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Natural Science Forum / Physics / Relativity / June 2006



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Time dilation mirrors perpendicular to motion

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Zinc Potterman - 21 Jun 2006 11:43 GMT
In James Hartle's book Gravity (An introduction...) he runs through the
maths of deriving time dilation from a pair of mirrors aligned parallel
with their motion.
He then sets the same problem for a pair of mirrors aligned perpendicular to
their motion
i.e at the front and back of a rocket e.g
I have struggled with this for many hours and can't progress.  Also searched
the net.
Does anyone know of a clear exlanation/derivation of time dilation for this
configuration please.
Zinc

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Sue... - 21 Jun 2006 11:56 GMT
> In James Hartle's book Gravity (An introduction...) he runs through the
> maths of deriving time dilation from a pair of mirrors aligned parallel
[quoted text clipped - 6 lines]
> Does anyone know of a clear exlanation/derivation of time dilation for this
> configuration please.

It is impossible to observe light propagating parallel to your line of
sight.
Have you ever seen any moon light bound for Jupiter?

There is no logical explanation of a physical absurditiy.
If you want to derive a Lorentz correction use something
that can acutally be observed and confirmed by experiment.

<<... we shall see later that the full time-dependent Maxwell's
equations only allow information to propagate at the speed of
light (i.e., they do not violate relativity). How can these two
statements be reconciled? The crucial point is that the scalar
potential cannot be measured directly, it can only be inferred
from the electric field. In the time-dependent case, there are
two parts to the electric field: that part which comes from the
scalar potential, and that part which comes from the vector
potential [see Eq. (393)]. So, if the scalar potential responds
immediately to some distance rearrangement of charge density
it does not necessarily follow that the electric field also has an i
mmediate response. What actually happens is that the change
in the part of the electric field which comes from the scalar
potential is balanced by an equal and opposite change in the
part which comes from the vector potential, so that the overall
electric field remains unchanged. This state of affairs persists
at least until sufficient time has elapsed for a light signal to
travel from the distant charges to the region in question.
Thus, relativity is not violated, since it is the electric field,
and not the scalar potential, which carries physically
accessible information. >>
http://farside.ph.utexas.edu/teaching/em/lectures/node45.html

"Retarded potential"
http://farside.ph.utexas.edu/teaching/em/lectures/node50.html

Sue...

> Zinc
>
[quoted text clipped - 4 lines]
> then delete spaces.
> ------------------------------------
Sue... - 21 Jun 2006 12:09 GMT
<< It is impossible to observe light propagating
perpendicular [XparallelX}
to your line of sight. >>

I was just trying to use a word I knew how to spell. <:}

Sue...
Sue... - 21 Jun 2006 13:11 GMT
> In James Hartle's book Gravity (An introduction...) he runs through the
> maths of deriving time dilation from a pair of mirrors aligned parallel
[quoted text clipped - 6 lines]
> Does anyone know of a clear exlanation/derivation of time dilation for this
> configuration please.

Since your book is about gravity, you might choose avoid some of
the rigour of derivng a 4 space:
http://farside.ph.utexas.edu/teaching/em/lectures/node113.html
... and try jumping right into the deep water

<< Spacetime in general relativity
In general relativity, it is assumed that spacetime is curved
by the presence of matter (energy), this curvature being
represented by the Riemann tensor. In special relativity,
the Riemann tensor is identically zero, and so this concept
of "non-curvedness" is sometimes expressed by the statement
"Minkowski space is flat."

Many space-time continua have physical interpretations
which most physicists would consider bizarre or unsettling.
For example, a compact spacetime has closed, time-like
curves, which violate our usual ideas of causality (that is,
future events could affect past ones). For this reason,
mathematical physicists usually consider only restricted
subsets of all the possible spacetimes. One way to do this is
to study "realistic" solutions of the equations of general relativity.
Another way is to add some additional "physically reasonable"
but still fairly general geometric restrictions, and try to prove
interesting things about the resulting spacetimes. The latter
approach has led to some important results, most notably the
Penrose-Hawking singularity theorems.  >>
http://en.wikipedia.org/wiki/Spacetime

It is a long swim by either route and I caution that many are
dissappointed at end of journey to find they have more a
quantitative calculating formalism that is not very illustrative
of underlying mechanisms. The rubber sheet analogy is
really misleading but it is a long journey to get to the higher
level of abstraction where you can attach any real meaning
to 'curvature of space-time'.

Sue...

> Zinc
>
[quoted text clipped - 4 lines]
> then delete spaces.
> ------------------------------------
xxein@bellsouth.net - 22 Jun 2006 01:33 GMT
> > In James Hartle's book Gravity (An introduction...) he runs through the
> > maths of deriving time dilation from a pair of mirrors aligned parallel
[quoted text clipped - 53 lines]
> > then delete spaces.
> > ------------------------------------

xxein:  Good reply.  At least you resist the myth.

All I am saying is that you are able to think beyond the box --- not
that it is the correct thinking.  At least you are trying to
investigate from what you think is a viable perspective.

Iow, you seem to attach a physicallity to the issue instead of just a
subjectively measured math concept.  There is hope for you.

I wish I could say more, but I'll give you some time renegotiate your
thoughts into your final say.  We know that it won't be complete, but
it is impossible for us to be complete.  We just try harder instead of
being sheep.

Just be as honest as you can with what you can think.
Sue... - 22 Jun 2006 04:55 GMT
> > > In James Hartle's book Gravity (An introduction...) he runs through the
> > > maths of deriving time dilation from a pair of mirrors aligned parallel
[quoted text clipped - 67 lines]
> it is impossible for us to be complete.  We just try harder instead of
> being sheep.

X: Just be as honest as you can with what you can think.

Thanks, :-)  IOW
<< So I have just one wish for you--the
good luck to be somewhere where you are free to maintain
the kind of integrity I have described, and where you do not
feel forced by a need to maintain your position in the organization,
or financial support, or so on, to lose your integrity. May you
have that freedom.   -- Richard Feynman >>
http://www.physics.brocku.ca/etc/cargo_cult_science.html
http://www.quackwatch.org/01QuackeryRelatedTopics/pseudo.html

Sue...

http://www.physics.brocku.ca/etc/cargo_cult_science.html
xxein@bellsouth.net - 23 Jun 2006 23:35 GMT
> > > > In James Hartle's book Gravity (An introduction...) he runs through the
> > > > maths of deriving time dilation from a pair of mirrors aligned parallel
[quoted text clipped - 83 lines]
>
> http://www.physics.brocku.ca/etc/cargo_cult_science.html

xxein:  One striking difference.  If Feynman is a stepping stone to
truth, I have use that.  But I am now beyond that.  I hope that you see
beyond that also.
Jem - 21 Jun 2006 13:57 GMT
> In James Hartle's book Gravity (An introduction...) he runs through the
> maths of deriving time dilation from a pair of mirrors aligned parallel
[quoted text clipped - 7 lines]
> configuration please.
> Zinc

Suppose the distance between the mirrors (in the reference frame of the
mirrors) is L, the speed of the mirrors is v, and g = 1/sqrt(1-v^2/c^2).
 Then, due to length contraction, the distance between the moving
mirrors is L/g, and the speed of a horizontal light pulse relative to
the mirrors is c-v in the direction the mirrors are moving, and c+v in
the opposite direction.  Therefore the time for a light pulse to
complete a round trip between the mirrors is L/(g(c-v)) + L/(g(c+v)) =
2gL/c (i.e. a factor of g longer than the time taken in the reference
frame of the mirrors).
xxein@bellsouth.net - 24 Jun 2006 00:02 GMT
> > In James Hartle's book Gravity (An introduction...) he runs through the
> > maths of deriving time dilation from a pair of mirrors aligned parallel
[quoted text clipped - 17 lines]
> 2gL/c (i.e. a factor of g longer than the time taken in the reference
> frame of the mirrors).

xxein:  I am just skipping through this but what about the parallel
perpendicular mirrors?  It seems that you gave a good description for
the mirrors aligned along the axis of motion, but not to parallel
mirrors aligned perpendicular to the line of motion.

What is the primary cause of a physical (not just mathematical) length
contraction?

Same for time.  What is time?

I am not being confrontational here.  I think that you think along the
same lines that I do.  But we have to have a solid physical reason for
these thoughts.  (And then it's still called a theory that is false
because Einstein had to be completely right?)
vern@bealenet.com - 24 Jun 2006 01:13 GMT
> > In James Hartle's book Gravity (An introduction...) he runs through the
> > maths of deriving time dilation from a pair of mirrors aligned parallel
[quoted text clipped - 10 lines]
> Suppose the distance between the mirrors (in the reference frame of the
> mirrors) is L, the speed of the mirrors is v, and g = 1/sqrt(1-v^2/c^2).

This much I can understand.

>   Then, due to length contraction, the distance between the moving
> mirrors is L/g

What is the frame of reference here?  Are we assuming that the mirrors
are on a moving platform and it is moving wrt the surface of the Earth?
If so, then is the statement above essentially saying, "In the
reference frame of the surface of the Earth, the distance between the
moving mirrors is L/g?"  If so, why is length contraction applied in
the frame of the surface of the Earth and not in the frame of the
mirrors?

>, and the speed of a horizontal light pulse relative to
> the mirrors is c-v in the direction the mirrors are moving, and c+v in
> the opposite direction.

How many frames are you using here?  When you say the speed of a
horizontal light pulse, do you mean the same light pulse that is
travelling back and forth between the mirrors in the frame of the
mirrors?  Are you saying that the speed of the light pulse in the frame
of the surface of the Earth is anything other than c?  SR's second
postulate states the speed of light is always c in any reference frame.
What gives?

>  Therefore the time for a light pulse to
> complete a round trip between the mirrors is L/(g(c-v)) + L/(g(c+v)) =
> 2gL/c (i.e. a factor of g longer than the time taken in the reference
> frame of the mirrors).

Can you just state what you're trying to show with the math?  Are you
maybe saying that in the reference frame of the surface of the Earth,
the light pulse is travelling at an angle between the mirrors since the
mirrors are moving and because the speed of light is always c and the
distance the light pulse travels appears to be longer in the frame of
the surface of the Earth as it's travelling down the hypotenuse of a
right triangle, then the distance between the mirrors must be less in
that frame, otherwise the light pulse wouldn't hit the mirror in the
same place?

Vern
Jem - 24 Jun 2006 14:27 GMT
>>>In James Hartle's book Gravity (An introduction...) he runs through the
>>>maths of deriving time dilation from a pair of mirrors aligned parallel
[quoted text clipped - 17 lines]
>
> What is the frame of reference here?

One in which the speed of the mirrors is v.

 Are we assuming that the mirrors
> are on a moving platform and it is moving wrt the surface of the Earth?
>  If so, then is the statement above essentially saying, "In the
> reference frame of the surface of the Earth, the distance between the
> moving mirrors is L/g?"  If so, why is length contraction applied in
> the frame of the surface of the Earth and not in the frame of the
> mirrors?

As measured in the reference frame of the mirrors, the distance between
the mirrors is L, and as measured in a reference frame in which the
mirrors are moving at speed v, the distance between the mirrors is L/g.

>>, and the speed of a horizontal light pulse relative to
>>the mirrors is c-v in the direction the mirrors are moving, and c+v in
[quoted text clipped - 4 lines]
> travelling back and forth between the mirrors in the frame of the
> mirrors?

The light pulse which travels between the mirrors - in every frame of
reference.

  Are you saying that the speed of the light pulse in the frame
> of the surface of the Earth is anything other than c?  SR's second
> postulate states the speed of light is always c in any reference frame.
>  What gives?

The speed of light (locally, in vacuum) will be measured as c, and so
(in 1-D) if the speed of some other object is measured as v, the speed
of the light with respect to that object will be measured as either c-v
or c+v.

>> Therefore the time for a light pulse to
>>complete a round trip between the mirrors is L/(g(c-v)) + L/(g(c+v)) =
[quoted text clipped - 10 lines]
> that frame, otherwise the light pulse wouldn't hit the mirror in the
> same place?

Apparently you didn't understand the question that was asked.  In order
to graphically demonstrate the time dilation effect, most introductory
textbooks on Relativity use a light clock which is moving
perpendicularly to the path of the light pulse which bounces back and
forth between the clock's two mirrors.  The question that was asked and
answered concerns how to demonstrate the time dilation effect when the
clock is rotated 90 degrees so that both the light pulse and the mirrors
travel along the same line.

> Vern
vern@bealenet.com - 25 Jun 2006 12:49 GMT
> Apparently you didn't understand the question that was asked.  In order
> to graphically demonstrate the time dilation effect, most introductory
[quoted text clipped - 4 lines]
> clock is rotated 90 degrees so that both the light pulse and the mirrors
> travel along the same line.

Sorry, but you are incorrect.  The original poster stated that the
textbook he was using gave the example of the mirrors moving parallel
to the path of the light first and he understood that example.  He was
asking for help with the second example in which the mirrors were
moving perpendicular to the path of the light.  See posts #1 and #13.

Vern
Dirk Van de moortel - 25 Jun 2006 13:12 GMT
>> Apparently you didn't understand the question that was asked.  In order
>> to graphically demonstrate the time dilation effect, most introductory
[quoted text clipped - 10 lines]
> asking for help with the second example in which the mirrors were
> moving perpendicular to the path of the light.  See posts #1 and #13.

See Jem's answer.

Dirk Vdm
Sue... - 25 Jun 2006 13:53 GMT
> > Apparently you didn't understand the question that was asked.  In order
> > to graphically demonstrate the time dilation effect, most introductory
[quoted text clipped - 12 lines]
>
> Vern

If an example uses a train to explain how a boat floats or
it uses a frog to explain how a bird flys...
... you find a better example.

Sue...
Jem - 25 Jun 2006 14:06 GMT
>>Apparently you didn't understand the question that was asked.  In order
>>to graphically demonstrate the time dilation effect, most introductory
[quoted text clipped - 10 lines]
> asking for help with the second example in which the mirrors were
> moving perpendicular to the path of the light.  See posts #1 and #13.

The original question was somewhat ambiguous, but if it had been about
motion perpendicular to the light path, there certainly wouldn't have
been any problem finding the answer on the "net".  See post #1.
vern@bealenet.com - 26 Jun 2006 00:33 GMT
> >>Apparently you didn't understand the question that was asked.  In order
> >>to graphically demonstrate the time dilation effect, most introductory
[quoted text clipped - 14 lines]
> motion perpendicular to the light path, there certainly wouldn't have
> been any problem finding the answer on the "net".  See post #1.

After reading the original poster's two posts again, I think he said
parallel in the first post when he meant perpendicular, so I think you
were right that he was having trouble with the example where the
mirrors are positioned so that the light is being reflected parallel to
the motion (at the front and back of the rocket, as he says in his
second post).  I found the following website which addresses both, so
maybe the original poster will read this message.

http://www.sparknotes.com/physics/specialrelativity/kinematics/section2.rhtml

Vern
Sue... - 24 Jun 2006 11:23 GMT
> > In James Hartle's book Gravity (An introduction...) he runs through the
> > maths of deriving time dilation from a pair of mirrors aligned parallel
[quoted text clipped - 17 lines]
> 2gL/c (i.e. a factor of g longer than the time taken in the reference
> frame of the mirrors).

The nice thing about this... you are using something that is
physically ambiguous to illustrate somthing with only a
mathematical interpretation.   This is much better because
the reader can't conclude with the notion that raindrops
should take longer to reach the ground when their diagonal
path is viewed from a moving car.  Absurd of course. ;-)

The changing distance between the mirrors then maps directly
to the distance which accounts for the retarded time in Maxwell's
time dependent equations.

Sue...

Sue...
Zinc Potterman - 24 Jun 2006 11:07 GMT
Hartle problem
-------------mirror 2
  ^
  |
  | light path
  |
  |
-------------mirror 1                     the two mirrors are moving up as
seen.

Most books cover the derivation of time dilation. As shown below
-------------mirror 2
  ^
  |
  | light path
  |
  |
-------------mirror 1                     the two mirrors are moving right
as seen.

Please can someone help with the basic maths. Or even start me off.
I'm sorry but can't understand a word of some previous contributors.
Are they genuine?
Zinc

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To reply to address don't click.
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------------------------------------

> In James Hartle's book Gravity (An introduction...) he runs through the
> maths of deriving time dilation from a pair of mirrors aligned parallel
[quoted text clipped - 7 lines]
> this configuration please.
> Zinc
Dirk Van de moortel - 24 Jun 2006 15:04 GMT
> Hartle problem
> -------------mirror 2
[quoted text clipped - 4 lines]
>   |
> -------------mirror 1                     the two mirrors are moving up as seen.

I don't see it unless you draw an arrow up or down
showing the motion of the mirrors w.r.t. the fixed screen.

> Most books cover the derivation of time dilation. As shown below
> -------------mirror 2
[quoted text clipped - 4 lines]
>   |
> -------------mirror 1                     the two mirrors are moving right as seen.

I don't see it. Draw an arrow like
       ----------------> v

> Please can someone help with the basic maths. Or even start me off.
> I'm sorry but can't understand a word of some previous contributors.
> Are they genuine?

Jem's reply (and his reply to deliberately clueless 'Sue...') was excellent.
The other replies were junk. Just ignore everything but Jem's (and this).

Why don't you ask Jem?

Dirk Vdm
Harry - 26 Jun 2006 10:02 GMT
> Hartle problem
> -------------mirror 2
[quoted text clipped - 20 lines]
> Are they genuine?
> Zinc

Jem's answer was perfect I think. Here it is again:

"Suppose the distance between the mirrors (in the reference frame of the
mirrors) is L, the speed of the mirrors is v, and g = 1/sqrt(1-v^2/c^2).
 Then, due to length contraction, the distance between the moving
mirrors is L/g, and the speed of a horizontal light pulse relative to
the mirrors is c-v in the direction the mirrors are moving, and c+v in
the opposite direction.  Therefore the time for a light pulse to
complete a round trip between the mirrors is L/(g(c-v)) + L/(g(c+v)) =
2gL/c (i.e. a factor of g longer than the time taken in the reference
frame of the mirrors)."

Thus the time dilation factor g (for "gamma") is the same in all
directions - as it should be.
You can find the same math in some detailed discussions of the
Michelson-Morley experiment.

Harald
Sue... - 26 Jun 2006 11:24 GMT
> > Hartle problem
> > -------------mirror 2
[quoted text clipped - 39 lines]
>
> Harald

Yes... Jem's model also gives the same result whether you
use wave or particle model for light. That eliminates another
source of confusion with the diagonal path illustrations.

Sue...
 
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