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Re: Light speed in emission theory



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Re: Light speed in emission theory

Ahmed Ouahi, Architect27 Apr 2007 23:49
Obviously!?

However, it does not matter, whether you would like to be a stupid, but what
you are asking, it would not let you, to be along any stupidy matter, as for
the simple reason, that it would as it should turns to a definite a
geometrically matter, as it would a puzzle you as a hell...

For the time being, as anything would be along a limited space, would never
repeat itself as it would never cross itself neither, for instance, do put
the v along  zero, a distance along a left of the center, a both point would
specify a single point, then the v would reach its maximum along any
perpendicularity, as it would cross the zero, as the v, would pass again to
the zero, as it would appear a negative motion.

Therefore, a simply, once a system returns to a state it has had been in it
before, should follow the same path, whether to produce every behaviors, as
the base would have to be along an infinitely long line along a finite area
all along, and this what it would be, what is all about, a definitely as a
matter a fact.

--
Ahmed Ouahi, Architect
Best Regards!

> I am a stupid guy, who does not know the answer to this problem: A body
> (observer) moves in a stationary frame with speed v<c. It sends a light
> signal travelling with speed c+v (parallel with v). What will be the speed
> of the signal after reflection on a stationary mirror (which is
> perpendicular to v).
> Thanks to anybody who would answer.

kanuk27 Apr 2007 21:29
I am a stupid guy, who does not know the answer to this problem: A body
(observer) moves in a stationary frame with speed v<c. It sends a light
signal travelling with speed c+v (parallel with v). What will be the speed
of the signal after reflection on a stationary mirror (which is
perpendicular to v).
Thanks to anybody who would answer.

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