>You have made an elementary error. You have performed a "frame
>jump". B measures A to be traveling away or towards at 0.866c. Guess
>what speed A measures B to be moving away or towards? 0.866c
>A simply does not measure the distance travelled to agree with B. But
>this is little different than the apparent height of a building if you
>are near or far from it. It is only "perspective".
Dear Richard Hachel:
> >You have made an elementary error. You have
> >performed a "frame jump". B measures A to be
[quoted text clipped - 10 lines]
> Regrettably, you do not understand what I want
> to say. I mean that a speed must be symmetric,
It is symmetric. Each measures the other to be travelling at the same
speed.
> and as much the visible speed is similar as
> the classic speed.
You perform a frame jump when you do this. This is your error, your
"contradictions and nonsenses".
> Now, in the langevin, it is not. Of
> course, Vo=Uo=0.8c but Vapp=0.444c and
> Uapp=0.8c. It's a great problem of symmetria.
It is a frame jump. If you make the measurements in a frame, and use
only measurements and "physics" from that frame, everything is in
agreement. Except for comparing elapsed time and trip length. But
both agree the trip was made, and A brought back pretty pictures to
prove it.
> Here, we have a contradiction, because the
> Lorentz contraction are badly understood.
Then it is your job to study and learn it.
> It' s not sqrt(1-v^2/c^2) but
> sqrt (1-v^2/c^2)/(1+cosµv/c) what we have
> --->perfect symmetria.
However perfect you imagine it to be, it is not in agreement with
experiment. Unless "mu" = (n * pi/2 * c/v), n= 1, 3, 5...
> However, I do not say that the SR is false.
You just say that it is "contradictions and nonsenses" and "un-
symmetric". And then provide a "correction" that has an infinite
number of wrong results.
> I say that it is very badly explained
> generaly, and especially, always very badly
> understood there; with, all in all, obvious
> contradictions and nonsenses.
Recall walking in the woods. Imagine someone complaining that the
roads in the woods are very rough, and the "walk / don't walk" signs
never seem to change. Common sense is comfortable in the terrain it
is trained in.
If you do not like the presentation in one text, try the one I
recommended:
"Spacetime Physics" by Taylor and Wheeler.
It is only *your* discomfort, not something wrong with the
application. Once you get past your discomfort, you might be able to
see that it is the postulates and the unstated assumptions that are a
theory's weak spots. Arguing about the "flavor" of a result is
"contradictions and nonsenses".
David A. Smith
Richard Hachel - 28 Feb 2007 09:42 GMT
> > to say. I mean that a speed must be symmetric,
>
> It is symmetric.
Not in the Langevin concept.
> Each measures the other to be travelling at the same
> speed.
No.
And this is a nonsense, a contradiction of Einstein symmetrical theory.
> > and as much the visible speed is similar as
> > the classic speed.
>
> You perform a frame jump when you do this. This is your error, your
> "contradictions and nonsenses".
No.
Nothing to see with "frame jump" here.
The frame jump explain other things, but not no-symmetrical
visible speed.
> > Now, in the langevin, it is not. Of
> > course, Vo=Uo=0.8c but Vapp=0.444c and
> > Uapp=0.8c. It's a great problem of symmetria.
>
> It is a frame jump.
Noooooo !
No have frame jump here !
Terrence sees Stella, and Stella sees Terrence. It's all.
In galilean frame. It's all.
And it's not symmetric ----> Then, there is a contradiction.
If v=0.8c
Terrence sees Vapp=0.444c
Stella sees Uapp=0.8c !!!
And when she returns:
Terrence sees Vapp=4c
Stella sees Uapp=0.8c !!!
To Stella, Uapp=v ----> Ridiculus !!!
Why ???
R.H.
dlzc - 28 Feb 2007 14:24 GMT
Dear Richard Hachel:
> dlzcwrote:
> > > to say. I mean that a speed must be
[quoted text clipped - 3 lines]
>
> Not in the Langevin concept.
Only how you choose to read it.
> > Each measures the other to be travelling
> > at the same speed.
>
> No.
t_A = time for round trip in A's frame.
l_A = distance travelled in A's frame.
t_B = time that A was gone in B's frame.
l_B = 2 x the rest frame distance to the star A visits.
l_A / t_A = l_B / t_B
Symmetric.
> And this is a nonsense, a contradiction of
> Einstein symmetrical theory.
You don't like symmetry now? Why not?
> > > and as much the visible speed is similar as
> > > the classic speed.
[quoted text clipped - 6 lines]
>
> Nothing to see with "frame jump" here.
Time in one frame, but distance from another... a frame jump.
> The frame jump explain other things, but
> not no-symmetrical visible speed.
It is symmetric. You want to imagine it is not.
> > > Now, in the langevin, it is not. Of
> > > course, Vo=Uo=0.8c but Vapp=0.444c and
[quoted text clipped - 5 lines]
>
> No have frame jump here !
Time and distance from one frame, not one from each of two frames.
> Terrence sees Stella, and Stella sees
> Terrence. It's all.
And they each agree on closing / departing speed.
> In galilean frame. It's all.
>
[quoted text clipped - 4 lines]
>
> Terrence sees Vapp=0.444c
Terrence sees 0.8c
> Stella sees Uapp=0.8c !!!
>
> And when she returns:
>
> Terrence sees Vapp=4c
Terrence sees 0.8c
> Stella sees Uapp=0.8c !!!
>
> To Stella, Uapp=v ----> Ridiculus !!!
>
> Why ???
Because you perform a frame jump. Terrence can measure the distance
too. Terrence measures everything in Terrence's frame. Terrence does
not have to rely on some Holy Book to use Stella's value of distance.
Why do you not like symmetry? Why do you insist on using another
frame's measurements? If I tell you that the distance to the store is
1.3 miles, you would be telling me that it is some other value.
Because the distance is a function of what path is taken.
A follows a different path from B, between A's departure and A'
arrival. Why is there a big surprise?
David A. Smith
Richard Hachel - 28 Feb 2007 14:56 GMT
> > If v=0.8c
> >
> > Terrence sees Vapp=0.444c
>
> Terrence sees 0.8c
No.
Vapp=v/(1+v/c)
Vapp=0.4444c
> > Stella sees Uapp=0.8c !!!
> >
[quoted text clipped - 3 lines]
>
> Terrence sees 0.8c
No.
Vapp=v/(1-v/c)= 4c
> > Stella sees Uapp=0.8c !!!
> >
[quoted text clipped - 4 lines]
> Because you perform a frame jump. Terrence can measure the distance
> too. Terrence measures everything in Terrence's frame.
Yes.
He measures d=12 (year light)
He measures 27 years (Doppler effect)
Vapp=12/27=0.4444c
Idem with I take Vapp=0.8/(1+0.8)= 0.4444c
When Stella return: he measures d=12 ; Tapp=3 years (Doppler effect)
Well, Vapp=12/3 = 4c.
Idem: Vapp=0.8/(1-0.8)= 4c.
But impossible that Stella sees the same effect with SR.
It's NOT symmetric.
CQFD.
> David A. Smith
R.H.
dlzc - 28 Feb 2007 17:33 GMT
Dear Richard Hachel:
> dlzcwrote:
>
[quoted text clipped - 9 lines]
>
> Vapp=0.4444c
Formula out of strange bodily orifice. Use version I supplied, where
only measurements are in the frame of the object.
> > > Stella sees Uapp=0.8c !!!
>
[quoted text clipped - 7 lines]
>
> Vapp=v/(1-v/c)= 4c
Formula out of strange bodily orifice. Use version I supplied, where
only measurements are in the frame of the object.
> > > Stella sees Uapp=0.8c !!!
>
[quoted text clipped - 15 lines]
>
> Idem with I take Vapp=0.8/(1+0.8)= 0.4444c
You know, your dislike of silliness apparently applies to sound.
Because your formula shows a similar problem for any motion near "the
speed of the medium".
> When Stella return: he measures d=12 ;
> Tapp=3 years (Doppler effect)
[quoted text clipped - 8 lines]
>
> CQFD.
Formula out of strange bodily orifice. Use version I supplied, where
only measurements are in the frame of the object.
One-way trip time for Terrence: (15 / gamma) years
One-way distance that Terrance measures for each leg once attaining
0.8c: (12 / gamma) light years
Round trip time Stella measures: 30 years
One-way distance that Stella measures: 24 ly
(12 / gamma) / (15 / gamma) = 30 / 24 = same average speed...
symmetric
You have your silliness because:
- you neglect the speed of light over a long distance, and
- you use a (rest frame) textbook value of distance... not what is
measured.
You make frame jumps.
David A. Smith