Home | Contact Us | FAQ | Search & Site Map | Link to Us
Sign In | Join | Other 45 Sites in Network
Home
Discussion Groups
Biology
BiologyBotanyMicrobiologyEntomologyEvolutionPaleontology
Chemistry
General ChemistryAnalytical ChemistryElectrochemistryOrganic Synthesis
Earth Science
GeologyMineralogyOceanographyMeteorologyEarthquakes
Physics
General PhysicsResearchRelativityParticle PhysicsElectromagnetismFusionOpticsAcousticsNew Theories

Natural Science Forum / Chemistry / Organic Synthesis / April 2005



Tip: Looking for answers? Try searching our database.

selective reduction of carboxylic acid

Thread view: 
Enable EMail Alerts  Start New Thread
Thread rating: 
josef muller - 16 Mar 2005 10:11 GMT
hi,

in literature i found quite interesting procedure for reducing
carboxylic acids without touching ester moiety. in typical procedure
the suspension of sodium borohydride in thf is treated with acid. then
the solution of iodine in thf is added dropwise. some authors observed
the traces of iodobutanol (thf cleavage product). unfortunately, i
always obtain ONLY iodobutanol without any traces of desired product.

my substrate to be reduced is 5-oxotetrahydrofuran-2-carboxylic acid.
probably lactone ring is too labile under such conditions.

does anybody have experience with this reduction protocol? any
suggestion what went wrong? can you recommend me another reagent for
such reaction (except of borane-dimethylsulfide comlex)

thanks in advance
matt - 11 Apr 2005 08:32 GMT
Is the iodine soln made from KI/NaI orI2?
matt - 11 Apr 2005 08:40 GMT
Is the iodine soln made from KI/NaI orI2?
BeeKay - 22 Apr 2005 08:10 GMT
Im sorry what Iodine solution are you speeking of?
KI + I2 => I3
I2 + CCl4 => I+
Gabriel Tojo - 29 Apr 2005 08:11 GMT
The compound you are lookin for,  that is, the product of the reduction
of 5-oxotetrahydrofuran-2-carboxylic acid on the carboxy group, is
commercially available from Aldrich and Across.

If you want to prepare it by reduction of the carboxylic acid,
certainly borane would work. If you do not like the complex BH3.SMe2,
you could  use the complex BH3.THF or you may prepare it in situ by
reaction of NaBH4 with an acid such as BF3.Et2O.

Alternatively, you may transform the acid into the acid chloride and
reduce it with NaBH4 to the alcohol.

Best regards.

Gabriel Tojo
 
Sign In
Join
My Latest Posts
My Monitored Threads
My Blog
My Photo Gallery
My Profile
My Homepage

Start New Thread
Enable EMail Alerts
Rate this Thread



©2009 Advenet LLC   Privacy Policy - Terms of Use
This website includes both content owned or controlled by Advenet as well as content owned or controlled by third parties.