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Natural Science Forum / Chemistry / Organic Synthesis / July 2006



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Reagent Prep

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gainullin@gmail.com - 18 Jul 2006 09:17 GMT
Hi,

Please help me to understand this.

Example. You wish to prepare a 2mM solution of NADP, and find that
anhydrous weight of NADP is 743. But you have purchased monosodium salt
containing four molecules of water, and the label states that the
preparation is 94% pure. The mol weight of monosodium NADP with four
molecules of water is then 743+23-1+(4x18) = 837.

Questions;
1) why do we add molecular weight of Sodium to 743?
 2) Why substract 1 (hydrogen?) ?

Thank you
Stephan Bird - 19 Jul 2006 09:11 GMT
Consider what NADP is, it's a phosphate ester, with an exchangable proton
on it, just like phosphoric acid.

Similarly, when calculating the Mr of monosodium phosphate, one way to go
about it is to start from phosphoric acid (H3PO4 == [3 x 1] + 31 + [4 x
16] == 98) take 1 away for the exhanged hydrogen, then add 23 back on for
the sodium salt NaH2PO4.
 
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