel in the first post when he meant perpendicular, so I think you
were right that he was having trouble with the example where the
mirrors are positioned so that the light is being reflected parallel to
the motion (at the front and back of the rocket, as he says in his
second post). I found the following website which addresses both, so
maybe the original poster will read this message.
http://www.sparknotes.com/physics/specialrelativity/kinematics/section2.rhtml
Vern
> > In James Hartle's book Gravity (An introduction...) he runs through the
> > maths of deriving time dilation from a pair of mirrors aligned parallel
[quoted text clipped - 17 lines]
> 2gL/c (i.e. a factor of g longer than the time taken in the reference
> frame of the mirrors).
The nice thing about this... you are using something that is
physically ambiguous to illustrate somthing with only a
mathematical interpretation. This is much better because
the reader can't conclude with the notion that raindrops
should take longer to reach the ground when their diagonal
path is viewed from a moving car. Absurd of course. ;-)
The changing distance between the mirrors then maps directly
to the distance which accounts for the retarded time in Maxwell's
time dependent equations.
Sue...
Sue...